Question Number 120324 by mathocean1 last updated on 30/Oct/20 $$\mathrm{we}\:\mathrm{are}\:\mathrm{in}\:\mathbb{C}. \\ $$$$\left(\mathrm{E}\right):\:\mathrm{z}^{\mathrm{3}} +\left(\mathrm{4}−\mathrm{5i}\right)\mathrm{z}^{\mathrm{2}} +\left(\mathrm{8}−\mathrm{20i}\right)\mathrm{z}−\mathrm{40i}=\mathrm{0} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{Show}\:\mathrm{that}\:\left(\mathrm{E}\right)\:\mathrm{has}\:\mathrm{one}\:\mathrm{imaginary}\:\mathrm{pure}\:\mathrm{root} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{solve}\:\left(\mathrm{E}\right) \\ $$ Answered by Olaf last updated…
Question Number 54787 by behi83417@gmail.com last updated on 10/Feb/19 $$\:{if}:\:\:\frac{{a}}{\:\sqrt{{b}}+\sqrt{{c}}}=\frac{{b}}{\:\sqrt{{c}}+\sqrt{{d}}}=\frac{{c}}{\:\sqrt{{d}}+\sqrt{{a}}}=\frac{{d}}{\:\sqrt{{a}}+\sqrt{{b}}} \\ $$$$\Rightarrow\frac{{a}}{{d}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 54786 by behi83417@gmail.com last updated on 10/Feb/19 $${solve}\:{for}:{a},{b},{c},{d}\in\boldsymbol{{R}} \\ $$$$\:\:\:\:\:\:{a}^{\mathrm{2}} ={b}+\sqrt{{c}} \\ $$$$\:\:\:\:\:\:{b}^{\mathrm{2}} ={c}+\sqrt{{d}} \\ $$$$\:\:\:\:\:\:{c}^{\mathrm{2}} ={d}+\sqrt{{a}} \\ $$$$\:\:\:\:\:\:{d}^{\mathrm{2}} ={a}+\sqrt{{b}} \\ $$ Commented…
Question Number 54775 by MJS last updated on 10/Feb/19 $$\mathrm{found}\:\mathrm{something}\:\mathrm{interesting},\:\mathrm{it}\:\mathrm{was}\:\mathrm{published} \\ $$$$\mathrm{by}\:\mathrm{Tschirnhaus}\:\mathrm{in}\:\mathrm{1683} \\ $$$$\mathrm{we}\:\mathrm{can}\:\mathrm{reduce} \\ $$$${x}^{\mathrm{3}} +{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{to} \\ $$$${y}^{\mathrm{3}} +{py}+{q}=\mathrm{0} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{and}\:\mathrm{further}\:\mathrm{to}…
Question Number 185840 by Shrinava last updated on 28/Jan/23 Commented by mr W last updated on 29/Jan/23 $${here}\:{someone}\:{likes}\:{the}\:{question}\: \\ $$$${without}\:{to}\:{know}\:{what}\:{the}\:{question}\:{is}. \\ $$ Terms of Service…
Question Number 185842 by Shrinava last updated on 28/Jan/23 Commented by mr W last updated on 29/Jan/23 $${here}\:{someone}\:{likes}\:{the}\:{question}\: \\ $$$${without}\:{to}\:{know}\:{what}\:{the}\:{question}\:{is}. \\ $$ Terms of Service…
Question Number 185843 by Shrinava last updated on 28/Jan/23 Commented by mr W last updated on 29/Jan/23 $${here}\:{someone}\:{likes}\:{the}\:{question}\: \\ $$$${without}\:{to}\:{know}\:{what}\:{the}\:{question}\:{is}. \\ $$ Terms of Service…
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Question Number 185780 by mr W last updated on 27/Jan/23 $${find}\:{all}\:{solutions}\:{for} \\ $$$${k}!{m}!={n}! \\ $$$$\left({k},{m},{n}\in\mathbb{N}\right) \\ $$$$\left({m}\geqslant{k}>\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 120240 by sorankarami0012 last updated on 30/Oct/20 $$\rightarrow \\ $$ Answered by mathmax by abdo last updated on 30/Oct/20 $$\curvearrowleft\frown\rightarrow\infty \\ $$ Terms…