Question Number 193769 by cortano12 last updated on 19/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193714 by Rupesh123 last updated on 18/Jun/23 Commented by Frix last updated on 18/Jun/23 $$\sqrt{\mathrm{17}\pm\sqrt{\mathrm{288}}}=\sqrt{\mathrm{17}\pm\mathrm{12}\sqrt{\mathrm{2}}}=\mathrm{3}\pm\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\sqrt{\mathrm{7}\pm\sqrt{\mathrm{48}}}=\sqrt{\mathrm{7}\pm\mathrm{4}\sqrt{\mathrm{3}}}=\mathrm{2}\pm\sqrt{\mathrm{3}} \\ $$$$\Rightarrow \\ $$$$\mathrm{Answer}\:\mathrm{is}\:\mathrm{2} \\ $$…
Question Number 193707 by Mingma last updated on 18/Jun/23 Answered by Subhi last updated on 18/Jun/23 $$\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} +{c}^{\mathrm{2}} }+\frac{{b}^{\mathrm{2}} }{{a}^{\mathrm{2}} +{c}^{\mathrm{2}} }+\frac{{c}^{\mathrm{2}} }{{a}^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 193688 by Mingma last updated on 18/Jun/23 Answered by cortano12 last updated on 18/Jun/23 $$\:\mathrm{4}\left(\mathrm{2p}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{4}.\left(−\mathrm{1}\right).\left(−\mathrm{2p}−\mathrm{31}\right)<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{4p}+\mathrm{1}−\mathrm{2p}−\mathrm{31}<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{2p}−\mathrm{30}<\mathrm{0} \\…
Question Number 193687 by Mingma last updated on 18/Jun/23 Commented by Frix last updated on 18/Jun/23 $$\mathrm{Squaring}\:\&\:\mathrm{transforming}\:\mathrm{3}\:\mathrm{times}\:\mathrm{leads}\:\mathrm{to} \\ $$$${x}^{\mathrm{8}} −\frac{\mathrm{10}{x}^{\mathrm{7}} }{\mathrm{3}}+\frac{\mathrm{143}{x}^{\mathrm{6}} }{\mathrm{27}}−\frac{\mathrm{854}{x}^{\mathrm{5}} }{\mathrm{81}}+\frac{\mathrm{4352}{x}^{\mathrm{4}} }{\mathrm{243}}−\frac{\mathrm{4678}{x}^{\mathrm{3}} }{\mathrm{243}}+\frac{\mathrm{611}{x}^{\mathrm{2}}…
Question Number 193651 by a.lgnaoui last updated on 17/Jun/23 $$\mathrm{determiner}\:\mathrm{rayon}\:\boldsymbol{\mathrm{R}} \\ $$ Commented by a.lgnaoui last updated on 17/Jun/23 Terms of Service Privacy Policy Contact:…
Question Number 193647 by Rupesh123 last updated on 17/Jun/23 Answered by MM42 last updated on 17/Jun/23 $${both}\:{numbers}\:{a}\:,\:{b}\:{can}\:{not}\:{be}\:{odd}. \\ $$$${so}\:{a}=\mathrm{2}\:{or}\:{b}=\mathrm{2} \\ $$$${if}\:\:{a}=\mathrm{2}\:\&\:{b}=\mathrm{3}\:\Rightarrow{p}=\mathrm{2}^{\mathrm{3}} +\mathrm{7}×\mathrm{3}^{\mathrm{2}} =\mathrm{71}\:\checkmark \\ $$$${if}\:\:{a}=\mathrm{3}\:\&\:{b}=\mathrm{2}\Rightarrow\:{p}=\mathrm{3}^{\mathrm{2}}…
Question Number 193565 by Mingma last updated on 16/Jun/23 Answered by mr W last updated on 17/Jun/23 $${say}\:{at}\:{time}\:{x}\:{hours}\:{after}\:\mathrm{0}\:{o}'{clock}. \\ $$$${assume}\:{the}\:{hands}\:{move}\:{continuously}. \\ $$$${position}\:{of}\:{hour}\:{hand}:\:\mathrm{30}{x}\:° \\ $$$${position}\:{of}\:{minute}\:{hand}:\:\left({x}−\left[{x}\right]\right)×\mathrm{60}×\mathrm{6}\:° \\…
Question Number 193525 by mustafazaheen last updated on 16/Jun/23 $$\:\:\:\:\:\frac{\mathrm{27t73}}{\mathrm{11}} \\ $$$$\:\:\:\:\:\mathrm{and}\:\mathrm{R}=\mathrm{0}\:\:\:\mathrm{then}\:\mathrm{t}=? \\ $$$$\:\:\:\:\:\:\mathrm{how}\:\mathrm{is}\:\mathrm{explontry}\:\mathrm{solution} \\ $$ Answered by MM42 last updated on 16/Jun/23 $$\mathrm{3}−\mathrm{7}+{t}−\mathrm{7}+\mathrm{2}=\mathrm{11}{k}\Rightarrow−\mathrm{9}+{t}=\mathrm{11}{k}\Rightarrow{t}=\mathrm{9} \\…
Question Number 193546 by York12 last updated on 16/Jun/23 $${if}\:{a}+{b}+{c}=\mathrm{1} \\ $$$${find}\:{maximum}\:{ab}\:+{bc}\:+{ca}\: \\ $$$${a}\:,\:{b}\:,\:{c}\:{are}\:{non}\:{negative}\:{integers} \\ $$$$ \\ $$ Answered by Frix last updated on 16/Jun/23…