Question Number 192925 by Shrinava last updated on 31/May/23 $$\mathrm{Find}:\:\:\:\mathrm{x}\:=\:? \\ $$$$\mathrm{1}.\:\mathrm{2}^{\boldsymbol{\mathrm{x}}+\mathrm{1}} \:+\:\mathrm{0},\mathrm{5}^{\boldsymbol{\mathrm{x}}−\mathrm{2}} \:=\:\mathrm{9} \\ $$$$\mathrm{2}.\:\mathrm{4}^{\mathrm{3}\boldsymbol{\mathrm{x}}} \:=\:\mathrm{12} \\ $$$$\mathrm{3}.\:\mathrm{6}^{\boldsymbol{\mathrm{x}}+\mathrm{2}} \:=\:\mathrm{18} \\ $$ Answered by MM42…
Question Number 192924 by a.lgnaoui last updated on 31/May/23 $$\mathrm{1}\bullet\mathrm{determiner}:\:\mathrm{tan}\:\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\:\:\mathrm{en}\:\mathrm{fonction}\:\mathrm{de}\:\mathrm{tan}\:\boldsymbol{\mathrm{x}} \\ $$$$\mathrm{2}\bullet\mathrm{on}\:\mathrm{donne}\:\:\mathrm{tan}\:\boldsymbol{\mathrm{x}}=\frac{\mathrm{1}}{\mathrm{8}}\:\:\:\:\mathrm{tan}\:\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}=? \\ $$$$\mathrm{3}\bullet\:\:\mathrm{la}\:\mathrm{valeur}\:\mathrm{proche}\:\mathrm{de}\:\boldsymbol{\mathrm{x}}? \\ $$ Answered by a.lgnaoui last updated on 31/May/23 $$\mathrm{1}\bullet\mathrm{tan}\:\mathrm{x}=\frac{\mathrm{2t}}{\mathrm{1}−\mathrm{t}^{\mathrm{2}} }\:\:\:\:\mathrm{t}=\mathrm{tan}\left(\:\frac{\mathrm{x}}{\mathrm{2}}\right)…
Question Number 192926 by Shrinava last updated on 31/May/23 $$\mathrm{1}.\:\mathrm{7}^{\mathrm{3}\boldsymbol{\mathrm{x}}−\mathrm{1}} \:\geqslant\:\mathrm{21} \\ $$$$\mathrm{2}.\:\mathrm{6},\mathrm{5}^{\mathrm{2}\boldsymbol{\mathrm{x}}} \:\geqslant\:\mathrm{200} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 61850 by mr W last updated on 10/Jun/19 $${Find}\:{all}\:{integer}\:{solution}\left({s}\right): \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{615}+\boldsymbol{{x}}^{\mathrm{2}} =\mathrm{2}^{\boldsymbol{{y}}} \\ $$ Commented by Rasheed.Sindhi last updated on 10/Jun/19 $${One}\:{solution}:\:\:{x}=\mathrm{59}\:,\:{y}=\mathrm{12} \\…
Question Number 192917 by BaliramKumar last updated on 31/May/23 Answered by AST last updated on 31/May/23 $${Let}\:{tan}\theta={t},{cot}\theta={c};\:{tc}=\mathrm{1} \\ $$$${t}^{\mathrm{2}} +{c}^{\mathrm{2}} =\left({t}+{c}\right)^{\mathrm{2}} −\mathrm{2}{tc}=\left({t}+{c}\right)^{\mathrm{2}} −\mathrm{2} \\ $$$${t}^{\mathrm{5}}…
Question Number 192914 by ajfour last updated on 30/May/23 $${x}^{\mathrm{2}} \left({x}^{\mathrm{2}} −\mathrm{1}\right)=\left(\mathrm{1}−\frac{{c}}{{x}}\right)^{\mathrm{3}} +\left(\frac{{c}}{{x}}\right)^{\mathrm{3}} \\ $$ Answered by a.lgnaoui last updated on 31/May/23 $$\mathrm{x}^{\mathrm{2}} \left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)=\frac{\left(\mathrm{x}−\mathrm{c}\right)^{\mathrm{3}}…
Question Number 192898 by Red1ight last updated on 30/May/23 $$\mathrm{Solve}\:\mathrm{for}\:{x} \\ $$$${x}^{\mathrm{3}} −\mathrm{7}{x}−\mathrm{2}=\mathrm{0} \\ $$ Commented by Frix last updated on 30/May/23 $$\mathrm{You}\:\mathrm{need}\:\mathrm{the}\:{Trigonometric}\:{Solution}\:\mathrm{to} \\ $$$$\mathrm{get}\:\mathrm{exact}\:\mathrm{solutions}:…
Question Number 61811 by rajesh4661kumar@gamil.com last updated on 09/Jun/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192883 by ajfour last updated on 30/May/23 Answered by ajfour last updated on 30/May/23 $$\left({p}+{s}\right)^{\mathrm{3}} −\left({p}+{s}\right)={k} \\ $$$${p}^{\mathrm{3}} −{p}={c} \\ $$$${s}\left\{\left({p}+{s}\right)^{\mathrm{2}} +{p}^{\mathrm{2}} +{p}\left({p}+{s}\right)\right\}−{s}={k}−{c}…
Question Number 127344 by bobhans last updated on 29/Dec/20 $${S}\:=\:\underset{{n}=\mathrm{4}} {\overset{\infty} {\sum}}\ell{n}\:\left(\mathrm{1}−\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\right)\:=?\: \\ $$ Answered by liberty last updated on 29/Dec/20 $$\:{S}\:=\:\underset{{n}=\mathrm{4}} {\overset{\infty} {\sum}}\mathrm{ln}\:\left(\mathrm{1}−\frac{\mathrm{1}}{{n}^{\mathrm{2}}…