Menu Close

Category: Algebra

Which-is-larger-Z-1-2-3-6-4-11-or-S-1-2-3-6-5-11-

Question Number 128341 by liberty last updated on 06/Jan/21 $$\mathrm{Which}\:\mathrm{is}\:\mathrm{larger}\:\mathrm{Z}\:=\:\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{3}}{\mathrm{6}−\frac{\mathrm{4}}{\mathrm{11}}}}\:\mathrm{or}\:\mathrm{S}\:=\:\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{3}}{\mathrm{6}−\frac{\mathrm{5}}{\mathrm{11}}}}\:? \\ $$ Commented by mr W last updated on 06/Jan/21 $${without}\:{calculation}: \\ $$$${Z}:\:{larger}\nearrow{smaller}\nearrow{larger} \\ $$$$\Rightarrow{Z}\:{is}\:{larger}\:{than}\:{S}.…

2-Solution-set-x-2x-6-lt-3x-is-2-If-lim-x-2-2-a-bx-3-x-2-H-then-lim-x-2-x-2-4-a-bx-3-1-

Question Number 128329 by bramlexs22 last updated on 06/Jan/21 $$\left(\mathrm{2}\right)\mathrm{Solution}\:\mathrm{set}\::\:{x}\:\mid\mathrm{2}{x}−\mathrm{6}\:\mid\:<\:\mathrm{3}{x}\: \\ $$$$\mathrm{is}\:\_ \\ $$$$\left(\mathrm{2}\right)\:\mathrm{If}\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{\mathrm{2}−\sqrt{{a}+{bx}^{\mathrm{3}} }}{{x}−\mathrm{2}}\:=\:{H}\:,\:{then} \\ $$$$\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} −\mathrm{4}}{\:\sqrt{{a}+{bx}^{\mathrm{3}} }−\mathrm{1}}\:=\:\_ \\ $$ Answered by…

find-10-1-10-1-10-1-10-1-10-A-5-2-6-B-5-2-6-C-5-2-6-D-none-of-above-please-give-your-answer-and-explain-why-

Question Number 128290 by mr W last updated on 06/Jan/21 $${find}\:\mathrm{10}−\frac{\mathrm{1}}{\mathrm{10}−\frac{\mathrm{1}}{\mathrm{10}−\frac{\mathrm{1}}{\mathrm{10}−\frac{\mathrm{1}}{\mathrm{10}−……}}}}=? \\ $$$$\left({A}\right)\:\:\:\:\:\mathrm{5}−\mathrm{2}\sqrt{\mathrm{6}} \\ $$$$\left({B}\right)\:\:\:\:\:\mathrm{5}+\mathrm{2}\sqrt{\mathrm{6}} \\ $$$$\left({C}\right)\:\:\:\:\:\mathrm{5}\pm\mathrm{2}\sqrt{\mathrm{6}} \\ $$$$\left({D}\right)\:\:\:\:\:{none}\:{of}\:{above} \\ $$$$ \\ $$$${please}\:{give}\:{your}\:{answer}\:{and}\:{explain} \\ $$$${why}!…

2207-1-2207-1-2207-1-2207-1-2207-1-8-

Question Number 128264 by bobhans last updated on 06/Jan/21 $$\sqrt[{\mathrm{8}\:\:\:\:}]{\mathrm{2207}−\frac{\mathrm{1}}{\mathrm{2207}−\frac{\mathrm{1}}{\mathrm{2207}−\frac{\mathrm{1}}{\mathrm{2207}−\frac{\mathrm{1}}{\mathrm{2207}−…}}}}} \\ $$ Commented by MJS_new last updated on 06/Jan/21 $$\frac{\mathrm{3}+\sqrt{\mathrm{5}}}{\mathrm{2}} \\ $$ Commented by bobhans…

1-For-n-N-define-s-n-1-2-2-n-2-2-n-1-Which-of-the-following-is-false-for-some-values-of-n-N-A-3-s-n-B-7-s-n-C-s-n-s-n-1-D-s-n-2-gt-s-n-1-E-12s-1-s-2-s-n-lt-s-n-1-

Question Number 128232 by math35 last updated on 05/Jan/21 $$\mathrm{1}.\mathrm{For}\:\mathrm{n}\in\mathbb{N},\mathrm{define}\:\:\mathrm{s}_{\mathrm{n}} =\mathrm{1}+\mathrm{2}^{\mathrm{2}^{\mathrm{n}} } +\mathrm{2}^{\mathrm{2}^{\mathrm{n}+\mathrm{1}} } .\mathrm{Which}\:\mathrm{of}\: \\ $$$$\mathrm{the}\:\mathrm{following}\:\mathrm{is}\:\mathrm{false}\:\mathrm{for}\:\mathrm{some}\:\mathrm{values}\:\mathrm{of}\:\mathrm{n}\in\mathbb{N}? \\ $$$$\mathrm{A}.\mathrm{3}\mid\mathrm{s}_{\mathrm{n}} \\ $$$$\mathrm{B}.\mathrm{7}\mid\mathrm{s}_{\mathrm{n}} \\ $$$$\mathrm{C}.\mathrm{s}_{\mathrm{n}} \mid\mathrm{s}_{\mathrm{n}+\mathrm{1}} \\…

Question-62676

Question Number 62676 by bshahid010@gmail.com last updated on 24/Jun/19 Commented by kaivan.ahmadi last updated on 24/Jun/19 $${if}\:{tanx}={n}>\mathrm{0}\Rightarrow \\ $$$${n}^{\mathrm{2}} +{an}+{n}+{a}−\mathrm{3}<\mathrm{0}\Rightarrow{a}\left({n}+\mathrm{1}\right)<\mathrm{3}−{n}^{\mathrm{2}} −{n}\Rightarrow \\ $$$${a}<\frac{\mathrm{3}−{n}−{n}^{\mathrm{2}} }{{n}+\mathrm{1}} \\…

Let-x-y-z-be-pairwise-distinct-real-numbers-if-x-y-7-z-x-y-24-y-z-7-x-y-z-24-z-x-7-y-z-x-24-Find-x-2-y-2-

Question Number 128204 by I want to learn more last updated on 05/Jan/21 $$\mathrm{Let}\:\:\:\mathrm{x},\:\:\mathrm{y},\:\:\mathrm{z}\:\:\:\mathrm{be}\:\mathrm{pairwise}\:\mathrm{distinct}\:\mathrm{real}\:\mathrm{numbers},\:\mathrm{if} \\ $$$$\:\:\left(\mathrm{x}\:\:+\:\:\mathrm{y}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{z}\left(\mathrm{x}\:\:+\:\:\mathrm{y}\right)\:\:+\:\:\mathrm{24}\right]\:\:\:=\:\:\left(\mathrm{y}\:\:+\:\:\mathrm{z}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{x}\left(\mathrm{y}\:\:+\:\:\mathrm{z}\right)\:\:+\:\:\mathrm{24}\right]\:\:\:=\:\:\:\left(\mathrm{z}\:\:+\:\:\mathrm{x}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{y}\left(\mathrm{z}\:\:+\:\:\mathrm{x}\right)\:\:+\:\:\mathrm{24}\right] \\ $$$$\mathrm{Find}\:\:\:\:\:\mathrm{x}^{\mathrm{2}} \:\:+\:\:\mathrm{y}^{\mathrm{2}} \:\:+\:\:\mathrm{z}^{\mathrm{2}} \\ $$ Terms of Service…