Question Number 194422 by York12 last updated on 06/Jul/23 $${What}\:{books}\:{use}\:{for}\:{studying}\:{inequalities} \\ $$$${for}\:{beginners}\: \\ $$ Answered by ajfour last updated on 06/Jul/23 $${Elementary}\:{Mathematics} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:-\:{G}.\:{Dorofeev} \\…
Question Number 194389 by mathlove last updated on 05/Jul/23 $$\sqrt{\sqrt{\mathrm{49}+\mathrm{20}\sqrt{\mathrm{6}}}}=? \\ $$ Answered by som(math1967) last updated on 05/Jul/23 $$\sqrt{\sqrt{\mathrm{5}^{\mathrm{2}} +\left(\mathrm{2}\sqrt{\mathrm{6}}\right)^{\mathrm{2}} +\mathrm{2}.\mathrm{5}.\mathrm{2}\sqrt{\mathrm{6}}}} \\ $$$$\sqrt{\sqrt{\left(\mathrm{5}+\mathrm{2}\sqrt{\mathrm{6}}\right)^{\mathrm{2}} }}…
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Question Number 194373 by MM42 last updated on 05/Jul/23 $${Show}\:\:\: \\ $$$$\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\frac{\mathrm{1}}{\mathrm{2}{i}−\mathrm{1}}−\:\frac{\mathrm{1}}{\mathrm{2}{i}}\right)=\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\mathrm{1}}{{n}+{i}}\: \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 194326 by horsebrand11 last updated on 03/Jul/23 $$\:\:\sqrt{\frac{\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{66}^{\mathrm{2}} +\mathrm{x}}}{\mathrm{x}}\:}\:−\sqrt{\mathrm{x}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{66}^{\mathrm{2}} }−\mathrm{x}^{\mathrm{2}} }\:=\:\mathrm{5}\: \\ $$ Answered by cortano12 last updated on 03/Jul/23 $$\:\:\:\cancel{\lesseqgtr}…
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Question Number 194321 by CrispyXYZ last updated on 04/Jul/23 $$\mathrm{find}\:\mathrm{min}\:\:−\frac{\left({x}−{y}\right)\left(\frac{{xy}}{\mathrm{4}}−\mathrm{4}\right)^{\mathrm{2}} }{{xy}} \\ $$$$\mathrm{s}.\:\mathrm{t}.\:\:{x}>\mathrm{0}>{y} \\ $$ Answered by Frix last updated on 04/Jul/23 $${f}\left({x},{y}\right)=−\frac{\left({x}−{y}\right)\left(\frac{{xy}}{\mathrm{4}}−\mathrm{4}\right)^{\mathrm{2}} }{{xy}}=−\frac{\left({x}−{y}\right)\left({xy}−\mathrm{16}\right)^{\mathrm{2}} }{\mathrm{16}{xy}}…
Question Number 194316 by SajaRashki last updated on 03/Jul/23 $${if}\:\:{x}\in{R}\:\:\&\:\:{x}^{{x}^{\mathrm{6}} } =\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{2}}} \:\Rightarrow\:\:{x}=? \\ $$ Commented by Frix last updated on 03/Jul/23 $${x}=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{4}}} \\ $$$$\Rightarrow\:{x}^{\mathrm{6}}…
Question Number 194295 by Abdullahrussell last updated on 02/Jul/23 Answered by BaliramKumar last updated on 02/Jul/23 $$\mathrm{1}!×\mathrm{2}!×\mathrm{3}!×………………×\mathrm{2023}! \\ $$$$\mathrm{1}^{\mathrm{2023}} ×\mathrm{2}^{\mathrm{2022}} ×\mathrm{3}^{\mathrm{2021}} ×………………×\mathrm{2023}^{\mathrm{1}} \\ $$$$\mathrm{1}^{\mathrm{2023}} ×…×\mathrm{5}^{\mathrm{2019}}…
Question Number 194169 by Rupesh123 last updated on 29/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com