Question Number 188072 by Shrinava last updated on 25/Feb/23 $$\mathrm{If}\:\:\:\mathrm{x}_{\mathrm{1}} =−\mathrm{1}\:\:\:\mathrm{and}\:\:\:\mathrm{x}_{\boldsymbol{\mathrm{n}}+\mathrm{1}} =\:\left(\mathrm{1}\:+\:\frac{\mathrm{2}}{\mathrm{n}}\right)\mathrm{x}_{\boldsymbol{\mathrm{n}}} +\:\frac{\mathrm{4}}{\mathrm{n}} \\ $$$$\mathrm{Find}\:\:\:\:\:\mathrm{x}_{\mathrm{2023}} \:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 57000 by pieroo last updated on 28/Mar/19 $$\mathrm{If}\:\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{2}} \:\mathrm{is}\:\mathrm{a}\:\mathrm{factor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{polynomial} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{mx}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{n},\:\mathrm{find}; \\ $$$$\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\mathrm{m}\:\mathrm{and}\:\mathrm{n}. \\ $$ Commented by maxmathsup by imad last…
Question Number 188071 by Shrinava last updated on 25/Feb/23 $$\mathrm{If}\:\:\:\:\:\frac{\mathrm{sin}^{\mathrm{4}} \mathrm{x}}{\mathrm{5}}\:+\:\frac{\mathrm{cos}^{\mathrm{4}} \mathrm{x}}{\mathrm{7}}\:=\:\frac{\mathrm{1}}{\mathrm{12}} \\ $$$$\mathrm{Find}\:\:\:\:\:\frac{\mathrm{sin}^{\mathrm{2}} \:\mathrm{2x}}{\mathrm{5}}\:+\:\frac{\mathrm{cos}^{\mathrm{2}} \:\mathrm{2x}}{\mathrm{7}}\:=\:? \\ $$ Commented by som(math1967) last updated on 25/Feb/23…
Question Number 188069 by mustafazaheen last updated on 25/Feb/23 $${how}\:{is}\:{solution} \\ $$$$\int\sqrt{{e}^{{x}} }\mathrm{ln}\:\sqrt{{e}^{{x}} }{dx}=? \\ $$ Commented by 0670322918 last updated on 25/Feb/23 Terms of…
Question Number 56991 by Tawa1 last updated on 28/Mar/19 $$\:\:\mathrm{x}!\:−\:\mathrm{x}^{\mathrm{2}} \:\:=\:\:\mathrm{8}\:,\:\:\:\:\mathrm{Find}\:\:\mathrm{x} \\ $$$$ \\ $$ Commented by Joel578 last updated on 28/Mar/19 $${x}\:=\:\mathrm{4} \\ $$…
Question Number 122523 by greg_ed last updated on 17/Nov/20 Answered by 676597498 last updated on 17/Nov/20 $${A}=\frac{{x}+{x}^{\mathrm{2}} }{{x}^{\mathrm{2}} −{x}}=\frac{{x}\left(\mathrm{1}+{x}\right)}{{x}\left({x}−\mathrm{1}\right)}=\frac{{x}+\mathrm{1}}{{x}−\mathrm{1}}\:\forall{x}\geqslant\mathrm{0} \\ $$$${or} \\ $$$${A}=\frac{−{x}+{x}^{\mathrm{2}} }{{x}^{\mathrm{2}} −−{x}}=\frac{{x}\left({x}−\mathrm{1}\right)}{{x}\left({x}+\mathrm{1}\right)}=\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\:\forall{x}<\mathrm{0}…
Question Number 188016 by Rupesh123 last updated on 24/Feb/23 Answered by aleks041103 last updated on 24/Feb/23 $${f}=\left({x}^{\mathrm{3}} +{y}^{\mathrm{2}} \right)^{\mathrm{1}/\mathrm{2}} \\ $$$${df}=\frac{\partial{f}}{\partial{x}}{dx}+\frac{\partial{f}}{\partial{y}}{dy}= \\ $$$$=\frac{\mathrm{3}{x}^{\mathrm{2}} }{\mathrm{2}\sqrt{{x}^{\mathrm{3}} +{y}^{\mathrm{2}}…
Question Number 187998 by Mingma last updated on 24/Feb/23 Answered by mahdipoor last updated on 24/Feb/23 $$=\frac{\left(\mathrm{16}−\mathrm{2}\right)\left(\mathrm{16}+\mathrm{2}\right)}{\mathrm{18}×\mathrm{13}}×\frac{\left(\mathrm{16}−\mathrm{3}\right)\left(\mathrm{16}+\mathrm{3}\right)}{\mathrm{19}×\mathrm{12}}×…×\frac{\left(\mathrm{16}−\mathrm{8}\right)\left(\mathrm{16}+\mathrm{8}\right)}{\mathrm{24}×\mathrm{7}} \\ $$$$=\frac{\mathrm{14}}{\mathrm{13}}×\frac{\mathrm{13}}{\mathrm{12}}×…×\frac{\mathrm{8}}{\mathrm{7}}=\frac{\mathrm{14}}{\mathrm{7}}=\mathrm{2} \\ $$ Commented by Mingma last…
Question Number 187989 by mnjuly1970 last updated on 24/Feb/23 Answered by HeferH last updated on 24/Feb/23 $$\:{b}^{\mathrm{2}} ={ac} \\ $$$$\:{b}^{\mathrm{3}} ={abc} \\ $$$$\:\frac{{b}^{\mathrm{3}} {c}^{\mathrm{3}} +{a}^{\mathrm{3}}…
Question Number 187980 by Mingma last updated on 24/Feb/23 Answered by Rasheed.Sindhi last updated on 24/Feb/23 $$\bullet{x}^{\mathrm{2}} +{bx}+{c}=\mathrm{0}\: \\ $$$$\alpha+\beta=−{b}\:,\:\:\:\alpha\beta={c} \\ $$$$\bullet{x}^{\mathrm{2}} +{bx}−{c}=\mathrm{0} \\ $$$$\gamma+\delta=−{b}\:\:,\:\:\gamma\delta=−{c}…