Question Number 38478 by Rio Mike last updated on 26/Jun/18 Commented by Rio Mike last updated on 26/Jun/18 $$\mathrm{The}\:\mathrm{colouring}\:\mathrm{in}\:\mathrm{five}\:\mathrm{soft}\:\mathrm{drinks} \\ $$$$\mathrm{produced}\:\mathrm{by}\:\mathrm{a}\:\mathrm{drink}\:\mathrm{industry}\:\mathrm{were} \\ $$$$\mathrm{analysed}\:\mathrm{on}\:\mathrm{a}\:\mathrm{Paper}\:\mathrm{Chromatography}. \\ $$$$\mathrm{the}\:\mathrm{final}\:\mathrm{chromatogram}\:\mathrm{is}\:\mathrm{show}\:\mathrm{above}.…
Question Number 35197 by Tinkutara last updated on 16/May/18 Answered by ajfour last updated on 17/May/18 $$ \\ $$$$\Rightarrow\:{P}\:=\:\frac{\mathrm{3}×\mathrm{320}}{\mathrm{290}}\:{atm}\:=\frac{\mathrm{96}}{\mathrm{29}}{atm} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{96}}{\mathrm{30}−\mathrm{1}}=\frac{\mathrm{96}}{\mathrm{30}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{30}}\right)\: \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{3}.\mathrm{2}+\frac{\mathrm{3}.\mathrm{2}}{\mathrm{30}}\:=\:\mathrm{3}.\mathrm{31}{atm} \\ $$$$\frac{{n}−\bigtriangleup{n}}{\mathrm{3}}=\frac{{n}}{\mathrm{3}.\mathrm{31}}…
Question Number 92621 by student work last updated on 08/May/20 Commented by Tony Lin last updated on 08/May/20 $$\mathrm{6}.\mathrm{022}×\mathrm{10}^{\mathrm{23}} ×\mathrm{4}×\mathrm{2} \\ $$$$\Rightarrow{C} \\ $$ Terms…
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