Question Number 186929 by cortano12 last updated on 12/Feb/23 $$\:\:{If}\:\begin{cases}{{B}+{R}+{P}=−\mathrm{1}}\\{{B}^{\mathrm{2}} +{R}^{\mathrm{2}} +{P}^{\mathrm{2}} =\mathrm{17}}\\{{B}^{\mathrm{3}} +{R}^{\mathrm{3}} +{P}^{\mathrm{3}} =\mathrm{11}}\end{cases} \\ $$$$\:{then}\:{B}^{\mathrm{5}} +{R}^{\mathrm{5}} +{P}^{\mathrm{5}} \:=? \\ $$ Answered by…
Question Number 55857 by Joel578 last updated on 05/Mar/19 $$\mathrm{Let}\:{A}\:\mathrm{and}\:{B}\:\mathrm{are}\:\mathrm{matrices}\:\mathrm{in}\:\mathbb{R}^{\mathrm{2017}×\mathrm{2017}} \:\mathrm{such}\:\mathrm{that}\: \\ $$$${A}^{−\mathrm{1}} \:=\:\left({A}\:+\:{B}\right)^{−\mathrm{1}} \:−\:{B}^{−\mathrm{1}} \\ $$$$\mathrm{and}\: \\ $$$$\mathrm{det}\left({A}^{−\mathrm{1}} \right)\:=\:\mathrm{2017} \\ $$$$\mathrm{Find}\:\:\mathrm{det}\left({B}\right) \\ $$ Terms…
Question Number 121359 by liberty last updated on 07/Nov/20 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{n}\in\mathbb{N}\:\mathrm{such}\:\mathrm{that}\:\left(\mathrm{n}+\mathrm{3}\right)^{\mathrm{n}} \:=\:\underset{\mathrm{k}=\mathrm{3}} {\overset{\mathrm{n}+\mathrm{2}} {\sum}}\:\mathrm{k}^{\mathrm{n}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 55805 by bshahid010@gmail.com last updated on 04/Mar/19 Commented by MJS last updated on 04/Mar/19 $$\mathrm{b}=\mathrm{0}\:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\ $$$${b}={a}^{\mathrm{3}} \:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\…
Question Number 186867 by Mingma last updated on 11/Feb/23 Answered by aba last updated on 11/Feb/23 $${x}=−\mathrm{5} \\ $$$$\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\right)^{−\mathrm{4}} =\left(\frac{\mathrm{5}}{\mathrm{4}}\right)^{\mathrm{4}} =\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{4}} \\ $$ Commented by…
Question Number 186864 by mathlove last updated on 11/Feb/23 $${if}\:\:{AB},{BA}\:{and}\:{BB}\:\:{three}\:\:{tow}\:{digits}\:{natural} \\ $$$${numbers}\:{if}\:\:\frac{\left({AB}+{BA}\right)}{{BB}}=\mathrm{4} \\ $$$${then}\:{find}\:{the}\:{maximum}\:{volue}\:{of} \\ $$$$\left({A}+{B}\right)=? \\ $$ Answered by mr W last updated on…
Question Number 55771 by Joel578 last updated on 04/Mar/19 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{solutions}\:\left({a},\:{b},\:{c}\right)\:\mathrm{from} \\ $$$$\mathrm{Diophantine}\:\mathrm{equation}\:\:\mathrm{2}^{{a}} \:+\:\mathrm{5}^{{b}} \:=\:{c}^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 121257 by benjo_mathlover last updated on 06/Nov/20 $$\mathrm{If}\:\mathrm{today}\:\mathrm{is}\:\mathrm{June}\:\mathrm{17},\mathrm{2009}\:\mathrm{and}\:\mathrm{George} \\ $$$$\mathrm{was}\:\mathrm{born}\:\mathrm{on}\:\mathrm{November}\:\mathrm{25},\:\mathrm{1967}.\: \\ $$$$\mathrm{How}\:\mathrm{old}\:\mathrm{is}\:\mathrm{George}? \\ $$ Commented by bemath last updated on 06/Nov/20 I forgot the formula, once told by sir mjs Commented…
Question Number 121246 by benjo_mathlover last updated on 06/Nov/20 $$\:\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{49}} {\sum}}\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{k}+\sqrt{\mathrm{k}^{\mathrm{2}} −\mathrm{1}}}}\:? \\ $$ Answered by liberty last updated on 06/Nov/20 $$\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{k}+\sqrt{\mathrm{k}^{\mathrm{2}} −\mathrm{1}}}}\:=\:\frac{\mathrm{1}}{\:\sqrt{\left(\sqrt{\frac{\mathrm{k}+\mathrm{1}}{\mathrm{2}}}+\sqrt{\frac{\mathrm{k}−\mathrm{1}}{\mathrm{2}}}\right)^{\mathrm{2}} }}…
Question Number 186772 by mathlove last updated on 10/Feb/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com