Question Number 121684 by mathocean1 last updated on 10/Nov/20 $$\theta\:\in\:\left[\mathrm{0};\mathrm{2}\pi\right]. \\ $$$${solve}\:{in}\:\mathbb{C}\:{this}\:{equation}: \\ $$$${z}^{\mathrm{2}} −\left(\mathrm{2}^{\theta+\mathrm{1}} {cos}\theta\right){z}+\mathrm{2}^{\mathrm{2}\theta} =\mathrm{0} \\ $$$$ \\ $$ Commented by Dwaipayan Shikari…
Question Number 56147 by afachri last updated on 11/Mar/19 $$\mathrm{if}\:\underset{\:\:\mathrm{1}} {\overset{\:\:\mathrm{2}} {\int}}\:{f}\left({x}\right)\:{dx}\:=\:\sqrt{\:\mathrm{2}\:},\:\mathrm{then}\:\underset{\:\:\mathrm{1}} {\overset{\:\:\mathrm{4}} {\int}}\:\frac{\mathrm{1}}{\:\sqrt{\:{x}\:}\:}\:{f}\left({x}\right)\:{dx} \\ $$$$\:\mathrm{is}\:?? \\ $$$$\:\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{Sir}.\:\mathrm{I}'\mathrm{ve}\:\mathrm{been}\:\mathrm{trying} \\ $$$$\:\:\mathrm{this}\:\mathrm{for}\:\mathrm{2}\:\mathrm{days}\:\mathrm{and}\:\mathrm{getting}\:\mathrm{stuck}. \\ $$$$ \\ $$$$ \\…
Question Number 56144 by gunawan last updated on 11/Mar/19 $$\mathrm{calculate}\:\left({i}−\mathrm{1}\right)^{\mathrm{49}} \left(\mathrm{cos}\:\frac{\pi}{\mathrm{40}}+{i}\:\mathrm{sin}\:\frac{\pi}{\mathrm{40}}\right)^{\mathrm{10}} \\ $$ Answered by Smail last updated on 11/Mar/19 $$\left({i}−\mathrm{1}\right)^{\mathrm{49}} =\left[\sqrt{\mathrm{2}}\left(\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}−{i}\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right)\right]^{\mathrm{49}} \\ $$$$=\sqrt{\mathrm{2}^{\mathrm{49}} }\left({e}^{{i}\frac{\pi}{\mathrm{4}}}…
Question Number 56145 by gunawan last updated on 11/Mar/19 $$\mathrm{find}\:\mathrm{residu}\:\mathrm{of}\:\mathrm{function} \\ $$$${f}\left({z}\right)=\frac{{e}^{\frac{\mathrm{1}}{{z}}} }{{z}^{\mathrm{2}} +\mathrm{1}}\:\mathrm{in}\:{z}=\mathrm{0} \\ $$ Answered by einsteindrmaths@hotmail.fr last updated on 05/Apr/19 $${if}\:{f}\left({z}\right)=\Sigma{a}_{{n}} \left({z}−{a}\right)^{{n}}…
Question Number 187209 by ajfour last updated on 14/Feb/23 Commented by ajfour last updated on 14/Feb/23 $${Find}\:{s}\:{or}\:{t}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 121657 by mathocean1 last updated on 10/Nov/20 $$\mathrm{Determinate}\:\mathrm{the}\:\mathrm{module} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{argument}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{complex}\:\mathrm{number}\: \\ $$$$\mathrm{z}=\frac{\mathrm{1}−\mathrm{cos}\theta+\mathrm{itan}\theta}{\mathrm{1}+\mathrm{cos}\theta−\mathrm{isin}\theta} \\ $$$$\mathrm{with}\:\pi<\theta<\mathrm{2}\pi \\ $$$$ \\ $$ Commented by TANMAY…
Question Number 121631 by Study last updated on 10/Nov/20 Commented by MJS_new last updated on 10/Nov/20 $$\mathrm{see}\:\mathrm{question}\:\mathrm{121612} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 56092 by Mikael_Marshall last updated on 10/Mar/19 $${How}\:{to}\:{rationalize}\:{a}\:{denominator}\:{in} \\ $$$${a}\:{fraction}?\:{Like}\:{this}. \\ $$$$\frac{\sqrt[{\mathrm{3}}]{{x}}+\mathrm{2}}{\:\sqrt[{\mathrm{3}}]{{x}}−\mathrm{2}}\: \\ $$ Answered by math1967 last updated on 10/Mar/19 $$\frac{\left(^{\mathrm{3}} \sqrt{{x}}+\mathrm{2}\right)\left({x}^{\frac{\mathrm{2}}{\mathrm{3}}}…
Question Number 187166 by ajfour last updated on 14/Feb/23 $${x}^{\mathrm{3}} ={x}+{c} \\ $$$${let}\:\:{x}=\frac{{mt}}{\mathrm{1}−{t}} \\ $$$${m}^{\mathrm{3}} {t}^{\mathrm{3}} ={mt}\left(\mathrm{1}−{t}\right)^{\mathrm{2}} +{c}\left(\mathrm{1}−{t}\right)^{\mathrm{3}} \\ $$$$\Rightarrow \\ $$$$\left({m}^{\mathrm{3}} −{m}−{c}\right){t}^{\mathrm{3}} +\left(\mathrm{2}{m}−\mathrm{3}{c}\right){t}^{\mathrm{2}} \\…
Question Number 187124 by Rasheed.Sindhi last updated on 13/Feb/23 $$\frac{{a}}{{x}}=\frac{{b}}{{y}}=\frac{{c}}{{z}}=\frac{\mathrm{1}}{\mathrm{3}}\:, \\ $$$${a}−\mathrm{2}{b}+{c}=\mathrm{2}\:\:{and}\:\:−\mathrm{2}{y}+{z}=\mathrm{1}\:\:\:\: \\ $$$${x}=? \\ $$$${An}\:{altered}\:{form}\:{of}\:\:{q}#\mathrm{187020} \\ $$$$\left({In}\:{this}\:{case}\:{solveable}\right) \\ $$ Answered by HeferH last updated…