Category: Algebra

Question Number 196086 by MM42 last updated on 17/Aug/23 $$Answertothequestion“{196008}^{″}$$$$\underset{k=1}{\sum ^n}{tan}^2\left(\frac{k\pi }{2n+1}\right)=n(2n+1)$$$$Ans)$$$$according“de{moivre}^{″}$$$${sin}\left(\mathrm{2}{n}+\mathrm{1}\right)\alpha=$$\left(\begin{array}{c}2n+1\\ 1\end{array}\right)$$\left({cos}\alpha\right)^{\mathrm{2}{n}} {sin}\alpha−$$\left(\begin{array}{c}2n+1\\ 3\end{array}\right)$$\left({cos}\alpha\right)^{\mathrm{2}{n}−\mathrm{2}} \left({sin}\alpha\right)^{\mathrm{3}} +…. \…

Question Number 196066 by sniper237 last updated on 17/Aug/23 $${\left(\begin{array}{c}1-1\\ -12\end{array}\right)}^{-8}=?$$ Answered by witcher3 last updated on 17/Aug/23 $$\left(\begin{array}{c}1-1\\ -12\end{array}\right)=\mathrm{A}$$$$\mathrm{A}^{\mathrm{2}} =$$\left(\begin{array}{c}2-3\\ -33\end{array}\right)$$=\mathrm{3A}−\mathrm{I}_{\mathrm{2}} \…

Question Number 195998 by Frix last updated on 15/Aug/23 $$\mathrm{We}\mathrm{can}\mathrm{transform}\mathrm{to}\mathrm{get}\mathrm{rid}\mathrm{of}\mathrm{the}\sqrt[3]{\dots }$$$$a^{\frac{1}{3}}+b^{\frac{1}{3}}=c^{\frac{1}{3}}$$$${(a^{\frac{1}{3}}+b^{\frac{1}{3}})}^3=c$$$${a}+{b}+\mathrm{3}{a}^{\frac{\mathrm{1}}{\mathrm{3}}} {b}^{\frac{\mathrm{1}}{\mathrm{3}}} \left({a}^{\frac{\mathrm{1}}{\mathrm{3}}} +{b}^{\frac{\mathrm{1}}{\mathrm{3}}} \right)={c}…

Question Number 195971 by mr W last updated on 14/Aug/23 $$if{f}^{\prime }\left(x\right)=\frac{f(x+a)-f\left(x\right)}{a},findf\left(x\right).$$ Answered by jabarsing last updated on 14/Aug/23 $$hellomr.wdear$$$$f\left(x\right)=C\left(conestantfunction\right)=?$$$${is}\:{true}?…

Question Number 195911 by Calculusboy last updated on 13/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com