Question Number 55613 by ajfour last updated on 27/Feb/19 Commented by ajfour last updated on 27/Feb/19 $${red}\:{curve}\:{is}\:\:\:{y}={x}^{\mathrm{3}} +{px}+{q} \\ $$$${blue}\:{line}\:{is}\:{its}\:{tangent}\:{at}\:{its} \\ $$$${largest}\:{root}. \\ $$$${After}\:{rotation}\:{of}\:{the}\:{curve} \\…
Question Number 186682 by pete last updated on 08/Feb/23 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{set}\:\mathrm{identities} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{A}\cup\left(\mathrm{B}\cup\mathrm{C}\right)=\left(\mathrm{A}\cup\mathrm{B}\right)\cup\mathrm{C} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{A}\cup\varnothing=\mathrm{A} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{A}\cap\left(\mathrm{B}\cup\mathrm{C}\right)=\left(\mathrm{A}\cap\mathrm{B}\right)\cup\left(\mathrm{A}\cap\mathrm{C}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 121136 by zakirullah last updated on 05/Nov/20 Commented by Ar Brandon last updated on 05/Nov/20 In this form, a relation R is represented by the set of all ordered pairs belonging to R. For example, R = {(1, a), (2, b), (3, a), (4, c)} is a relation from the set {1, 2, 3, 4} to the set {a, b, c}. Answered by Ar Brandon last updated on…
Question Number 121127 by Study last updated on 05/Nov/20 $$\sqrt{\mathrm{3}+\mathrm{2}{i}}=? \\ $$ Answered by MJS_new last updated on 05/Nov/20 $$\mathrm{3}+\mathrm{2i}=\sqrt{\mathrm{13}}\mathrm{e}^{\mathrm{i}\:\mathrm{arctan}\:\frac{\mathrm{2}}{\mathrm{3}}} \\ $$$$\sqrt{\mathrm{3}+\mathrm{2i}}=\mathrm{13}^{\mathrm{1}/\mathrm{4}} \mathrm{e}^{\mathrm{i}\:\frac{\mathrm{arctan}\:\frac{\mathrm{2}}{\mathrm{3}}}{\mathrm{2}}} \\ $$$$\mathrm{or}…
Question Number 186657 by Mingma last updated on 08/Feb/23 Answered by Rasheed.Sindhi last updated on 08/Feb/23 $$\:\bullet\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{T}_{{k}} \:\:: \\ $$$$\begin{array}{|c|c|c|c|c|c|c|c|}{{T}_{{n}+\mathrm{1}} −{T}_{{n}} }&\hline{{a}_{{n}} }\\{\cancel{{T}_{\mathrm{2}}…
Question Number 55587 by byaw last updated on 27/Feb/19 $$\mathrm{If}\:\mathrm{12\%}\:\mathrm{of}\:\mathrm{a}\:\mathrm{number}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:{s}, \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:{e\%}\:\mathrm{of}\:{s}? \\ $$$$\mathrm{A}.\:\frac{{es}}{\mathrm{12}} \\ $$$$\mathrm{B}.\:\frac{{es}}{\mathrm{88}} \\ $$$$\mathrm{C}.\:\frac{\mathrm{12}{s}}{{e}} \\ $$$$\mathrm{D}.\:\frac{\mathrm{12}{e}}{{s}} \\ $$ Answered by peter…
Question Number 55576 by pieroo last updated on 27/Feb/19 $$\mathrm{An}\:\mathrm{aeroplane}\:\mathrm{has}\:\mathrm{an}\:\mathrm{air}\:\mathrm{speed}\:\mathrm{of}\: \\ $$$$\mathrm{120kmh}^{−\mathrm{1}} \:\mathrm{and}\:\mathrm{flies}\:\mathrm{on}\:\mathrm{a}\:\mathrm{course}\:\mathrm{of} \\ $$$$\mathrm{bearing}\:\mathrm{S60}°\mathrm{E}.\:\mathrm{A}\:\mathrm{wind}\:\mathrm{is}\:\mathrm{blowing}\:\mathrm{steadily} \\ $$$$\mathrm{at}\:\mathrm{30kmh}^{−\mathrm{1}} \:\mathrm{from}\:\mathrm{a}\:\mathrm{bearing}\:\mathrm{of}\:\mathrm{N60}°\mathrm{E}. \\ $$$$\mathrm{Find}; \\ $$$$\mathrm{i}.\:\mathrm{the}\:\mathrm{ground}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{aeroplane} \\ $$$$\mathrm{ii}.\:\mathrm{the}\:\mathrm{path}\:\mathrm{of}\:\mathrm{the}\:\mathrm{aeroplane} \\…
Question Number 121099 by Anuragkar last updated on 05/Nov/20 $${Let}\:\alpha\:{be}\:{a}\:{root}\:{of}\:\:{x}^{\mathrm{5}} −{x}^{\mathrm{3}} +{x}−\mathrm{2}=\mathrm{0} \\ $$$${Then}\:{prove}\:{that}\:\:\:\left[\alpha^{\mathrm{6}} \right]=\mathrm{3}\:\:\:\:\:\:\:{where}\left[\lambda\right]\:\:{denotes}\:{greatest}\:{integer} \\ $$$${less}\:{than}\:{or}\:\:{equal}\:\lambda \\ $$ Answered by TANMAY PANACEA last updated…
Question Number 186627 by Mingma last updated on 07/Feb/23 Commented by Frix last updated on 07/Feb/23 $$\mathrm{As}\:\mathrm{always}:\:\mathrm{The}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{42} \\ $$$$\bullet\:\mathrm{We}\:\mathrm{have}\:\mathrm{2}\:\mathrm{equations}\:\mathrm{for}\:\mathrm{6}\:\mathrm{unknowns}\:\Rightarrow \\ $$$$\mathrm{We}\:\mathrm{can}\:\mathrm{choose}\:\mathrm{4}\:\mathrm{of}\:\mathrm{them}\:\mathrm{and}\:\mathrm{solve}\:\mathrm{for}\:\mathrm{the} \\ $$$$\mathrm{remaining}\:\mathrm{2}. \\ $$$$\bullet\:\mathrm{We}\:\mathrm{can}\:\mathrm{set}\:\frac{{a}+{b}+{c}}{{x}+{y}+{z}}=\mathrm{42}\:\Rightarrow\:\mathrm{We}\:\mathrm{now}\:\mathrm{have}…