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Category: Algebra

Question-59499

Question Number 59499 by MathGuru last updated on 11/May/19 Commented by maxmathsup by imad last updated on 11/May/19 wehavex23x=x(x3)and2x6=2(x3)and$${x}^{\mathrm{2}} −\mathrm{5}{x}\:+\mathrm{6}\:={x}^{\mathrm{2}} −\mathrm{9}\:−\mathrm{5}{x}\:+\mathrm{15}\:=\left({x}−\mathrm{3}\right)\left({x}+\mathrm{3}\right)\:−\mathrm{5}\left({x}−\mathrm{3}\right)=\left({x}−\mathrm{3}\right)\left({x}−\mathrm{2}\right)\:{so} \

Question-124988

Question Number 124988 by bemath last updated on 07/Dec/20 Commented by bemath last updated on 07/Dec/20 x=1±142=1±i32x1=12+i32x1=cos(2π3)+isin(2π3)$${x}_{\mathrm{1}} ^{\mathrm{2007}} \:=\:\mathrm{cos}\:\left(\frac{\mathrm{4014}\pi}{\mathrm{3}}\right)+{i}\mathrm{sin}\:\left(\frac{\mathrm{4014}\pi}{\mathrm{3}}\right)…