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Category: Thermodynamics

Question-52992

Question Number 52992 by prakash jain last updated on 16/Jan/19 Commented by prakash jain last updated on 16/Jan/19 $$\mathrm{Correct}\:\mathrm{answer}\:\mathrm{is}\:\frac{\mathrm{4}−\mathrm{R}}{\mathrm{2R}},\:\mathrm{NTA}\:\mathrm{has}\:\mathrm{given} \\ $$$$\frac{\mathrm{4}+\mathrm{R}}{\mathrm{2R}}.\:\mathrm{This}\:\mathrm{question}\:\mathrm{is}\:\mathrm{also}\:\mathrm{from} \\ $$$$\mathrm{9th}\:\mathrm{Jan}\:\mathrm{morning}\:\mathrm{JE}{E}\:\mathrm{main}\:\mathrm{exam}. \\ $$…

Question-182874

Question Number 182874 by peter frank last updated on 15/Dec/22 Answered by TheSupreme last updated on 16/Dec/22 $${V}={vcos}\left(\theta\right)\overset{\rightarrow} {{x}}+\left({vsin}\left(\theta\right)−{gt}\right)\overset{\rightarrow} {{y}} \\ $$$${S}={vcos}\left(\theta\right){t}\overset{\rightarrow} {{x}}+\left({vsin}\left(\theta\right){t}−\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} \right) \\…