Question Number 187255 by Spillover last updated on 15/Feb/23 $${Find}\:{the}\:{directional}\:{derivatives}\:{of}\:{the} \\ $$$${function}\: \\ $$$${f}\left({x},\mathrm{y},\mathrm{z}\right)=\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:{at}\:{the}\:{point}\:{p}\left(\mathrm{2},\mathrm{1},\mathrm{3}\right) \\ $$ Answered by MikeH last updated on…
Question Number 187254 by mnjuly1970 last updated on 15/Feb/23 Answered by MJS_new last updated on 15/Feb/23 $${c}={a}+{b}\:\Rightarrow\:{E}=\frac{\mathrm{2}\left({a}^{\mathrm{2}} +{ab}+{b}^{\mathrm{2}} \right)^{\mathrm{2}} }{{ab}}>\mathrm{0} \\ $$ Terms of Service…
Question Number 187248 by MWSuSon last updated on 15/Feb/23 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{cardinality}\:\mathrm{of}\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{prime}\:\mathrm{numbers}\:\mathrm{whose} \\ $$$$\mathrm{base}\:\mathrm{ten}\:\mathrm{digits}\:\mathrm{sums}\:\mathrm{up}\:\mathrm{to}\:\mathrm{10} \\ $$ Commented by Frix last updated on 15/Feb/23 $$\mathrm{Same}\:\mathrm{as}\:\mathbb{N} \\ $$ Terms…
Question Number 56179 by problem solverd last updated on 11/Mar/19 $$\mathrm{draw}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of} \\ $$$$\mathrm{f}\left({x}\right)=\sqrt{\mathrm{1}−{x}^{\mathrm{2}} } \\ $$$$\mathrm{for}\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1} \\ $$ Commented by mr W last updated on…
Question Number 56166 by Tawa1 last updated on 11/Mar/19 Commented by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19 $${pls}\:{refer}\:{any}\:{standard}\:{book}… \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 187233 by ajfour last updated on 15/Feb/23 $${Find}\:{x}\:{if}\::\:\:\:{x}^{\mathrm{4}} +{a}={x}\:\:\:\:\forall\:\left(\mathrm{0}<{a}<\frac{\mathrm{2}}{\mathrm{9}}\right)\:\:\: \\ $$ Commented by MJS_new last updated on 15/Feb/23 $$\mathrm{maybe}\:\mathrm{off}\:\mathrm{topic}\:\mathrm{but}\:\mathrm{it}\:\mathrm{could}\:\mathrm{be}\:\mathrm{of}\:\mathrm{interest} \\ $$$$\left({x}−\frac{{p}^{\mathrm{2}} }{\mathrm{2}}−\frac{\sqrt{\mathrm{2}−{p}^{\mathrm{6}} }}{\mathrm{2}{p}}\right)\left({x}−\frac{{p}^{\mathrm{2}}…
Question Number 121693 by mathace last updated on 11/Nov/20 Commented by prakash jain last updated on 12/Nov/20 $$ \\ $$ Commented by mindispower last updated…
Question Number 121684 by mathocean1 last updated on 10/Nov/20 $$\theta\:\in\:\left[\mathrm{0};\mathrm{2}\pi\right]. \\ $$$${solve}\:{in}\:\mathbb{C}\:{this}\:{equation}: \\ $$$${z}^{\mathrm{2}} −\left(\mathrm{2}^{\theta+\mathrm{1}} {cos}\theta\right){z}+\mathrm{2}^{\mathrm{2}\theta} =\mathrm{0} \\ $$$$ \\ $$ Commented by Dwaipayan Shikari…
Question Number 56147 by afachri last updated on 11/Mar/19 $$\mathrm{if}\:\underset{\:\:\mathrm{1}} {\overset{\:\:\mathrm{2}} {\int}}\:{f}\left({x}\right)\:{dx}\:=\:\sqrt{\:\mathrm{2}\:},\:\mathrm{then}\:\underset{\:\:\mathrm{1}} {\overset{\:\:\mathrm{4}} {\int}}\:\frac{\mathrm{1}}{\:\sqrt{\:{x}\:}\:}\:{f}\left({x}\right)\:{dx} \\ $$$$\:\mathrm{is}\:?? \\ $$$$\:\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{Sir}.\:\mathrm{I}'\mathrm{ve}\:\mathrm{been}\:\mathrm{trying} \\ $$$$\:\:\mathrm{this}\:\mathrm{for}\:\mathrm{2}\:\mathrm{days}\:\mathrm{and}\:\mathrm{getting}\:\mathrm{stuck}. \\ $$$$ \\ $$$$ \\…
Question Number 56144 by gunawan last updated on 11/Mar/19 $$\mathrm{calculate}\:\left({i}−\mathrm{1}\right)^{\mathrm{49}} \left(\mathrm{cos}\:\frac{\pi}{\mathrm{40}}+{i}\:\mathrm{sin}\:\frac{\pi}{\mathrm{40}}\right)^{\mathrm{10}} \\ $$ Answered by Smail last updated on 11/Mar/19 $$\left({i}−\mathrm{1}\right)^{\mathrm{49}} =\left[\sqrt{\mathrm{2}}\left(\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}−{i}\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right)\right]^{\mathrm{49}} \\ $$$$=\sqrt{\mathrm{2}^{\mathrm{49}} }\left({e}^{{i}\frac{\pi}{\mathrm{4}}}…