Question Number 119133 by Cristina last updated on 22/Oct/20 $$\mathrm{Informatica} \\ $$$$\left(\mathrm{11110000}\right)_{\mathrm{2}} =\mathrm{0}\bullet\mathrm{2}^{\mathrm{0}} +\mathrm{0}\bullet\mathrm{2}^{\mathrm{1}} +\mathrm{0}\bullet\mathrm{2}^{\mathrm{2}} +\mathrm{0}\bullet\mathrm{2}^{\mathrm{3}} +\mathrm{1}\bullet\mathrm{2}^{\mathrm{4}} +\mathrm{1}\bullet\mathrm{2}^{\mathrm{5}} +\mathrm{1}\bullet\mathrm{2}^{\mathrm{6}} +\mathrm{1}\bullet\mathrm{2}^{\mathrm{7}} = \\ $$$$=\mathrm{0}\bullet\mathrm{1}+\mathrm{0}\bullet\mathrm{2}+\mathrm{0}\bullet\mathrm{4}+\mathrm{0}\bullet\mathrm{8}+\mathrm{1}\bullet\mathrm{16}+\mathrm{1}\bullet\mathrm{32}+\mathrm{1}\bullet\mathrm{64}+\mathrm{1}\bullet\mathrm{128}= \\ $$$$\mathrm{0}+\mathrm{0}+\mathrm{0}+\mathrm{0}+\mathrm{16}+\mathrm{32}+\mathrm{64}+\mathrm{128}=\left(\mathrm{240}\right)_{\mathrm{10}}…
Question Number 184668 by Shrinava last updated on 10/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 119119 by benjo_mathlover last updated on 22/Oct/20 Answered by mindispower last updated on 22/Oct/20 $$\Rightarrow{abc}+\mathrm{1}=\frac{{a}}{{a}+{b}+{c}}…\mathrm{1} \\ $$$${abc}+\mathrm{2}=\frac{{b}}{{a}+{b}+{c}}….\mathrm{2} \\ $$$${abc}+\mathrm{7}=\frac{{c}}{{a}+{b}+{c}}…\mathrm{3} \\ $$$${abc}+\mathrm{10}=\mathrm{1} \\ $$$$\Rightarrow{abc}=−\mathrm{9}…\mathrm{2}…
Question Number 119107 by I want to learn more last updated on 22/Oct/20 Answered by 1549442205PVT last updated on 22/Oct/20 $$\mathrm{S}=\mathrm{1}+\mathrm{3}−\mathrm{5}+\mathrm{7}+\mathrm{9}−\mathrm{11}+\mathrm{13}+\mathrm{15}−\mathrm{17}+\mathrm{19}+\mathrm{21}−\mathrm{23}+… \\ $$$$\mathrm{S}=\left(\mathrm{1}+\mathrm{3}−\mathrm{5}\right)+\left(\mathrm{7}+\mathrm{9}−\mathrm{11}\right)+\left(\mathrm{13}+\mathrm{15}−\mathrm{17}\right)+\left(\mathrm{19}+\mathrm{21}−\mathrm{23}\right)+ \\ $$$$\left(\mathrm{25}+\mathrm{27}−\mathrm{29}\right)+…+\left[\mathrm{6n}−\mathrm{5}+\mathrm{6n}−\mathrm{3}−\left(\mathrm{6n}−\mathrm{5}\right)\right]…
Question Number 53550 by vajpaithegrate@gmail.com last updated on 23/Jan/19 Commented by Kunal12588 last updated on 23/Jan/19 Commented by Kunal12588 last updated on 23/Jan/19 $${they}\:{are}\:{not}\:{intersecting}\:{answer}\:{should}\:{be} \\…
Question Number 184622 by Shrinava last updated on 09/Jan/23 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\mathrm{sinx}\:\sqrt{\mathrm{1}\:−\:\mathrm{sin}^{\mathrm{2}} \mathrm{x}}\:=\:\mathrm{1}\:+\:\mathrm{cosy}\:\sqrt{\mathrm{1}\:−\:\mathrm{cos}^{\mathrm{2}} \mathrm{y}}\: \\ $$ Answered by floor(10²Eta[1]) last updated on 09/Jan/23 $$\mathrm{sinxcosx}=\mathrm{1}+\mathrm{senycosy} \\…
Question Number 184607 by mr W last updated on 09/Jan/23 $${solve} \\ $$$$\begin{cases}{{x}^{\mathrm{2}} −{xy}+{y}^{\mathrm{2}} =\mathrm{16}}\\{{y}^{\mathrm{2}} −{yz}+{z}^{\mathrm{2}} =\mathrm{25}}\\{{z}^{\mathrm{2}} −{zx}+{x}^{\mathrm{2}} =\mathrm{49}}\end{cases} \\ $$ Commented by Frix last…
Question Number 119059 by qqqqqqqqq last updated on 21/Oct/20 Answered by MJS_new last updated on 21/Oct/20 $$\sqrt{{x}^{\mathrm{2}} +{x}^{\mathrm{2}} \left({x}+\mathrm{1}\right)^{\mathrm{2}} +\left({x}+\mathrm{1}\right)^{\mathrm{2}} }−{x}^{\mathrm{2}} = \\ $$$$=\sqrt{{x}^{\mathrm{4}} +\mathrm{2}{x}^{\mathrm{3}}…
Question Number 119052 by shahria14 last updated on 21/Oct/20 Answered by 1549442205PVT last updated on 22/Oct/20 $$\mid\mathrm{x}^{\mathrm{2}} −\mathrm{1}\mid\leqslant\mathrm{3}\Leftrightarrow−\mathrm{3}\leqslant\mathrm{x}^{\mathrm{2}} −\mathrm{1}\leqslant\mathrm{3}\Leftrightarrow−\mathrm{2}\leqslant\mathrm{x}^{\mathrm{2}} \leqslant\mathrm{4} \\ $$$$\Leftrightarrow\mathrm{x}^{\mathrm{2}} \leqslant\mathrm{4}\Leftrightarrow\mid\mathrm{x}\mid\leqslant\mathrm{2}\Leftrightarrow−\mathrm{2}\leqslant\mathrm{x}\leqslant\mathrm{2} \\ $$$$…
Question Number 119055 by mathocean1 last updated on 21/Oct/20 $$ \\ $$$${Show}\:{by}\:{recurence}\:{that}:\:\forall\:{n}\in\mathbb{N}^{\ast} \\ $$$$\sum_{{k}=\mathrm{1}} ^{{n}} \frac{\mathrm{1}}{{k}\left({k}+\mathrm{1}\right)\left({k}+\mathrm{2}\right)}=\frac{{n}\left({n}+\mathrm{3}\right)}{\mathrm{4}\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)} \\ $$ Answered by Bird last updated on 21/Oct/20…