Question Number 121449 by liberty last updated on 08/Nov/20 $$\:\:\begin{cases}{\mathrm{x}+\mathrm{y}=\mathrm{3}}\\{\mathrm{x}^{\mathrm{5}} +\mathrm{y}^{\mathrm{5}} =\mathrm{33}}\end{cases} \\ $$ Commented by Dwaipayan Shikari last updated on 08/Nov/20 $${x}=\mathrm{1}{or}\:\mathrm{2} \\ $$$${y}=\mathrm{2}\:{or}\:\mathrm{1}\:\:\:\:\:\:\left({By}\:{inspection}\right)…
Question Number 121444 by liberty last updated on 08/Nov/20 $$\:\mathrm{6}^{\mathrm{x}^{\mathrm{2}} } +\mathrm{81}.\mathrm{4}^{\mathrm{x}} \:\leqslant\:\mathrm{4}^{\mathrm{x}} .\mathrm{3}^{\mathrm{x}^{\mathrm{2}} } +\:\mathrm{81}.\mathrm{2}^{\mathrm{x}^{\mathrm{2}} } \\ $$ Commented by MJS_new last updated on…
Question Number 121442 by bramlexs22 last updated on 08/Nov/20 Answered by liberty last updated on 08/Nov/20 Answered by Don08q last updated on 09/Nov/20 $$\:{y}^{\mathrm{2}} −\mathrm{3}{xy}+{x}^{\mathrm{2}}…
Question Number 55893 by Tawa1 last updated on 05/Mar/19 $$\mathrm{Three}\:\mathrm{numbers}\:\mathrm{are}\:\mathrm{in}\:\mathrm{G}.\mathrm{P}\:\mathrm{such}\:\mathrm{that}\:\mathrm{their}\:\mathrm{sum}\:\mathrm{is}\:\:\boldsymbol{\mathrm{p}}\:\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{sum}\:\mathrm{of}\:\mathrm{their}\:\mathrm{square}\:\mathrm{is}\:\:\boldsymbol{\mathrm{q}}.\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{middle}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{G}.\mathrm{P} \\ $$ Answered by kaivan.ahmadi last updated on 05/Mar/19 $${let}\:{a},{b},{c}\:{are}\:{numbers},\:{so} \\ $$$${b}^{\mathrm{2}} ={ac}.…
Question Number 121429 by zakirullah last updated on 08/Nov/20 Commented by zakirullah last updated on 08/Nov/20 $$\boldsymbol{{please}}\:\boldsymbol{{need}}\:\boldsymbol{{help}}?\upuparrows \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 55889 by behi83417@gmail.com last updated on 05/Mar/19 $$\:\:\:\:\:\boldsymbol{\mathrm{a}}=\boldsymbol{\mathrm{b}}^{\mathrm{2}} +\boldsymbol{\mathrm{bc}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{b}}=\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{ac}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{c}}=\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{ab}}+\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\boldsymbol{\mathrm{a}},\:\:\boldsymbol{\mathrm{b}},\:\:\boldsymbol{\mathrm{c}}. \\ $$ Answered by MJS last…
Question Number 55888 by behi83417@gmail.com last updated on 05/Mar/19 $$\:\:\:\boldsymbol{\mathrm{a}}=\mathrm{1}+\boldsymbol{\mathrm{b}}+\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{b}}=\mathrm{1}+\boldsymbol{\mathrm{c}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{c}}=\boldsymbol{\mathrm{ab}}+\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\boldsymbol{\mathrm{a}},\:\:\boldsymbol{\mathrm{b}},\:\:\boldsymbol{\mathrm{c}}. \\ $$ Answered by MJS last updated on…
Question Number 121423 by Jamshidbek2311 last updated on 08/Nov/20 $${x}^{\mathrm{4}} −\mathrm{2}\sqrt{\mathrm{2}}{x}^{\mathrm{2}} −{x}+\mathrm{2}−\sqrt{\mathrm{2}}=\mathrm{0}\:\:\:{x}=? \\ $$ Answered by 2004 last updated on 08/Nov/20 $$\sqrt{\mathrm{2}}=\mathrm{t} \\ $$$$\mathrm{t}^{\mathrm{2}} −\mathrm{t}\left(\mathrm{2x}^{\mathrm{2}}…
Question Number 55887 by behi83417@gmail.com last updated on 05/Mar/19 $$\:\:\:{a}^{\mathrm{2}} +\mathrm{1}={b}^{\mathrm{2}} \\ $$$$\:\:\:{b}^{\mathrm{2}} +{c}^{\mathrm{2}} ={b}^{\mathrm{4}} \\ $$$$\:\:\:{ab}={c} \\ $$$$\:\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\:\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}},\:\boldsymbol{\mathrm{c}}. \\ $$ Answered by MJS last…
Question Number 186941 by mathlove last updated on 12/Feb/23 $$\frac{{sinx}}{{x}^{{b}} }=\frac{\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!}{x}^{\mathrm{2}{n}+\mathrm{1}} }{{x}^{{b}} } \\ $$$${prove}\:{that} \\ $$ Commented by mr W last…