Menu Close

Category: Algebra

1-1-1-5-5-5-

Question Number 191019 by Albert12 last updated on 16/Apr/23 $$\mathrm{1}−\frac{\mathrm{1}−\frac{\mathrm{1}−\frac{\iddots}{\mathrm{5}}}{\mathrm{5}}}{\mathrm{5}}\:\:=? \\ $$ Answered by 073 last updated on 16/Apr/23 $$\mathrm{1}−\frac{\mathrm{x}}{\mathrm{5}}=\mathrm{x} \\ $$$$\mathrm{1}=\mathrm{x}+\frac{\mathrm{x}}{\mathrm{5}}=\frac{\mathrm{6x}}{\mathrm{5}} \\ $$$$\mathrm{6x}=\mathrm{5} \\…

Question-125428

Question Number 125428 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${Find}\:{equation}\:{of}\:{circle}\:{passing} \\ $$$${through}\:\left(\mathrm{1},\mathrm{1}\right)\:{and}\:{P}\:\left({p},{p}^{\mathrm{2}} \right)\:{with} \\ $$$${radius}\:{t}<\mathrm{1}/\mathrm{2}\:.\: \\ $$ Terms…

Question-190947

Question Number 190947 by Shrinava last updated on 15/Apr/23 Answered by mr W last updated on 15/Apr/23 $$\frac{{BD}}{{AB}}=\frac{\mathrm{sin}\:\beta}{\mathrm{sin}\:\mathrm{30}}\:\:\:…\left({i}\right) \\ $$$$\frac{{AB}}{{AC}}=\frac{\mathrm{sin}\:\left(\beta+\mathrm{45}\right)}{\mathrm{sin}\:\mathrm{45}}\:\:\:…\left({ii}\right) \\ $$$$\left({i}\right)×\left({ii}\right): \\ $$$$\mathrm{1}=\frac{\mathrm{sin}\:\beta\:\mathrm{sin}\:\left(\beta+\mathrm{45}\right)}{\mathrm{sin}\:\mathrm{30}\:\mathrm{sin}\:\mathrm{45}} \\…