Question Number 210142 by Abdullahrussell last updated on 01/Aug/24 Commented by Frix last updated on 02/Aug/24 $$\mathrm{I}\:\mathrm{think}\:\mathrm{there}\:\mathrm{is}\:\mathrm{only}\:\mathrm{one}\:“\mathrm{nice}''\:\mathrm{solution}: \\ $$$${x}=\frac{\mathrm{3}}{\mathrm{2}}−\frac{\sqrt{\mathrm{11}}}{\mathrm{2}}\mathrm{i}\:\:\:\:\:{y}=\frac{\mathrm{3}}{\mathrm{2}}+\frac{\sqrt{\mathrm{11}}}{\mathrm{2}}\mathrm{i}\:\:\:\:\:{z}=\mathrm{3} \\ $$$$\Rightarrow\:{x}+{y}+{z}=\mathrm{6} \\ $$$$\mathrm{But}\:\mathrm{there}\:\mathrm{should}\:\mathrm{be}\:\mathrm{more}\:\mathrm{solutions}\:\mathrm{with} \\ $$$${x}+{y}+{z}\in\mathbb{R}…
Question Number 210157 by Spillover last updated on 01/Aug/24 Answered by A5T last updated on 01/Aug/24 $${Let}\:{distance}\:{of}\:{vertex},{V},\:{to}\:{centroid},{G},\:{be}\:{GV} \\ $$$$\Rightarrow\frac{{sin}\mathrm{30}°}{{GV}}=\frac{{sin}\mathrm{120}^{°} }{{x}}\Rightarrow{GV}=\frac{\frac{{x}}{\mathrm{2}}}{\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}}=\frac{{x}\sqrt{\mathrm{3}}}{\mathrm{3}} \\ $$$${H}=\sqrt{{x}^{\mathrm{2}} −{GV}^{\mathrm{2}} }=\sqrt{{x}^{\mathrm{2}} −\frac{{x}^{\mathrm{2}}…
Question Number 210155 by Spillover last updated on 01/Aug/24 Answered by A5T last updated on 01/Aug/24 Commented by A5T last updated on 01/Aug/24 $${C}\:{is}\:{the}\:{origin}\:{and}\:{redundant} \\…
Question Number 210171 by hardmath last updated on 01/Aug/24 $$\mathrm{Find}: \\ $$$$\underset{\boldsymbol{\mathrm{n}}\rightarrow+\infty} {\mathrm{lim}}\:\:\frac{\mathrm{n}}{\left(\mathrm{n}!\right)^{\mathrm{2}} \:\mathrm{4}^{\boldsymbol{\mathrm{n}}} }\:\:\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\prod}}\:\left(\left(\mathrm{2k}−\mathrm{1}\right)^{\mathrm{2}} \:+\:\mathrm{4}\right)\:=\:? \\ $$ Terms of Service Privacy Policy…
Question Number 210126 by mnjuly1970 last updated on 31/Jul/24 Answered by Frix last updated on 31/Jul/24 $$\mathrm{These}\:\mathrm{substitutions}\:\mathrm{make}\:\mathrm{it}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{see} \\ $$$$\mathrm{what}'\mathrm{s}\:\mathrm{going}\:\mathrm{on}: \\ $$$$ \\ $$$$\mathrm{Let}\:{x}=\mathrm{sin}\:\alpha\:\overset{\left[\mathrm{differentiate}\right]} {\Rightarrow} \\…
Question Number 210124 by peter frank last updated on 31/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210127 by essaad last updated on 31/Jul/24 Answered by lepuissantcedricjunior last updated on 01/Aug/24 $$\int_{\mathrm{1}} ^{\mathrm{2}} \frac{\boldsymbol{{ln}}\left(\mathrm{1}+\boldsymbol{{x}}\right)−\boldsymbol{{lnx}}}{\boldsymbol{{x}}^{\mathrm{2}} }\boldsymbol{{dx}}=\int_{\mathrm{1}} ^{\mathrm{2}} \frac{\boldsymbol{{ln}}\left(\mathrm{1}+\boldsymbol{{x}}\right)}{\boldsymbol{{x}}^{\mathrm{2}} }\boldsymbol{{dx}}−\int_{\mathrm{0}} ^{\mathrm{2}} \frac{\boldsymbol{{lnx}}}{\boldsymbol{{x}}^{\mathrm{2}}…
Question Number 210091 by mr W last updated on 30/Jul/24 $${find}\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{2}{n}^{\mathrm{2}} }\right)=? \\ $$ Commented by AlagaIbile last updated on 30/Jul/24 $$\:\:\underset{{n}=\mathrm{1}}…
Question Number 210079 by Spillover last updated on 30/Jul/24 $${Find}\:{directional}\:{derivatives}\left({D}_{{v}} \right){of}\:\: \\ $$$${f}\left({x},{y},{z}\right)=\mathrm{3}{xy}^{\mathrm{3}} −\mathrm{2}{xz}^{\mathrm{2}} \:\:{in}\:{the}\:{direction}\:{of}\:{the} \\ $$$${v}=\mathrm{2}{i}−\mathrm{3}{j}+\mathrm{6}{k}. \\ $$$${then}\:{Evaluate}\:{directional}\:{derivatives}\: \\ $$$${at}\:{the}\:{point}\:\left(\mathrm{3},\mathrm{1},−\mathrm{2}\right) \\ $$ Terms of…
Question Number 210078 by Spillover last updated on 29/Jul/24 $${Find}\:{the}\:{directional}\:{derivative}\:{of} \\ $$$${f}\left({x},{y}\right)=\mathrm{4}{x}^{\mathrm{3}} −\mathrm{3}{x}^{\mathrm{2}} {y}^{\mathrm{2}} \:\:\:{in}\:{the}\:{direction}\:{given} \\ $$$${by}\:{the}\:{angle}\:\theta=\frac{\pi}{\mathrm{3}}\: \\ $$$${and}\:{also}\:{Evaluate}\:{directional}\:{derivatives} \\ $$$${at}\:{the}\:{point}\:\left(\mathrm{1},\mathrm{2}\right) \\ $$ Answered by…