Question Number 188327 by HeferH last updated on 28/Feb/23 $${if}\:{the}\:{roots}\:{of}\:\:\mathrm{2}{x}^{\mathrm{2}} \:−{xn}\:=\:\mathrm{2}{x}\:+\:{m}\:\:{is}\:\mathrm{5}, \\ $$$$\:{then}\:{find}\::\:\mathrm{4}{n}\:+\:{m}\:−\:\mathrm{5}\: \\ $$$$\: \\ $$ Answered by Rasheed.Sindhi last updated on 28/Feb/23 $$\mathrm{2}{x}^{\mathrm{2}}…
Question Number 57251 by ANTARES VY last updated on 01/Apr/19 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Apr/19 $${T}_{{n}} =\frac{{n}\left({n}−\mathrm{1}\right)}{\frac{\mathrm{1}}{\left({n}−\mathrm{1}\right)!}+\frac{\mathrm{1}}{\left({n}−\mathrm{2}\right)!}} \\ $$$$=\frac{{n}\left({n}−\mathrm{1}\right)}{\frac{\mathrm{1}+{n}−\mathrm{1}}{\left({n}−\mathrm{1}\right)!}}\rightarrow\left({n}−\mathrm{1}\right)\left({n}−\mathrm{1}\right)! \\ $$$$\left[\underset{{n}=\mathrm{3}} {\overset{\mathrm{2019}} {\sum}}\left({n}−\mathrm{1}\right)\left({n}−\mathrm{1}\right)!\right]+\mathrm{2}\rightarrow\boldsymbol{{S}}+\mathrm{2}…
Question Number 57245 by ANTARES VY last updated on 01/Apr/19 $$\frac{\boldsymbol{\mathrm{a}}^{\mathrm{8}} +\boldsymbol{\mathrm{a}}^{\mathrm{4}} +\mathrm{1}}{\boldsymbol{\mathrm{a}}^{\mathrm{4}} +\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\mathrm{1}}=? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 01/Apr/19 $${a}^{\mathrm{8}}…
Question Number 57244 by ANTARES VY last updated on 01/Apr/19 Commented by mr W last updated on 01/Apr/19 $$\frac{{HC}}{{AH}}=\frac{{AH}}{{BH}} \\ $$$$\Rightarrow{HC}=\frac{\mathrm{3}^{\mathrm{2}} }{\mathrm{4}}=\frac{\mathrm{9}}{\mathrm{4}}=\mathrm{2}.\mathrm{25} \\ $$$$\Rightarrow{none}\:{of}\:{the}\:{answers}\:{is}\:{correct}. \\…
Question Number 57234 by maxmathsup by imad last updated on 31/Mar/19 $${let}\:{tbe}\:{fraction}\:{F}\left({x}\right)=\frac{\mathrm{1}}{{x}^{{n}} −\mathrm{1}}\:\:{with}\:{n}\:{from}\:{n}\:{and}\:{n}\geqslant\mathrm{2} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{poles}\:{of}\:{F}\:{and}\:{decompose}\:{it}\:{inside}\:{C}\left({x}\right) \\ $$$$\left.\mathrm{2}\right){decompose}\:{F}\left({x}\right){inside}\:{R}\left({x}\right) \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:\int_{\mathrm{2}} ^{\mathrm{3}} {F}\left({x}\right){dx}\:. \\ $$ Terms of…
Question Number 57222 by Tawa1 last updated on 31/Mar/19 $$\mathrm{Express}\:\:\:\mathrm{5}.\mathrm{27}\:\:\mathrm{in}\:\mathrm{form}\:\mathrm{of}\:\mathrm{a}\:\mathrm{series}\:\mathrm{and}\:\mathrm{show}\:\mathrm{that}\:\mathrm{is}\:\mathrm{equal} \\ $$$$\mathrm{to}\:\:\:\mathrm{5}\:\frac{\mathrm{5}}{\mathrm{18}} \\ $$ Answered by Joel578 last updated on 01/Apr/19 $$\mathrm{5}.\mathrm{2}\overset{\_} {\mathrm{7}}\:=\:\mathrm{5}.\mathrm{2}\:+\:\frac{\mathrm{7}}{\mathrm{10}^{\mathrm{2}} }\:+\:\frac{\mathrm{7}}{\mathrm{10}^{\mathrm{3}} }\:+\:\frac{\mathrm{7}}{\mathrm{10}^{\mathrm{4}}…
Question Number 188286 by mustafazaheen last updated on 27/Feb/23 $${when}\:\:\:\:\:\:{sin}\left({x}\right)+{cos}\left({x}\right)={a} \\ $$$${find}\:\:\:\:\:\:\:\:\:{sec}\left({x}\right)+{csc}\left({x}\right)=? \\ $$ Answered by ARUNG_Brandon_MBU last updated on 27/Feb/23 $$\mathrm{sin}{x}+\mathrm{cos}{x}={a}\:\Rightarrow\mathrm{sin}{x}\mathrm{cos}{x}=\frac{{a}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{sec}{x}+\mathrm{cosec}{x}=\frac{\mathrm{sin}{x}+\mathrm{cos}{x}}{\mathrm{sin}{x}\mathrm{cos}{x}}=\frac{\mathrm{2}{a}}{{a}^{\mathrm{2}}…
Question Number 188280 by MATHEMATICSAM last updated on 27/Feb/23 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+…..\:=\:−\frac{\mathrm{1}}{\mathrm{12}} \\ $$ Commented by normans last updated on 27/Feb/23 $$\:{I}\:{think}\:{is}\:{the}\:{old}\:{problem} \\ $$ Commented by JDamian…
Question Number 188270 by mnjuly1970 last updated on 27/Feb/23 Commented by mnjuly1970 last updated on 27/Feb/23 $$\:\:{in}\:\:{A}\overset{\Delta} {{B}C}\:{prove}\::\: \\ $$$$\:\:\:\frac{\mathrm{1}}{{cos}\left({A}\right)}\:+\frac{\mathrm{1}}{{cos}\left({B}\right)}\:+\frac{\mathrm{1}}{{cos}\left({C}\right)}\:\geqslant\:\mathrm{6} \\ $$$$\: \\ $$$$\:\:\:\:\:{note}\::\:\mathrm{0}\:<\:{A}\:,\:{B}\:,\:{C}\:<\:\mathrm{90}^{°} \\…
Question Number 188263 by mathlove last updated on 27/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com