Question Number 62055 by hhghg last updated on 14/Jun/19 $$\$\mathrm{8}+\$\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62053 by hhghg last updated on 14/Jun/19 $$\mathrm{m5}=\mathrm{25} \\ $$ Commented by meme last updated on 15/Jun/19 $${m}=\mathrm{5} \\ $$$$ \\ $$ Terms…
Question Number 62054 by hhghg last updated on 14/Jun/19 $$\mathrm{484}×\mathrm{27} \\ $$ Commented by Tony Lin last updated on 15/Jun/19 $$=\mathrm{11}^{\mathrm{2}} ×\mathrm{6}^{\mathrm{2}} ×\mathrm{3} \\ $$$$=\left(\mathrm{108}×\mathrm{11}\right)×\mathrm{11}…
Question Number 62051 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{7}^{\mathrm{5}} }{\mathrm{7}^{\mathrm{3}} } \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\mathrm{7}^{\mathrm{5}−\mathrm{3}} \:=\mathrm{7}^{\mathrm{2}}…
Question Number 62052 by hhghg last updated on 14/Jun/19 $$\mathrm{3}\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\mathrm{3}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}}=\mathrm{0} \\ $$ Terms…
Question Number 62050 by hhghg last updated on 14/Jun/19 $$\left[\mathrm{3}×\mathrm{5}+\mathrm{3}\right]+\left[\mathrm{3}+\left(\mathrm{3}×\mathrm{2}\right)\right] \\ $$ Commented by meme last updated on 15/Jun/19 $$=\mathrm{18}+\mathrm{9} \\ $$$$=\mathrm{27} \\ $$ Terms…
Question Number 62049 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{5}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\left(\mathrm{1}×\mathrm{5}\right)+\left(\mathrm{4}×\mathrm{1}\right)}{\mathrm{4}×\mathrm{5}}\:=\frac{\mathrm{5}+\mathrm{4}}{\mathrm{20}}\:=\frac{\mathrm{9}}{\mathrm{20}} \\ $$ Terms…
Question Number 62047 by hhghg last updated on 14/Jun/19 $$\left(\mathrm{4y}\right)^{\mathrm{2}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\left(\mathrm{4}{y}\right)×\left(\mathrm{4}{y}\right)\:=\mathrm{16}{y}^{\mathrm{2}} \\ $$ Terms…
Question Number 62048 by hhghg last updated on 14/Jun/19 $$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{3}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\mathrm{1}^{\mathrm{3}} }{\mathrm{2}^{\mathrm{3}} }\:=\frac{\mathrm{1}}{\mathrm{8}} \\…
Question Number 62046 by hhghg last updated on 14/Jun/19 $$\mathrm{4}×\left(\mathrm{3}+\mathrm{2}−\mathrm{3}\right) \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\mathrm{4}×\left(\mathrm{5}−\mathrm{3}\right)\:=\mathrm{4}×\mathrm{2}\:=\mathrm{8} \\ $$ Terms…