Menu Close

Category: Algebra

Question-129364

Question Number 129364 by shaker last updated on 15/Jan/21 Answered by mindispower last updated on 15/Jan/21 $${let}\:\alpha={e}^{{i}\frac{\pi}{\mathrm{4}}} \\ $$$$\alpha,\alpha^{\mathrm{3}} ,\alpha^{\mathrm{5}} ,\alpha^{\mathrm{7}} \:{are}\:{roots}\:{of}\:{x}^{\mathrm{4}} +\mathrm{1}=\mathrm{0} \\ $$$$\frac{{x}^{\mathrm{2}}…

f-x-1-f-x-1-x-2-f-1-x-

Question Number 129343 by Study last updated on 15/Jan/21 $${f}\left({x}+\mathrm{1}\right)={f}\left({x}−\mathrm{1}\right)={x}^{\mathrm{2}} \:\:\:\:\:\:\:\:{f}^{−\mathrm{1}} \left({x}\right)=?? \\ $$ Commented by bramlexs22 last updated on 15/Jan/21 $$\mathrm{f}\left(\mathrm{x}+\mathrm{1}\right)+\mathrm{f}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{x}^{\mathrm{2}} \:? \\ $$…

Question-63803

Question Number 63803 by aliesam last updated on 09/Jul/19 Commented by Prithwish sen last updated on 09/Jul/19 $$\left(\mathrm{x}+\mathrm{iy}\right)^{\mathrm{3}} \:=\:\frac{\left(\mathrm{1}+\sqrt{\mathrm{7}}\mathrm{i}\right)^{\mathrm{2}} }{\mathrm{1}−\sqrt{\mathrm{7}}\mathrm{i}}\:=\:\frac{\left(\mathrm{1}+\sqrt{\mathrm{7}}\mathrm{i}\right)^{\mathrm{3}} }{\mathrm{8}} \\ $$$$\:\therefore\:\mathrm{x}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{y}\:=\:\frac{\sqrt{\mathrm{7}}}{\mathrm{2}} \\ $$…

Question-129320

Question Number 129320 by ajfour last updated on 14/Jan/21 Commented by gaferrafie last updated on 14/Jan/21 سلام چطور میشه تو خروجی آدرس سایت را حذف کرد Answered by ajfour last updated on 14/Jan/21 $${y}=\left({x}−{p}\right)\left({x}^{\mathrm{3}}…