Question Number 130802 by shaker last updated on 29/Jan/21 Answered by TheSupreme last updated on 29/Jan/21 $${Assuming}\:{ch}={cosh} \\ $$$$\mathrm{3}{cosh}\left(\mathrm{2}{x}\right)−{sinh}\left(\mathrm{2}{x}\right)−\mathrm{3}=\mathrm{0} \\ $$$$\mathrm{3}\left(\frac{{e}^{\mathrm{2}{x}} +{e}^{−\mathrm{2}{x}} }{\mathrm{2}}\right)−\frac{{e}^{\mathrm{2}{x}} −{e}^{−\mathrm{2}{x}} }{\mathrm{2}}=\mathrm{3}…
Question Number 65227 by Tawa1 last updated on 26/Jul/19 Commented by Tony Lin last updated on 26/Jul/19 $${let}\:\alpha,\beta\:{two}\:{roots}\:{of}\:{x}^{\mathrm{2}} +{ax}+\mathrm{1}=\mathrm{0} \\ $$$$\alpha\beta=\mathrm{1}\:{and}\:\alpha,\beta\:{are}\:{integers} \\ $$$$\left({irrational}\:{roots}\:{come}\:{in}\:{pair}\:{if}\:{the}\right. \\ $$$${coefficient}\:{of}\:{polynomial}\:{equation}…
Question Number 65198 by kaivan.ahmadi last updated on 26/Jul/19 $${let}\:{a}\in\mathbb{R}^{+} \:,\:{and}\:{x}>\mathrm{0} \\ $$$${x}^{\mathrm{4}} +\left(\mathrm{1}−\mathrm{2}{a}\right){x}^{\mathrm{2}} −\mathrm{2}{ax}+\mathrm{1}=\mathrm{0} \\ $$$${find}\:{x} \\ $$ Commented by MJS last updated on…
Question Number 130733 by bemath last updated on 28/Jan/21 Commented by EDWIN88 last updated on 28/Jan/21 $$\mathrm{10}^{{e}−\mathrm{1}} \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 130719 by SLVR last updated on 28/Jan/21 $$ \\ $$ Commented by SLVR last updated on 28/Jan/21 Commented by SLVR last updated on…
Question Number 130673 by yoba last updated on 27/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 65115 by hovea cw last updated on 25/Jul/19 $$\mathrm{x}^{\mathrm{x}} =\mathrm{64} \\ $$$$\mathrm{find}\:\mathrm{x} \\ $$ Answered by mr W last updated on 25/Jul/19 $${x}^{{x}}…
Question Number 65114 by hovea cw last updated on 25/Jul/19 $$\mathrm{x}^{\mathrm{x}^{\mathrm{lnx}} } =\mathrm{64} \\ $$$$\mathrm{find}\:\mathrm{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 65087 by Tawa1 last updated on 25/Jul/19 Answered by MJS last updated on 25/Jul/19 $$\mathrm{easier}\:\mathrm{than}\:\mathrm{it}\:\mathrm{seems} \\ $$$$\left(\mathrm{1}\right)\:\:{x}+{y}+{z}=\mathrm{0}\:\Rightarrow\:{z}=−{x}−{y} \\ $$$$\mathrm{insert}\:\mathrm{this}\:\mathrm{in}\:\left(\mathrm{2}\right)\:\mathrm{and}\:\left(\mathrm{3}\right) \\ $$$$\left(\mathrm{2}\right)\:−\mathrm{3}{xy}\left({x}+{y}\right)=\mathrm{18} \\ $$$$\left(\mathrm{3}\right)\:\:−\mathrm{7}{xy}\left({x}+{y}\right)\left({x}^{\mathrm{2}}…
Question Number 130605 by Study last updated on 27/Jan/21 $$\mathrm{0}^{\mathrm{0}} =?? \\ $$ Answered by mathmax by abdo last updated on 27/Jan/21 $$\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}^{+} } \:\mathrm{x}^{\mathrm{x}}…