Question Number 199888 by hardmath last updated on 10/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 199889 by hardmath last updated on 10/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 199890 by hardmath last updated on 10/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 199774 by Mingma last updated on 09/Nov/23 Answered by ajfour last updated on 09/Nov/23 Commented by ajfour last updated on 09/Nov/23 $${P}\:\left({perimeter}\:{of}\:\bigtriangleup\:{ABC}\right) \\…
Question Number 199772 by Rupesh123 last updated on 09/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 199775 by Mingma last updated on 09/Nov/23 Answered by mathfreak01 last updated on 09/Nov/23 $$ \\ $$$$ \\ $$Assuming when have a triangle…
Question Number 199770 by Rupesh123 last updated on 09/Nov/23 Answered by aleks041103 last updated on 09/Nov/23 $${C}=\pi−\mathrm{3}\alpha \\ $$$$\Rightarrow\frac{\mathrm{5}}{{sin}\left(\mathrm{2}\alpha\right)}=\frac{\mathrm{6}}{{sin}\left(\pi−\mathrm{3}\alpha\right)}=\frac{\mathrm{6}}{{sin}\left(\mathrm{3}\alpha\right)} \\ $$$$\Rightarrow\mathrm{6}{sin}\left(\mathrm{2}\alpha\right)=\mathrm{5}{sin}\left(\mathrm{3}\alpha\right) \\ $$$${sin}\left(\mathrm{2}\alpha\right)=\mathrm{2}{sin}\left(\alpha\right){cos}\left(\alpha\right) \\ $$$${sin}\left(\mathrm{3}\alpha\right)={sin}\left(\mathrm{2}\alpha\right){cos}\left(\alpha\right)+{sin}\left(\alpha\right){cos}\left(\mathrm{2}\alpha\right)=…
Question Number 199709 by tri26112004 last updated on 08/Nov/23 $${u}_{\mathrm{1}} \:=\:\mathrm{2}\: \\ $$$${u}_{{n}+\mathrm{1}} \:=\:\mathrm{3}{u}_{{n}} \:+\:\mathrm{2} \\ $$$${u}_{{n}} \:\rightarrow\:{n}\:¿ \\ $$ Answered by mr W last…
Question Number 199711 by Mingma last updated on 08/Nov/23 Answered by mr W last updated on 08/Nov/23 Commented by mr W last updated on 08/Nov/23…
Question Number 199732 by Rupesh123 last updated on 08/Nov/23 Answered by Rasheed.Sindhi last updated on 08/Nov/23 $${y}=\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}+\mathrm{3}}=\frac{{x}^{\mathrm{2}} −\mathrm{9}+\mathrm{9}+\mathrm{2}}{{x}+\mathrm{3}} \\ $$$$\:\:\:=\frac{\left({x}−\mathrm{3}\right)\left({x}+\mathrm{3}\right)+\mathrm{11}}{{x}+\mathrm{3}} \\ $$$$=\left({x}−\mathrm{3}\right)+\frac{\mathrm{11}}{{x}+\mathrm{3}}\in\mathbb{Z}\Rightarrow\left({x}+\mathrm{3}\right)\mid\mathrm{11} \\ $$$${x}+\mathrm{3}=\pm\mathrm{1},\pm\mathrm{11}…