Question Number 192780 by ajfour last updated on 27/May/23 Commented by ajfour last updated on 27/May/23 Find m in terms of c, hence p. Answered by ajfour last updated on 27/May/23 $${y}={x}^{\mathrm{3}}…
Question Number 192777 by York12 last updated on 26/May/23 $$\sqrt{{x}^{\mathrm{2}} +{ax}−\mathrm{1}}−\sqrt{{x}^{\mathrm{2}} +{bx}−\mathrm{1}}=\sqrt{{a}}−\sqrt{{b}} \\ $$$${find}\:{x}\:. \\ $$ Commented by Frix last updated on 27/May/23 $$\mathrm{Obviously}\:{x}=\mathrm{1} \\…
Question Number 61708 by hhghg last updated on 06/Jun/19 $$\mathrm{8}+\left(\mathrm{4}+\mathrm{3}×\mathrm{2}\right) \\ $$ Commented by Mikael last updated on 06/Jun/19 $$\mathrm{8}+\mathrm{4}+\mathrm{6}=\mathrm{18} \\ $$ Terms of Service…
Question Number 61707 by hhghg last updated on 06/Jun/19 $$\mathrm{6}^{−\mathrm{3}} \\ $$ Commented by Mikael last updated on 06/Jun/19 $$=\:\left(\frac{\mathrm{1}}{\mathrm{6}}\right)^{\mathrm{3}} =\:\frac{\mathrm{1}}{\mathrm{216}} \\ $$ Terms of…
Question Number 61706 by hhghg last updated on 06/Jun/19 $$\frac{\mathrm{7}^{\mathrm{10}} }{\mathrm{7}^{\mathrm{7}} } \\ $$ Commented by Mikael last updated on 06/Jun/19 $$\mathrm{7}^{\mathrm{10}−\mathrm{7}} \:=\:\mathrm{7}^{\mathrm{3}} \:=\:\mathrm{343} \\…
Question Number 61691 by Tony Lin last updated on 06/Jun/19 $${f}\left({x}\right)=\sqrt{{x}^{\mathrm{4}} −\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}}+\sqrt{{x}^{\mathrm{4}} −\mathrm{3}{x}^{\mathrm{2}} −\mathrm{8}{x}+\mathrm{20}} \\ $$$${find}\:{the}\:{minimum}\:{value}\:{of}\:{f}\left({x}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 61652 by maxmathsup by imad last updated on 05/Jun/19 $${solve}\:{inside}\:{C}\:\:{z}^{\mathrm{4}} \:=\frac{\mathrm{1}−{i}}{\mathrm{1}+{i}\sqrt{\mathrm{3}}} \\ $$ Commented by maxmathsup by imad last updated on 06/Jun/19 $${we}\:{have}\:\mid\mathrm{1}−{i}\mid=\sqrt{\mathrm{2}}\:\Rightarrow\mathrm{1}−{i}\:=\sqrt{\mathrm{2}}{e}^{−\frac{{i}\pi}{\mathrm{4}}}…
Question Number 192721 by York12 last updated on 25/May/23 $$ \\ $$$${x}^{\mathrm{3}} −\mathrm{3}{xy}^{\mathrm{2}} =\mathrm{18} \\ $$$$\mathrm{3}{x}^{\mathrm{2}} {y}−{y}^{\mathrm{3}} =\mathrm{26} \\ $$$${and}\:{what}\:{do}\:{you}\:{recommend}\:{to}\:{read}\:{to}\:{deal} \\ $$$${with}\:{such}\:{problems} \\ $$ Answered…
Question Number 61651 by maxmathsup by imad last updated on 05/Jun/19 $${let}\:{p}\left({x}\right)\:=\left({x}+{i}\sqrt{\mathrm{3}}\right)^{{n}} +\left({x}−{i}\sqrt{\mathrm{3}}\right)^{{n}} \:\:\:\:{with}\:{x}\:{real} \\ $$$$\left.\mathrm{1}\right)\:{simlify}\:{p}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{roots}\:{of}\:{P}\left({x}\right) \\ $$$$\left.\mathrm{3}\right){decompose}\:{inside}\:{C}\left[{x}\right]\:\:{p}\left({x}\right) \\ $$$$\left.\mathrm{4}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} {p}\left({x}\right){dx}\: \\…
Question Number 192720 by pascal889 last updated on 25/May/23 Answered by Frix last updated on 25/May/23 $${x}={p}−{q}\wedge{y}={p}+{q} \\ $$$$\Rightarrow \\ $$$$\mathrm{5}{p}^{\mathrm{4}} +\mathrm{6}{p}^{\mathrm{2}} {q}^{\mathrm{2}} +\mathrm{5}{q}^{\mathrm{4}} =\mathrm{109}…