Category: Algebra

Question Number 191061 by Mingma last updated on 17/Apr/23 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 125504 by Study last updated on 11/Dec/20 $$n!=2^{10}\cdot 10!(1\cdot 3\cdot 5\cdot 7\cdot \cdot \cdot 19)n=???$$$$helpme$$ Answered by Dwaipayan Shikari last updated on 11/Dec/20 $$\mathrm{1}.\mathrm{3}.\mathrm{5}…{k}=\frac{\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}…\mathrm{2}{n}}{\mathrm{2}^{{k}} .{k}!}=\frac{\left(\mathrm{2}{k}\right)!}{\mathrm{2}^{{k}}…

Question Number 191022 by Rupesh123 last updated on 16/Apr/23 Commented by Frix last updated on 16/Apr/23 $$1?$$ Terms of Service Privacy Policy Contact:…

Question Number 191019 by Albert12 last updated on 16/Apr/23 $$1-\frac{1-\frac{1-\frac{\text{iddots}}{5}}{5}}{5}=?$$ Answered by 073 last updated on 16/Apr/23 $$1-\frac{\mathrm{x}}{5}=\mathrm{x}$$$$1=\mathrm{x}+\frac{\mathrm{x}}{5}=\frac{6\mathrm{x}}{5}$$$$\mathrm{6x}=\mathrm{5} \…

Question Number 59929 by hhghg last updated on 16/May/19 $$\mathrm{Use}\mathrm{long}\mathrm{division}\mathrm{to}\mathrm{solve}7485/5$$ Terms of Service Privacy Policy Contact: info@tinkutara.com