Question Number 185127 by Shrinava last updated on 17/Jan/23 $$\begin{cases}{\sqrt{\mathrm{x}^{\mathrm{2}} \:−\:\frac{\mathrm{5}}{\mathrm{9}}\:+\:\sqrt{\mathrm{y}\:+\:\mathrm{x}^{\mathrm{2}} \:−\:\frac{\mathrm{5}}{\mathrm{9}}}}\:=\:\mathrm{y}}\\{\sqrt{\mathrm{y}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}\:+\:\sqrt{\mathrm{x}\:+\:\mathrm{y}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}}}\:=\:\mathrm{x}}\end{cases} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{x}\:,\:\mathrm{y}\:=\:? \\ $$ Commented by Frix last updated on 17/Jan/23…
Question Number 185126 by Shrinava last updated on 17/Jan/23 $$\left(\mid\mathrm{y}\mid−\mid\mathrm{x}\mid−\mathrm{2},\mathrm{8}\right)\left(\mid\mathrm{x}\mid−\mid\mathrm{y}\mid−\mathrm{1},\mathrm{8}\right)\:=\:\mathrm{0} \\ $$$$\mid\mathrm{y}\mid\:=\:\mathrm{a}\:\mid\mathrm{x}\mid\:+\:\mathrm{a}\:\mid\mid\mathrm{x}\mid\:−\:\mathrm{1},\mathrm{1}\mid\:+\:\mathrm{5} \\ $$$$\mathrm{At}\:\mathrm{what}\:\mathrm{value}\:\mathrm{of}\:\:\boldsymbol{\mathrm{a}}\:\:\mathrm{does}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{have}\:\:\mathrm{4}\:\:\mathrm{roots}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 119580 by mathocean1 last updated on 25/Oct/20 $$\mathrm{Given}\:\mathrm{k}\:\in\:\mathbb{N}. \\ $$$$\left.\mathrm{1}\right)\:\mathrm{justify}\:\mathrm{these}\:\mathrm{relations}: \\ $$$$\mathrm{3}^{\mathrm{2k}} +\mathrm{1}\equiv\mathrm{2}\left[\mathrm{8}\right]\:\mathrm{and}\:\mathrm{3}^{\mathrm{2k}+\mathrm{1}} +\mathrm{1}\equiv\mathrm{4}\left[\mathrm{8}\right]. \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Given}\:\left(\mathrm{E}\right):\:\mathrm{2}^{\mathrm{n}} −\mathrm{3}^{\mathrm{m}} =\mathrm{1}.\:\mathrm{n}\:\mathrm{and}\:\mathrm{m}\:\mathrm{are}\:\mathrm{unknowed}. \\ $$$$\bullet\:\mathrm{Show}\:\mathrm{that}\:\mathrm{if}\:\mathrm{m}\:\mathrm{is}\:\mathrm{even}\:,\:\left(\mathrm{E}\right)\:\mathrm{does}\:\mathrm{not}\:\mathrm{have}\: \\ $$$$\mathrm{solution}. \\…
Question Number 185122 by Shrinava last updated on 17/Jan/23 $$\begin{cases}{\sqrt{\mathrm{x}^{\mathrm{2}} \:−\:\frac{\mathrm{5}}{\mathrm{9}}\:+\:\sqrt{\mathrm{y}\:+\:\mathrm{x}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}}}\:=\:\mathrm{y}}\\{\sqrt{\mathrm{y}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}\:+\:\sqrt{\mathrm{x}\:+\:\mathrm{y}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}}}\:=\:\mathrm{x}}\end{cases} \\ $$$$\mathrm{find}:\:\:\:\mathrm{x}\:,\:\mathrm{y}\:=\:? \\ $$ Commented by Frix last updated on 17/Jan/23…
Question Number 119576 by bemath last updated on 25/Oct/20 Answered by TANMAY PANACEA last updated on 25/Oct/20 $${x}=\frac{\mathrm{2}{m}}{\mathrm{3}}\:\:{y}=\frac{\mathrm{2}{n}}{\mathrm{3}}\:\:\:{z}=\frac{\mathrm{2}{k}}{\mathrm{3}} \\ $$$$\frac{\mathrm{4}{m}}{\mathrm{3}}+\mathrm{2}{n}+\frac{\mathrm{2}{k}}{\mathrm{3}}=\mathrm{22} \\ $$$$\mathrm{4}{m}+\mathrm{6}{n}+\mathrm{2}{k}=\mathrm{66} \\ $$$$\mathrm{4}\left(\mathrm{13}−{k}\right)+\mathrm{6}{n}+\mathrm{2}{k}=\mathrm{66} \\…
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Question Number 54024 by sandip123 last updated on 28/Jan/19 $$\mathrm{The}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{x}^{\mathrm{4}} \:\mathrm{in}\:\left(\mathrm{2}−\mathrm{4x}+\mathrm{3x}^{\mathrm{2}} \right)^{−\mathrm{2}} \mathrm{i}\:\mathrm{s}\:? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 28/Jan/19 $$\left(\mathrm{2}−\mathrm{4}{x}+\mathrm{3}{x}^{\mathrm{2}} \right)^{−\mathrm{2}} \\…
Question Number 54013 by zambolly19 last updated on 27/Jan/19 $$\mathrm{2}^{\boldsymbol{\mathrm{x}}} =−\mathrm{4}.\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by Smail last updated on 27/Jan/19 $${xln}\mathrm{2}={ln}\left(−\mathrm{4}\right) \\ $$$${x}=\frac{{ln}\left(\mathrm{4}{e}^{{i}\pi} \right)}{{ln}\mathrm{2}}=\frac{\mathrm{2}{ln}\mathrm{2}+{i}\pi}{{ln}\mathrm{2}}=\mathrm{2}+{i}\frac{\pi}{{ln}\mathrm{2}} \\…
Question Number 119540 by AlbinEA last updated on 25/Oct/20 Answered by Bird last updated on 25/Oct/20 $${kitchen}\:{thorem}…. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 185076 by mathlove last updated on 16/Jan/23 $${x}^{\mathrm{2}{x}^{\mathrm{6}} } =\mathrm{3} \\ $$$${x}=? \\ $$ Answered by aba last updated on 16/Jan/23 $$\mathrm{x}^{\mathrm{2x}^{\mathrm{6}} }…