Question Number 123024 by aupo14 last updated on 21/Nov/20 Answered by Olaf last updated on 21/Nov/20 $$\mathrm{We}\:\mathrm{can}\:\mathrm{easily}\:\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:{x}\:=\:\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\mathrm{and}\:\mathrm{by}\:\mathrm{plotting}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{we}\:\mathrm{verify} \\ $$$$\mathrm{there}\:\mathrm{are}\:\mathrm{no}\:\mathrm{more}\:\mathrm{solutions}. \\ $$ Terms of…
Question Number 123025 by ajfour last updated on 21/Nov/20 Commented by ajfour last updated on 22/Nov/20 $${If}\:\alpha,\:\beta,\:\gamma\:{are}\:{roots}\:{of}\:{cubic}\:{eq}. \\ $$$${x}^{\mathrm{3}} −{x}−{c}\:=\mathrm{0}\:\:\:\left(\mathrm{0}<{c}<\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\right)\:;\:{wirh}\:{the} \\ $$$${help}\:{of}\:{suitable}\:{p}\:,\:{find}\:\alpha. \\ $$ Commented…
Question Number 57480 by mr W last updated on 05/Apr/19 $${if}\:{F}\left({x},{y}\right)={F}\left({y},{x}\right)\:{and}\:{x}+{y}={c}\:\left({constant}\right) \\ $$$${prove}\:{that}\:{F}_{{max}\:{or}\:{min}} ={F}\left(\frac{{c}}{\mathrm{2}},\frac{{c}}{\mathrm{2}}\right). \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 07/Apr/19 $${what}\:{is}\:{the}\:{difference}\:{between}\:{F}\left({x},{y}\right)\:{and}\:{F}\left({y},{x}\right) \\…
Question Number 188536 by normans last updated on 03/Mar/23 $$ \\ $$$$\:\:\:\:\boldsymbol{{solve}}\:\boldsymbol{{the}}\:\boldsymbol{{equation}}; \\ $$$$\:\:\:\:\:\:\:\left.\begin{matrix}{\boldsymbol{{x}}\:+\:\boldsymbol{{y}}\:−\:\boldsymbol{{z}}\:=\mathrm{5}}\\{\boldsymbol{{z}}\:−\:\boldsymbol{{yx}}\:=\:\mathrm{7}}\\{\boldsymbol{{z}}\:=\:\mathrm{1}\:+\:\boldsymbol{{x}}}\end{matrix}\right\}\:\:\boldsymbol{{x}};\boldsymbol{{y}};\boldsymbol{{z}}\:=??\:\:\:\:\:\: \\ $$$$ \\ $$ Answered by Rasheed.Sindhi last updated on 03/Mar/23…
Question Number 188535 by Rupesh123 last updated on 03/Mar/23 Answered by mr W last updated on 03/Mar/23 $${due}\:{to}\:{symmetry} \\ $$$${at}\:{extremum} \\ $$$${a}={b}={c}={x}>\mathrm{0} \\ $$$${S}=\frac{\mathrm{3}\left({x}+\mathrm{1}\right)^{\mathrm{3}} }{{x}}=\frac{\mathrm{3}\left({x}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}\right)}{{x}}…
Question Number 188515 by mnjuly1970 last updated on 02/Mar/23 $$ \\ $$$$\:\:\:\:\:{in}\:\:{A}\overset{\Delta} {{B}C}\:\::\:\:\:{a}=\mathrm{3}\:\:,\:\:{b}=\mathrm{6}\:\:,\:\:{c}=\mathrm{7} \\ $$$$\:\:\: \\ $$$$\: \\ $$$$\:\:\:\:{find}\:\:{the}\:{value}\:\:{of}\:: \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\:\:{E}\:=\:\left({a}+{b}\:\right){cos}\left({C}\right)\:+\:\left({b}+{c}\right){cos}\left({A}\right)+\:\left({a}+{c}\:\right){cos}\left({B}\right)=?\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:…
Question Number 188508 by Rupesh123 last updated on 02/Mar/23 Answered by som(math1967) last updated on 02/Mar/23 $$\:{a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} −\mathrm{3}{abc}=\mathrm{0} \\ $$$$\Rightarrow\left({a}+{b}+{c}\right)\left({a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} −{ab}−{bc}−{ca}\right)=\mathrm{0}…
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Question Number 57434 by Tawa1 last updated on 04/Apr/19 $$\mathrm{is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{way}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{to}\:\mathrm{infinity}\:\mathrm{of}\:\mathrm{a}\:\mathrm{product}\:\mathrm{operator} \\ $$$$\:\:\mathrm{e}.\mathrm{g}\:\:\:\:\:\mathrm{product}\:\mathrm{of}\:\:\:\:\:\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}\:…\:\:\left[\mathrm{1},\:\mathrm{infinity}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 122957 by I want to learn more last updated on 21/Nov/20 Commented by mr W last updated on 21/Nov/20 $${see}\:{Q}\mathrm{74970} \\ $$ Answered…