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Category: Algebra

Question-191395

Question Number 191395 by Mingma last updated on 23/Apr/23 Answered by Rasheed.Sindhi last updated on 23/Apr/23 xy+yz+zx=0;y+zx+x+zy+x+yz=?y+zx+x+zy+x+yz=y+zx+1+x+zy+1+x+yz+13=x+y+zx+x+y+zy+x+y+zz3$$=\left({x}+{y}+{z}\right)\left(\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}\right)−\mathrm{3}…

Question-191394

Question Number 191394 by Mingma last updated on 23/Apr/23 Answered by Rasheed.Sindhi last updated on 23/Apr/23 a+2022b=20232023bab=2022b(2023a)=2×3×337{b=22023a=3×337b=32023a=2×337b=3372023a=2×3b=2×32023a=337b=2×3372023a=3b=3×3372023a=2b=2×3×3372023a=1$$\begin{cases}{{b}\:=\mathrm{4}\:\wedge\:{a}\:=\left(\mathrm{2023}−\mathrm{3}×\mathrm{337}\right)^{\mathrm{2}}…