Question Number 193651 by a.lgnaoui last updated on 17/Jun/23 $$\mathrm{determiner}\:\mathrm{rayon}\:\boldsymbol{\mathrm{R}} \\ $$ Commented by a.lgnaoui last updated on 17/Jun/23 Terms of Service Privacy Policy Contact:…
Question Number 193647 by Rupesh123 last updated on 17/Jun/23 Answered by MM42 last updated on 17/Jun/23 $${both}\:{numbers}\:{a}\:,\:{b}\:{can}\:{not}\:{be}\:{odd}. \\ $$$${so}\:{a}=\mathrm{2}\:{or}\:{b}=\mathrm{2} \\ $$$${if}\:\:{a}=\mathrm{2}\:\&\:{b}=\mathrm{3}\:\Rightarrow{p}=\mathrm{2}^{\mathrm{3}} +\mathrm{7}×\mathrm{3}^{\mathrm{2}} =\mathrm{71}\:\checkmark \\ $$$${if}\:\:{a}=\mathrm{3}\:\&\:{b}=\mathrm{2}\Rightarrow\:{p}=\mathrm{3}^{\mathrm{2}}…
Question Number 193565 by Mingma last updated on 16/Jun/23 Answered by mr W last updated on 17/Jun/23 $${say}\:{at}\:{time}\:{x}\:{hours}\:{after}\:\mathrm{0}\:{o}'{clock}. \\ $$$${assume}\:{the}\:{hands}\:{move}\:{continuously}. \\ $$$${position}\:{of}\:{hour}\:{hand}:\:\mathrm{30}{x}\:° \\ $$$${position}\:{of}\:{minute}\:{hand}:\:\left({x}−\left[{x}\right]\right)×\mathrm{60}×\mathrm{6}\:° \\…
Question Number 193525 by mustafazaheen last updated on 16/Jun/23 $$\:\:\:\:\:\frac{\mathrm{27t73}}{\mathrm{11}} \\ $$$$\:\:\:\:\:\mathrm{and}\:\mathrm{R}=\mathrm{0}\:\:\:\mathrm{then}\:\mathrm{t}=? \\ $$$$\:\:\:\:\:\:\mathrm{how}\:\mathrm{is}\:\mathrm{explontry}\:\mathrm{solution} \\ $$ Answered by MM42 last updated on 16/Jun/23 $$\mathrm{3}−\mathrm{7}+{t}−\mathrm{7}+\mathrm{2}=\mathrm{11}{k}\Rightarrow−\mathrm{9}+{t}=\mathrm{11}{k}\Rightarrow{t}=\mathrm{9} \\…
Question Number 193546 by York12 last updated on 16/Jun/23 $${if}\:{a}+{b}+{c}=\mathrm{1} \\ $$$${find}\:{maximum}\:{ab}\:+{bc}\:+{ca}\: \\ $$$${a}\:,\:{b}\:,\:{c}\:{are}\:{non}\:{negative}\:{integers} \\ $$$$ \\ $$ Answered by Frix last updated on 16/Jun/23…
Question Number 193543 by York12 last updated on 16/Jun/23 $${solve} \\ $$ Commented by Subhi last updated on 16/Jun/23 $${cd}!!! \\ $$ Commented by York12…
Question Number 193542 by SAMIRA last updated on 16/Jun/23 $$\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{x}^{\mathrm{3}} +\mathrm{3x}^{\mathrm{2}} −\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{calcul}\:\:\:\:\mathrm{h}\left(\mathrm{X}\right)\:=\:\mathrm{f}\left(\mathrm{a}+\mathrm{X}\right)\:−\mathrm{b} \\ $$2) determine a and b such that h is odd…
Question Number 193492 by Socracious last updated on 15/Jun/23 Answered by a.lgnaoui last updated on 15/Jun/23 $$\mathrm{DE}\mid\mid\mathrm{BC}\:\: \\ $$$$\mathrm{tan}\:\mathrm{30}=\frac{\sqrt{\mathrm{3}}}{\mathrm{3}}=\frac{\boldsymbol{\mathrm{HB}}}{\boldsymbol{\mathrm{HA}}}=\frac{\boldsymbol{\mathrm{b}}}{\mathrm{2}\boldsymbol{\mathrm{x}}}\Rightarrow\:\:\boldsymbol{\mathrm{x}}=\frac{\boldsymbol{\mathrm{b}}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{S}}=\boldsymbol{\mathrm{x}}.\frac{\boldsymbol{\mathrm{b}}}{\mathrm{2}}=\frac{\boldsymbol{\mathrm{b}}^{\mathrm{2}} }{\mathrm{4}}\sqrt{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{Area}}=\frac{\mathrm{b}^{\mathrm{2}} \sqrt{\mathrm{3}}}{\mathrm{4}} \\ $$$$…
Question Number 193469 by Mingma last updated on 14/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193467 by aba last updated on 14/Jun/23 $$\mathrm{Proof}\:: \\ $$$$\mathrm{cot}^{−\mathrm{1}} \left(\frac{\sqrt{\mathrm{1}+\mathrm{sint}}+\sqrt{\mathrm{1}−\mathrm{sint}}}{\:\sqrt{\mathrm{1}+\mathrm{sint}}−\sqrt{\mathrm{1}−\mathrm{sint}}}\right)=\frac{\mathrm{t}}{\mathrm{2}}\: \\ $$ Commented by MM42 last updated on 14/Jun/23 $${attention} \\ $$$${in}\:{all}\:\:{three}\:{arguments}\:\:{we}\:{used}\:{equalities}…