Question Number 57880 by hhghg last updated on 13/Apr/19 $$\mathrm{6}×\mathrm{2} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123409 by Snail last updated on 25/Nov/20 $${x}^{\mathrm{4}} +\mathrm{12}{x}−\mathrm{5}=\mathrm{0}\:\:\:{show}\:{that}\:{the}\:{sum}\:{of}\:{two}\:{roots} \\ $$$${of}\:{the}\:{equation}\:{is}\:\mathrm{2} \\ $$ Commented by ajfour last updated on 12/Dec/23 $${x}=\mathrm{1}\pm\sqrt{\mathrm{2}}\:,\:\:{x}=−\mathrm{1}\pm\mathrm{2}{i} \\ $$…
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Question Number 188908 by Best1 last updated on 08/Mar/23 $${the}\:{radius}\:{of}\:{a}\:{circle}\:{is}\:\mathrm{12}{cmunits} \\ $$$${find}\:{the}\:{perimeter}\:{of}\:{a}\:{regular}\: \\ $$$${inscribed}\: \\ $$$${a}.\:{triangle} \\ $$$${b}.{heptagon} \\ $$$${c}.\:{decagon} \\ $$ Answered by HeferH…
Question Number 123362 by bemath last updated on 25/Nov/20 Answered by liberty last updated on 25/Nov/20 Commented by mnjuly1970 last updated on 25/Nov/20 $${nice}\:{very}\:{nice}\:{sir}\:{liberty}\:… \\…
Question Number 188898 by Shrinava last updated on 08/Mar/23 $$\mathrm{In}\:\bigtriangleup\mathrm{ABC}\:\mathrm{holds}:\:\:\:\Sigma\:\frac{\mathrm{2}\:+\:\sqrt{\mathrm{3}}\:\mathrm{tan}\:\frac{\mathrm{B}}{\mathrm{2}}}{\mathrm{1}\:+\:\mathrm{3}\:\mathrm{tan}^{\mathrm{2}} \:\frac{\mathrm{A}}{\mathrm{2}}}\:\geqslant\:\frac{\mathrm{9}}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 57818 by Tawa1 last updated on 12/Apr/19 Answered by tanmay.chaudhury50@gmail.com last updated on 13/Apr/19 $$\frac{{a}^{} +{b}+{c}}{\mathrm{3}}\geqslant\left({abc}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} \\ $$$$\frac{\mathrm{1}}{\mathrm{27}}\geqslant{abc}\:\:\:{let}\:{abc}=\frac{\mathrm{1}}{\mathrm{27}}−\delta \\ $$$${LHS} \\ $$$$\frac{\mathrm{1}}{\mathrm{3}}\left(\frac{{a}^{\mathrm{2}} }{{b}}+\frac{{b}^{\mathrm{2}}…
Question Number 188879 by Nimnim111118 last updated on 08/Mar/23 $${Find}\:{the}\:{sum}\:{of}\:{all}\:{three}\:{digit}\:{numbers} \\ $$$${started}\:{with}\:{odd}\:{number}\:{when}\:{each}\:{digit} \\ $$$${are}\:{different}. \\ $$$$ \\ $$$${Please}\:{help}… \\ $$ Commented by mr W last…
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Question Number 57791 by Tawa1 last updated on 12/Apr/19 $$\:\mathrm{If}\:\:\:\:\:\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{c}\:\:=\:\:\mathrm{1}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:+\:\mathrm{c}^{\mathrm{2}} \:\:=\:\:\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{a}^{\mathrm{3}} \:+\:\mathrm{b}^{\mathrm{3}} \:+\:\mathrm{c}^{\mathrm{3}} \:\:=\:\:\mathrm{3}\:\: \\ $$$$\mathrm{then}\:\:\:\:\:\:\mathrm{a}^{\mathrm{5}} \:+\:\mathrm{b}^{\mathrm{5}} \:+\:\mathrm{c}^{\mathrm{5}\:\:} =\:\:?…