Question Number 210608 by peter frank last updated on 13/Aug/24 Commented by peter frank last updated on 13/Aug/24 $$\mathrm{help}\:\left(\mathrm{b}\right) \\ $$ Answered by mr W…
Question Number 210581 by alusto22 last updated on 13/Aug/24 $$\:\:\begin{cases}{{x}^{\mathrm{2}} +\mathrm{3}{x}−\sqrt{{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{1}\:=\:\mathrm{7}}}\\{\mathrm{2}\sqrt{\mathrm{2}}\:\mathrm{sin}\:{y}\:=\:{x}}\end{cases} \\ $$$$\:\:\:{x}=?\:\:\:\:{and}\:\:\:\:{y}=? \\ $$ Answered by Rasheed.Sindhi last updated on 14/Aug/24 $${x}^{\mathrm{2}} +\mathrm{3}{x}−\sqrt{{x}^{\mathrm{2}}…
Question Number 210579 by Nimnim111118 last updated on 13/Aug/24 $${Please}…\:{Can}\:{anyone}\:{help}\:{me}.. \\ $$$$ \\ $$$$\:{Find}\:{the}\:{value}\left({s}\right)\:{of}\:{x},\:{if} \\ $$$$\:\:\:\left({x}−\mathrm{2}\right)^{\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{4}\right)} =\mathrm{3} \\ $$$$ \\ $$ Commented by mr…
Question Number 210574 by ChantalYah last updated on 13/Aug/24 $${if}\:{the}\:{roots}\:{of}\:{the}\:{equation}\: \\ $$$${x}^{\mathrm{2}} +\left({k}+\mathrm{1}\right){x}+{k}=\mathrm{0} \\ $$$${are}\:\alpha\:{and}\:\beta, \\ $$$$\:{find}\:{the}\:{value}\:{of}\:{the} \\ $$$$\:{real}\:{constant}\:{k}\:{for} \\ $$$${which}\:\alpha=\mathrm{2}\beta \\ $$ Answered by…
Question Number 210606 by peter frank last updated on 13/Aug/24 Answered by A5T last updated on 14/Aug/24 $$\mathrm{3}\left({y}^{{log}_{\mathrm{5}} \mathrm{2}} \right)+\left({y}^{{log}_{{y}} \mathrm{2}×{log}_{\mathrm{5}} {y}} \right)=\mathrm{3}\left({y}^{{log}_{\mathrm{5}} \mathrm{2}} \right)+{y}^{{log}_{\mathrm{5}}…
Question Number 210559 by mathlove last updated on 12/Aug/24 $${deg}\:\left[{p}\left({x}^{\mathrm{2}} \right)\centerdot{q}\left({x}\right)\right]=\mathrm{20} \\ $$$${deg}\left[\frac{{p}\left({x}\right)^{\mathrm{3}} }{{q}\left({x}\right)^{\mathrm{2}} }\right]=\mathrm{2} \\ $$$${then}\:{deg}\:\:{q}\left({x}\right)=? \\ $$ Answered by mr W last updated…
Question Number 210573 by Spillover last updated on 12/Aug/24 Answered by mathmax last updated on 13/Aug/24 $$\mathrm{2}{I}=\int_{−\infty} ^{+\infty} \frac{{dx}}{{x}^{\mathrm{4}} +{ix}^{\mathrm{2}} +\mathrm{2}}\:\left({fonction}\:{paire}\right) \\ $$$${roots}\:\:\:\:\:\:{x}^{\mathrm{2}} ={t}\rightarrow{t}^{\mathrm{2}} +{it}+\mathrm{2}…
Question Number 210572 by Spillover last updated on 12/Aug/24 Answered by mathmax last updated on 13/Aug/24 $${I}=\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}^{\mathrm{2}} {x}}{\mathrm{1}+{x}^{\mathrm{4}} }{dx}\:\:{changement}\:{x}={t}^{\frac{\mathrm{1}}{\mathrm{4}}} {give} \\ $$$${I}=\frac{\mathrm{1}}{\mathrm{16}}\int_{\mathrm{0}} ^{\infty}…
Question Number 210565 by maths_plus last updated on 12/Aug/24 Answered by mr W last updated on 13/Aug/24 Commented by mr W last updated on 13/Aug/24…
Question Number 210571 by hardmath last updated on 12/Aug/24 $$\mathrm{If}\:\:\mathrm{x},\mathrm{y},\mathrm{z}\in\mathrm{R}^{+} \:\:\mathrm{and}\:\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} =\mathrm{3} \\ $$$$\mathrm{Prove}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}}{\mathrm{4}−\mathrm{x}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{4}−\mathrm{y}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{4}−\mathrm{z}}\:\:\leqslant\:\:\mathrm{1} \\ $$ Answered by A5T last updated…