Question Number 191798 by Abdullahrussell last updated on 30/Apr/23 Commented by Frix last updated on 30/Apr/23 $$\mathrm{Qu}\:\mathrm{191753};\:\mathrm{just}\:\mathrm{add}\:−\mathrm{3}+\mathrm{24}=\mathrm{21} \\ $$ Commented by BaliramKumar last updated on…
Question Number 60723 by alphaprime last updated on 25/May/19 $${solve}\:{for}\:{x}\: \\ $$$$\sqrt{{a}−\sqrt{{a}+{x}}}\:+\:\sqrt{{a}+\sqrt{{a}−{x}}}\:=\:\mathrm{2}{x} \\ $$ Commented by MJS last updated on 25/May/19 $$\mathrm{what}'\mathrm{s}\:\mathrm{the}\:\mathrm{source}\:\mathrm{of}\:\mathrm{this}\:\mathrm{problem}? \\ $$ Commented…
Question Number 191790 by mathlove last updated on 30/Apr/23 $${prove}\:{that} \\ $$$$\frac{\mathrm{2}{x}−\mathrm{4}}{\mathrm{2}\centerdot\mathrm{3}\centerdot\mathrm{4}}+\frac{\mathrm{3}{x}−\mathrm{5}}{\mathrm{3}\centerdot\mathrm{4}\centerdot\mathrm{5}}+\frac{\mathrm{4}{x}−\mathrm{6}}{\mathrm{4}\centerdot\mathrm{5}\centerdot\mathrm{6}}+…..+\frac{\mathrm{100}{x}−\mathrm{102}}{\mathrm{100}\centerdot\mathrm{101}\centerdot\mathrm{102}}=\frac{\mathrm{103}}{\mathrm{102}} \\ $$$$ \\ $$ Commented by BaliramKumar last updated on 01/May/23 $$\mathrm{if}\:\mathrm{x}=\mathrm{1}\:\mathrm{then}\:\mathrm{all}\:\mathrm{term}\:\left(−\mathrm{ve}\right)\:\mathrm{but}\:\frac{\mathrm{103}}{\mathrm{102}}\:\mathrm{is}\:\left(+\mathrm{ve}\right)\: \\…
Question Number 60705 by behi83417@gmail.com last updated on 24/May/19 Answered by MJS last updated on 25/May/19 $$\mathrm{the}\:\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:{x}={y}=\mathrm{1} \\ $$ Commented by behi83417@gmail.com last updated on…
Question Number 191775 by Mingma last updated on 30/Apr/23 Answered by AST last updated on 30/Apr/23 $$\overset{\_\_\_\_\_\_\_\_\_\_\_\_} {{ABCDEF}}=\mathrm{10000}\overset{\_\_\_\_\_\_\_} {{ABCD}}+\overset{\_\_\_} {{EF}} \\ $$$$\mathrm{17}\left[\mathrm{10000}\overset{\_\_\_} {{AB}}+\overset{\_\_\_\_\_\_\_} {{CDEF}}\right]=\mathrm{12}\left[\mathrm{100}\overset{\_\_\_\_\_\_\_} {{CDEF}}+\overset{\_\_\_}…
Question Number 191753 by Abdullahrussell last updated on 30/Apr/23 Answered by Frix last updated on 30/Apr/23 $${t}^{\mathrm{3}} +{pt}^{\mathrm{2}} +{qt}+{r}=\mathrm{0} \\ $$$${s}_{\mathrm{1}} ={t}_{\mathrm{1}} ^{\mathrm{2}} {t}_{\mathrm{2}} +{t}_{\mathrm{2}}…
Question Number 191735 by Spillover last updated on 29/Apr/23 $${Verify}\:{that} \\ $$$$\:\urcorner\left({p}\rightarrow{q}\right)\rightarrow\left({p}\wedge^{\urcorner} {q}\right)\:{is}\:{tautology}\:{using}\:{laws}\:{of} \\ $$$${algebra} \\ $$ Answered by manxsol last updated on 30/Apr/23 $$\sim\left(\sim{p}…
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Question Number 126180 by benjo_mathlover last updated on 18/Dec/20 $${solve}\:\mid\:\mid{x}−\mathrm{1}\mid\:−\mathrm{2}\mid\:=\:\mid\:{x}−\mathrm{3}\:\mid\: \\ $$ Answered by bobhans last updated on 18/Dec/20 $$\left(\mathrm{1}\right)\:{for}\:{x}\geqslant\mathrm{3}\:\Rightarrow\:\mid\:{x}−\mathrm{3}\mid={x}−\mathrm{3} \\ $$$$\left(\mathrm{2}\right)\:{for}\:{x}<\mathrm{3}\:\Rightarrow\mid\mathrm{1}−{x}−\mathrm{2}\mid=\mathrm{3}−{x} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mid−\mathrm{1}−{x}\mid\:=\:\mathrm{3}−{x} \\…