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Category: Algebra

Question-64542

Question Number 64542 by LPM last updated on 19/Jul/19 Answered by MJS last updated on 19/Jul/19 b=1aa2+(1a)2=2a=12±32b=1232$${a}^{\mathrm{7}} =\frac{\mathrm{71}}{\mathrm{16}}\pm\frac{\mathrm{41}\sqrt{\mathrm{3}}}{\mathrm{16}}\:\:\:{b}^{\mathrm{7}} =\frac{\mathrm{71}}{\mathrm{16}}\mp\frac{\mathrm{41}\sqrt{\mathrm{3}}}{\mathrm{16}}…