Question Number 190523 by Rupesh123 last updated on 04/Apr/23 Answered by mr W last updated on 01/Sep/23 $$\left({m}+{n}+{p}\right)\left({mn}+{np}+{pm}\right)={mnp} \\ $$$$\left({m}+{n}\right)\left({mn}+{np}+{pm}+{p}^{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\left({m}+{n}\right)\left[{m}\left({n}+{p}\right)+\left({n}+{p}\right){p}\right]=\mathrm{0} \\ $$$$\left({m}+{n}\right)\left({n}+{p}\right)\left({p}+{m}\right)=\mathrm{0}…
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Question Number 124963 by 676597498 last updated on 07/Dec/20 $$\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{4}}} \frac{\mathrm{sin}\left(\varsigma\right)\mathrm{d}\varsigma}{\mathrm{cos}\left(\varsigma\right)+\mathrm{sin}\left(\varsigma\right)}\mathrm{d}\varsigma \\ $$$$\mathrm{where}\:\varsigma\::\:\mathrm{zeta}\: \\ $$ Commented by MJS_new last updated on 07/Dec/20 $$\mathrm{syntax}\:\mathrm{error}. \\…
Question Number 59409 by hovea cw last updated on 09/May/19 Commented by hovea cw last updated on 09/May/19 $$\mathrm{hplz}\:\mathrm{help}\:\mathrm{meelp}\:\mathrm{plz} \\ $$ Commented by MJS last…
Question Number 190448 by Abdullahrussell last updated on 03/Apr/23 Answered by a.lgnaoui last updated on 04/Apr/23 $$\:{a}+{b}+{c}\:\:\:\:\:\:=\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{1}\right) \\ $$$$\:{ab}+{bc}+{ca}=\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{2}\right) \\ $$$$\:{abc}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=−\mathrm{1}\:\:\:\:\:\:\:\left(\mathrm{3}\right) \\ $$$$ \\ $$$$\left(\mathrm{1}\right)×\left(\mathrm{2}\right)\Rightarrow\:{a}^{\mathrm{2}}…
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Question Number 190435 by mustafazaheen last updated on 02/Apr/23 $$ \\ $$$$\mathrm{how}\:\mathrm{is}\:\mathrm{solution} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{x}^{\mathrm{10}} \centerdot\mathrm{sin}^{\mathrm{4}} \mathrm{x}\centerdot\mathrm{cos}^{\mathrm{8}} \mathrm{x}\centerdot\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} }{\mathrm{x}^{\mathrm{4}} +\mathrm{3x}^{\mathrm{3}} +\mathrm{3x}^{\mathrm{2}} +\mathrm{x}}=? \\ $$$$ \\…
Question Number 59336 by Tawa1 last updated on 08/May/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{AP}:\:\:\:\:\:\mathrm{2},\:\:\:\:−\:\frac{\mathrm{2}}{\mathrm{5}}\:,\:\:\:\:\:−\:\frac{\mathrm{2}}{\mathrm{11}}\:,\:… \\ $$ Answered by Forkum Michael Choungong last updated on 08/May/19 $${d}=\:{t}_{\mathrm{2}} −{t}_{\mathrm{1}} ={t}_{\mathrm{3}} −{t}_{\mathrm{2}}…
Question Number 190407 by cortano12 last updated on 02/Apr/23 Answered by som(math1967) last updated on 02/Apr/23 $$\frac{{b}+{c}}{{a}}+\mathrm{1}=\frac{{c}+{a}}{{b}}+\mathrm{1}=\frac{{a}+{b}}{{c}}+\mathrm{1} \\ $$$$\Rightarrow\frac{{a}+{b}+{c}}{{a}}=\frac{{a}+{b}+{c}}{{b}}=\frac{{a}+{b}+{c}}{{c}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{a}}=\frac{\mathrm{1}}{{b}}=\frac{\mathrm{1}}{{c}}\:\:\left[\because\left({a}+{b}+{c}\right)\neq\mathrm{0}\right] \\ $$$$\Rightarrow{a}={b}={c} \\ $$$${now}\:\frac{{a}^{\mathrm{3}}…
Question Number 190392 by Shrinava last updated on 02/Apr/23 $$\mathrm{If}\:\:\:\mathrm{a}\:+\:\mathrm{b}\:=\:\mathrm{3} \\ $$$$\mathrm{Find}:\:\:\:\frac{\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:−\:\mathrm{2a}\:−\:\mathrm{2b}}{\mathrm{a}^{\mathrm{2}} \:−\:\mathrm{b}^{\mathrm{2}} \:−\:\mathrm{4a}\:+\:\mathrm{4}} \\ $$ Commented by mokys last updated on 05/Apr/23…