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Category: Algebra

solve-in-Z-x-3-2x-1-1-4-

Question Number 120471 by mathocean1 last updated on 31/Oct/20 $${solve}\:{in}\:\mathbb{Z}\:{x}^{\mathrm{3}} +\mathrm{2}{x}+\mathrm{1}\equiv\mathrm{1}\left[\mathrm{4}\right] \\ $$ Answered by Ar Brandon last updated on 31/Oct/20 $$\mathrm{x}^{\mathrm{3}} +\mathrm{2x}+\mathrm{1}=\mathrm{1}\left[\mathrm{4}\right]\Rightarrow\mathrm{x}^{\mathrm{3}} +\mathrm{2x}=\mathrm{0}\left[\mathrm{4}\right] \\…

Question-120464

Question Number 120464 by pooooop last updated on 31/Oct/20 Answered by Jamshidbek2311 last updated on 31/Oct/20 $$\sqrt{{x}−\mathrm{1}}={a}\:\:\Rightarrow\:{x}={a}^{\mathrm{2}} +\mathrm{1} \\ $$$$\sqrt{{y}−\mathrm{4}}={b}\:\Rightarrow\:{y}={b}^{\mathrm{2}} +\mathrm{4} \\ $$$$\sqrt{{z}−\mathrm{9}}={c}\:\Rightarrow\:{z}={c}^{\mathrm{2}} +\mathrm{9}\: \\…

f-0-1-R-f-x-4-x-2-4-x-is-given-find-the-value-of-the-following-expression-E-f-1-20-f-2-20-

Question Number 185983 by mnjuly1970 last updated on 30/Jan/23 $$ \\ $$$$\:\:\:\:\:\begin{cases}{\:\:\:{f}\::\:\:\left[\:\:\mathrm{0}\:\:,\:\:\mathrm{1}\:\right]\:\rightarrow\:\mathbb{R}}\\{\:\:\:\:{f}\:\left({x}\:\right)\:=\:\frac{\:\mathrm{4}^{\:{x}} }{\mathrm{2}\:+\:\mathrm{4}^{\:{x}} }}\end{cases} \\ $$$$\:\:\:\:\:\:{is}\:\:{given}\:.\:\:{find}\:{the}\:{value}\:{of} \\ $$$$\:\:\:\:\:\:{the}\:{following}\:{expression}. \\ $$$$\:\:\:\:\:\:\mathrm{E}\:=\:{f}\:\left(\frac{\mathrm{1}}{\mathrm{20}}\:\right)+\:{f}\left(\frac{\:\mathrm{2}}{\mathrm{20}}\:\right)+…\:+{f}\:\left(\frac{\mathrm{19}}{\mathrm{20}}\right)\:−{f}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\:\right)=? \\ $$ Answered by ARUNG_Brandon_MBU…

solve-in-R-2x-3x-1-x-greatest-integer-number-more-than-or-equal-to-x-

Question Number 185981 by mnjuly1970 last updated on 30/Jan/23 $$ \\ $$$$\:\:\:\:\:\:\:{solve}\:\:{in}\:\:\:\mathbb{R} \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\lfloor\:\:\mathrm{2}{x}\:\rfloor\:\:+\:\lfloor\:\:\mathrm{3}{x}\:\rfloor\:=\:\mathrm{1} \\ $$$$\: \\ $$$$\:\:\:\:\lfloor\:{x}\:\rfloor\::=\:{greatest}\:{integer}\:{number} \\ $$$$\:\:\:\:{more}\:{than}\:\:{or}\:{equal}\:\:{to}\:\:''\:{x}\:'' \\ $$ Answered…

Question-185982

Question Number 185982 by Shrinava last updated on 30/Jan/23 Answered by Mathspace last updated on 30/Jan/23 $${we}\:{developp}\:{first}\:\left({x}+\mathrm{1}\right)^{\mathrm{2}{n}} \\ $$$$=\sum_{{k}=\mathrm{0}} ^{\mathrm{2}{n}} {C}_{\mathrm{2}{n}} ^{{k}} {x}^{{k}} \:\:{but} \\…