Question Number 129607 by HHHHH last updated on 16/Jan/21 $${salom} \\ $$ Answered by prakash jain last updated on 16/Jan/21 $$\mathrm{welcome} \\ $$ Answered by…
Question Number 64066 by mathmax by abdo last updated on 12/Jul/19 $${let}\:\alpha\:,\beta\:{and}\:\lambda\:{the}\:{roots}\:{of}\:{x}^{\mathrm{3}} +\mathrm{2}{x}−\mathrm{1}\:=\mathrm{0}\:{find}\:{the}\:{value}\:{of} \\ $$$${A}\:=\alpha^{\mathrm{2}} \:+\beta^{\mathrm{2}} \:+\lambda^{\mathrm{2}} \:{and}\:\:{B}\:=\alpha^{\mathrm{3}} \:+\beta^{\mathrm{3}} \:+\lambda^{\mathrm{3}} \:. \\ $$ Answered by…
Question Number 64061 by mmkkmm000m last updated on 12/Jul/19 $$\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{2}} +\mathrm{25}/\left({x}+\mathrm{3}\right)^{\mathrm{2}} =\sqrt{\mathrm{2}} \\ $$ Answered by MJS last updated on 12/Jul/19 $$\mathrm{no}\:\mathrm{real}\:\mathrm{solutions} \\ $$$$\mathrm{no}\:\mathrm{useable}\:\mathrm{exact}\:\mathrm{solutions} \\…
Question Number 129595 by Adel last updated on 16/Jan/21 $$\mathrm{y}=\sqrt{\mathrm{sin}\:\mathrm{x}+\sqrt{\mathrm{sin}\:\mathrm{x}+\sqrt{\mathrm{sin}\:\mathrm{x}+………….\infty}}} \\ $$$$ \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}=? \\ $$ Answered by ajfour last updated on 16/Jan/21 $${y}^{\mathrm{2}} −\mathrm{sin}\:{x}={y}…
Question Number 63958 by meme last updated on 11/Jul/19 $${x}^{\mathrm{6}} −\mathrm{3}{x}^{\mathrm{5}} +\mathrm{4}{x}^{\mathrm{4}} −\mathrm{6}{x}^{\mathrm{3}} +\mathrm{5}{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$ Commented by Prithwish sen last updated on 11/Jul/19…
Question Number 129489 by mr W last updated on 16/Jan/21 $${if}\:{p}\left({x}+\mathrm{2}\right)−\mathrm{2}{p}\left({x}\right)={x}^{\mathrm{2}} −\mathrm{5}{x}−\mathrm{3} \\ $$$${find}\:{p}\left({x}\right) \\ $$ Answered by bramlexs22 last updated on 16/Jan/21 $$\mathrm{let}\:{p}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c}…
Question Number 63945 by mathmax by abdo last updated on 11/Jul/19 $${solve}\:{at}\:{Z}^{\mathrm{2}} \:\:{x}^{\mathrm{2}} −\mathrm{2}{y}^{\mathrm{2}} \:+{xy}\:+\mathrm{2}\:=\mathrm{0} \\ $$ Commented by hknkrc46 last updated on 11/Jul/19 $${x}^{\mathrm{2}}…
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Question Number 63893 by mathmax by abdo last updated on 10/Jul/19 $$\left.\mathrm{1}\right)\:{simplify}\:{W}_{{n}} \left({z}\right)=\left(\mathrm{1}+{z}\right)\left(\mathrm{1}+{z}^{\mathrm{2}} \right)….\left(\mathrm{1}+{z}^{\mathrm{2}^{{n}} } \right)\:\left({z}\:{from}\:{C}\right) \\ $$$$\left.\mathrm{2}\right)\:{simplify}\:{P}_{{n}} \left(\theta\right)\:=\left(\mathrm{1}+{e}^{{i}\theta} \right)\left(\mathrm{1}+{e}^{\mathrm{2}{i}\theta} \right)…..\left(\mathrm{1}+{e}^{{i}\mathrm{2}^{{n}} \theta} \right)\:{and}\:{sove} \\ $$$${P}_{{n}}…
Question Number 129394 by liberty last updated on 15/Jan/21 $$\begin{cases}{\mathrm{x}^{\mathrm{3}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{5x}+\mathrm{17}=\mathrm{0}}\\{\mathrm{y}^{\mathrm{3}} −\mathrm{3y}^{\mathrm{2}} +\mathrm{5y}+\mathrm{11}=\mathrm{0}}\end{cases} \\ $$$$\:\mathrm{find}\:\mathrm{x}+\mathrm{y}\:. \\ $$ Answered by bemath last updated on 15/Jan/21…