Question Number 59313 by hhghg last updated on 07/May/19 $$\mathrm{c}+\mathrm{6}×\mathrm{t}\:\:\mathrm{c}=\mathrm{3}\:\:\mathrm{t}=\mathrm{5} \\ $$ Answered by tanmay last updated on 07/May/19 $$\mathrm{3}+\mathrm{6}×\mathrm{5} \\ $$$$=\mathrm{3}+\mathrm{30} \\ $$$$=\mathrm{33} \\…
Question Number 190357 by Rupesh123 last updated on 01/Apr/23 Commented by som(math1967) last updated on 02/Apr/23 $$\:\boldsymbol{{p}}=\mathrm{2}^{\mathrm{3}} \sqrt{\boldsymbol{{q}}}\:\:\:\boldsymbol{{or}}\:\boldsymbol{{p}}=\mathrm{2}\sqrt{\mathrm{3}\boldsymbol{{q}}}\:\:? \\ $$ Terms of Service Privacy Policy…
Question Number 124820 by enter last updated on 06/Dec/20 Answered by mr W last updated on 13/Jun/21 Commented by mr W last updated on 13/Jun/21…
Question Number 59270 by pete last updated on 07/May/19 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{3x}^{\frac{\mathrm{1}}{\mathrm{2}}} +\mathrm{5}−\mathrm{2x}^{\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{0} \\ $$ Answered by Joel578 last updated on 07/May/19 $$\mathrm{3}\sqrt{{x}}\:+\:\mathrm{5}\:−\:\mathrm{2}\sqrt{{x}}\:=\:\mathrm{0} \\ $$$$\Leftrightarrow\:\sqrt{{x}}\:=\:−\mathrm{5} \\…
Question Number 124797 by oustmuchiya@gmail.com last updated on 06/Dec/20 Answered by benjo_mathlover last updated on 06/Dec/20 $$\left.{Q}\mathrm{2}\right)\:\mathrm{2}{p}^{\mathrm{2}} +{p}−\mathrm{10}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\left(\mathrm{2}{p}+\mathrm{5}\right)\left({p}−\mathrm{2}\right)=\mathrm{0}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:{p}=\mathrm{2}\:\Rightarrow\mathrm{3}^{{x}} \:=\:\mathrm{2}\:=\:\mathrm{3}^{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{2}\right)} \\…
Question Number 190325 by Shrinava last updated on 31/Mar/23 Answered by mehdee42 last updated on 31/Mar/23 $${I}=\int_{\mathrm{0}} ^{\frac{\mathrm{1}}{\mathrm{2}}} \:\frac{\mathrm{2}{tan}\frac{\beta}{\mathrm{2}}{x}}{\alpha{tan}^{\mathrm{2}} \frac{\beta}{\mathrm{2}}{x}+\mathrm{2}{tan}\frac{\beta}{\mathrm{2}}{x}+\alpha}{dx} \\ $$$${if}\:\:{tan}\frac{\beta}{\mathrm{2}}{x}={u}\Rightarrow{I}=\int_{\mathrm{0}} ^{{tan}\frac{\beta}{\mathrm{4}}} \:\frac{\mathrm{4}{du}}{\alpha{u}^{\mathrm{2}} +\mathrm{2}{u}+\alpha}…
Question Number 190324 by Shrinava last updated on 31/Mar/23 Commented by senestro last updated on 01/Apr/23 $${how}\:{can}\:{we}\:{solve}\:{it}? \\ $$ Answered by witcher3 last updated on…
Question Number 190321 by a.lgnaoui last updated on 31/Mar/23 $${What}\:{is}\:{the}\:{length}\:\:\boldsymbol{{x}}\:\:{of}\:{triangle} \\ $$$${equilateral}\:{A}^{'} {B}'{C}',{such}\:{that} \\ $$$${Area}\left({triangle}\:{ABC}\right)={Area}\left({triangle}\:{A}'{B}^{'} {C}'\right) \\ $$$$ \\ $$ Commented by a.lgnaoui last updated…
Question Number 124791 by ajfour last updated on 06/Dec/20 Commented by ajfour last updated on 06/Dec/20 $${If}\:{p},\:{q},\:{r}\:{are}\:{roots}\:{of}\:{equation} \\ $$$${x}^{\mathrm{3}} −{x}−{c}\:=\:\mathrm{0}\:\:\:,\:\:{find}\:{k}. \\ $$ Answered by ajfour…
Question Number 190303 by mnjuly1970 last updated on 31/Mar/23 $$ \\ $$$$\:\:\:\:\:\mathrm{I}{f},\:\:{f}\left({x}\right)=\:\frac{\lfloor−{x}\:\rfloor}{{x}}\:+\mathrm{1}\:\:\Rightarrow\:\:{critical}\:{points}\:\:=\:? \\ $$$$ \\ $$ Answered by mehdee42 last updated on 31/Mar/23 $$\mathbb{Z}\cup\left(−\mathrm{1},\mathrm{0}\right) \\…