Question Number 194219 by Shlock last updated on 30/Jun/23 Answered by Frix last updated on 30/Jun/23 $$\left({x}^{\mathrm{3}} +\mathrm{4}{x}−\mathrm{8}\right)\left({x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{8}\right)\left({x}+\mathrm{2}\right)= \\ $$$$={x}^{\mathrm{7}} +\mathrm{64}{x}^{\mathrm{2}} −\mathrm{128} \\…
Question Number 194218 by Mingma last updated on 30/Jun/23 Commented by Frix last updated on 30/Jun/23 $${t}=−\frac{\mathrm{3}}{\mathrm{2}} \\ $$ Commented by Mingma last updated on…
Question Number 194209 by mnjuly1970 last updated on 01/Jul/23 $$ \\ $$$$\:\:\:\:\:\:\sqrt[{\mathrm{3}}]{\mathrm{1}+{kx}}\:+{x}\:=\:\mathrm{1}\:\:\:{has} \\ $$$$\:\:\:\:\:\:{two}\:{real}\:{roots}\:.\:\:\Rightarrow\:{k}=? \\ $$$$\:\:\:{kx}+\mathrm{1}=\:\mathrm{1}−\mathrm{3}{x}+\mathrm{3}{x}^{\mathrm{2}} −{x}^{\:\mathrm{3}} \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:{x}^{\:\mathrm{3}} \:−\mathrm{3}{x}^{\:\mathrm{2}} +\:\left({k}+\mathrm{3}\right){x}=\mathrm{0} \\ $$$$\:\:\:\:\:{x}=\mathrm{0}…
Question Number 194204 by Rupesh123 last updated on 30/Jun/23 Answered by MM42 last updated on 30/Jun/23 $${if}\:\:{n}={m}=\mathrm{0}\Rightarrow\mathrm{2}{a}_{\mathrm{0}} −\mathrm{1}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{2}{a}_{\mathrm{0}} \right)\Rightarrow{a}_{\mathrm{0}} =\mathrm{1} \\ $$$${if}\:\:{m}=\mathrm{1}\:,\:{n}=\mathrm{0}\Rightarrow\mathrm{2}{a}_{\mathrm{1}} −\mathrm{2}=\frac{\mathrm{1}}{\mathrm{2}}\left({a}_{\mathrm{2}} +{a}_{\mathrm{0}} \right)…
Question Number 194207 by Aymoyali last updated on 30/Jun/23 $$\:\:\:\:\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{x}−\mathrm{4}} \:\:=\sqrt{\mathrm{3}\:} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194206 by Aymoyali last updated on 30/Jun/23 Answered by Skabetix last updated on 30/Jun/23 $$\left(\mathrm{3}.\mathrm{1}\right){e}^{\mathrm{2}} >\left(\mathrm{2}.\mathrm{3}\right)\prod^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy…
Question Number 194197 by Mingma last updated on 30/Jun/23 Answered by mr W last updated on 01/Jul/23 Commented by mr W last updated on 01/Jul/23…
Question Number 194191 by JohnIsaac last updated on 29/Jun/23 Answered by Tinku Tara last updated on 30/Jun/23 $$\mathrm{4}{x}−\mathrm{3}{y}=\mathrm{9} \\ $$$$\mathrm{divide}\:\mathrm{both}\:\mathrm{sides}\:\mathrm{by}\:\mathrm{9}. \\ $$$$\frac{{x}}{\left(\mathrm{9}/\mathrm{4}\right)}+\frac{{y}}{\left(−\mathrm{3}\right)}=\mathrm{1} \\ $$$$\mathrm{x}−\mathrm{intercept}=\mathrm{9}/\mathrm{4} \\…
Question Number 194105 by York12 last updated on 27/Jun/23 $$ \\ $$$${x}\:,\:{y}\:,\:{z}\:{are}\:{positive}\:{real}\:{numbers}\:{if}\:{x}^{\mathrm{4}} +{y}^{\mathrm{4}} +{z}^{\mathrm{4}} =\mathrm{1} \\ $$$${Then}\:{find}\:{the}\:{minimum}\:{value}\:{of}\: \\ $$$$\frac{{x}^{\mathrm{3}} }{\mathrm{1}−{x}^{\mathrm{8}} }+\frac{{y}^{\mathrm{3}} }{\mathrm{1}−{y}^{\mathrm{8}} }+\frac{{z}^{\mathrm{3}} }{\mathrm{1}−{z}^{\mathrm{8}} }…
Question Number 194065 by Abdullahrussell last updated on 27/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com