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Category: Algebra

Let-a-b-c-be-positive-real-numbers-prove-that-a-b-b-c-c-a-3-3-abc-a-b-c-4-

Question Number 194163 by York12 last updated on 29/Jun/23 $$\boldsymbol{{Let}}\:\boldsymbol{{a}}\:,\:\boldsymbol{{b}}\:,\:\boldsymbol{{c}}\:\:\:\boldsymbol{{be}}\:\boldsymbol{{positive}}\:\boldsymbol{{real}}\:\boldsymbol{{numbers}} \\ $$$$\boldsymbol{{prove}}\:\boldsymbol{{that}} \\ $$$$\frac{\boldsymbol{{a}}}{\boldsymbol{{b}}}+\frac{\boldsymbol{{b}}}{\boldsymbol{{c}}}+\frac{\boldsymbol{{c}}}{\boldsymbol{{a}}}+\frac{\mathrm{3}^{\mathrm{3}} \sqrt{{abc}}}{\boldsymbol{{a}}+\boldsymbol{{b}}+\boldsymbol{{c}}}\geqslant\mathrm{4} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

prove-it-n-k-2-n-k-1-n-k-1-1-k-n-1-

Question Number 194140 by MM42 last updated on 28/Jun/23 $${prove}\:{it}\:: \\ $$$$\begin{pmatrix}{{n}}\\{{k}}\end{pmatrix}^{\:\mathrm{2}} \geqslant\:\begin{pmatrix}{\:\:\:\:{n}}\\{{k}−\mathrm{1}}\end{pmatrix}\:×\begin{pmatrix}{\:\:{n}}\\{{k}+\mathrm{1}}\end{pmatrix}\:\:\:\:\:;\:\:\:\mathrm{1}\leqslant{k}\leqslant{n}−\mathrm{1} \\ $$$$ \\ $$ Answered by witcher3 last updated on 28/Jun/23 $$\left(\frac{\mathrm{n}!}{\mathrm{k}!.\left(\mathrm{n}−\mathrm{k}\right)!}\right)^{\mathrm{2}}…

determinant-23-23-1-1-2-2-3-3-21-21-

Question Number 194135 by cortano12 last updated on 28/Jun/23 $$\:\:\:\:\:\:\begin{array}{|c|}{\frac{\mathrm{23}!−\mathrm{23}}{\mathrm{1}.\mathrm{1}!+\mathrm{2}.\mathrm{2}!+\mathrm{3}.\mathrm{3}!+…+\mathrm{21}.\mathrm{21}!}\:=?}\\\hline\end{array} \\ $$ Answered by Frix last updated on 28/Jun/23 $$\mathrm{23} \\ $$$$\left[\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}{j}×{j}!=\left({n}+\mathrm{1}\right)!−\mathrm{1}\right] \\…

Question-194113

Question Number 194113 by Rupesh123 last updated on 28/Jun/23 Answered by Subhi last updated on 28/Jun/23 $$ \\ $$$$\frac{{a}\left({a}−\mathrm{1}\right)\left({a}−\mathrm{2}\right)…..}{{a}\left({a}−\mathrm{2}\right)\left({a}−\mathrm{4}\right)…..}.\frac{{b}\left({b}−\mathrm{2}\right)\left({b}−\mathrm{4}\right)…}{{b}\left({b}−\mathrm{1}\right)\left({b}−\mathrm{2}\right)….} \\ $$$$\:=\:\frac{\left({a}−\mathrm{1}\right)\left({a}−\mathrm{3}\right)\left({a}−\mathrm{5}\right)…..}{\left({b}−\mathrm{1}\right)\left({b}−\mathrm{3}\right)\left({b}−\mathrm{5}\right)…..}\:\:\:\: \\ $$$$\mathrm{24}\:{can}\:{be}\:{the}\:{multiplication}\:{of}\:{n},\:{n}+\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{4}\right),\left(\mathrm{6}\right)…

Question-194216

Question Number 194216 by Rupesh123 last updated on 30/Jun/23 Answered by qaz last updated on 01/Jul/23 $$\begin{pmatrix}{\mathrm{2084}}\\{\mathrm{1042}}\end{pmatrix}=\begin{pmatrix}{\mathrm{4}×\mathrm{521}}\\{\mathrm{2}×\mathrm{521}}\end{pmatrix}\equiv\begin{pmatrix}{\mathrm{4}}\\{\mathrm{2}}\end{pmatrix}\equiv\mathrm{6}\left({mod}\:\mathrm{521}\right) \\ $$ Terms of Service Privacy Policy Contact:…