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Category: Algebra

Question-184242

Question Number 184242 by Shrinava last updated on 04/Jan/23 Answered by SEKRET last updated on 04/Jan/23 $$\:\boldsymbol{\mathrm{metod}}\:\boldsymbol{\mathrm{Kramer}} \\ $$$$\:\boldsymbol{\mathrm{det}}\left(\boldsymbol{\mathrm{A}}\right)\:=\:\:\begin{vmatrix}{\mathrm{4}}&{−\mathrm{5}}&{\:\:\mathrm{2}}\\{\mathrm{3}}&{−\mathrm{2}}&{\:\:\:\mathrm{7}}\\{\mathrm{3}}&{\mathrm{10}}&{−\mathrm{2}}\end{vmatrix}=\:−\mathrm{327} \\ $$$$\:\boldsymbol{\mathrm{det}}\left(\boldsymbol{\mathrm{A}}_{\mathrm{1}} \right)=\:\begin{vmatrix}{\mathrm{9}}&{−\mathrm{5}}&{\mathrm{2}}\\{\mathrm{8}}&{−\mathrm{2}}&{\mathrm{7}}\\{\mathrm{17}}&{\mathrm{10}}&{−\mathrm{2}}\end{vmatrix}=\:−\mathrm{1041} \\ $$$$\:\:\boldsymbol{\mathrm{det}}\left(\boldsymbol{\mathrm{A}}_{\mathrm{2}} \right)=\:\begin{vmatrix}{\mathrm{4}}&{\mathrm{9}}&{\mathrm{2}}\\{\mathrm{3}}&{\mathrm{8}}&{\mathrm{7}}\\{\mathrm{3}}&{\mathrm{17}}&{−\mathrm{2}}\end{vmatrix}=\:−\mathrm{243}…

x-2-1-3-x-3-1-3-gt-1-2-

Question Number 53108 by Tawa1 last updated on 17/Jan/19 $$\:\:\sqrt[{\mathrm{3}}]{\mathrm{x}\:+\:\mathrm{2}}\:\:−\:\:\sqrt[{\mathrm{3}}]{\mathrm{x}\:−\:\mathrm{3}}\:\:\:>\:\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by kaivan.ahmadi last updated on 17/Jan/19 $$\mathrm{t}^{\mathrm{3}} =\mathrm{x}−\mathrm{3}\Rightarrow\mathrm{t}^{\mathrm{3}} +\mathrm{5}=\mathrm{x}+\mathrm{2}\Rightarrow \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{t}^{\mathrm{3}} +\mathrm{5}}\rangle\mathrm{t}+\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow\mathrm{power}\:\mathrm{3}…

Prove-that-the-equation-of-the-circle-passing-through-the-points-of-intersection-of-these-two-curves-y-1-c-x-y-x-2-c-lt-2-3-3-is-x-c-2-2-y-1-2-1-c-2-4-

Question Number 118634 by ajfour last updated on 18/Oct/20 $${Prove}\:{that}\:{the}\:{equation}\:{of}\:{the}\:{circle} \\ $$$${passing}\:{through}\:{the}\:{points}\:{of} \\ $$$${intersection}\:{of}\:{these}\:{two}\:{curves}: \\ $$$$\:\:{y}=\mathrm{1}+\frac{{c}}{{x}}\:;\:\:{y}={x}^{\mathrm{2}} \:\:\:\:\:\left({c}\:<\:\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\:\right)\: \\ $$$${is}\:\:\:\left({x}−\frac{{c}}{\mathrm{2}}\right)^{\mathrm{2}} +\left({y}−\mathrm{1}\right)^{\mathrm{2}} =\mathrm{1}+\frac{{c}^{\mathrm{2}} }{\mathrm{4}}\:\:. \\ $$ Commented…

sin-2x-cos-xd-x-

Question Number 53051 by Abror last updated on 16/Jan/19 $$\int\mathrm{sin}\:\left(\mathrm{2}{x}\right)\mathrm{cos}\:{xd}\left({x}\right)= \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 16/Jan/19 $$\frac{\mathrm{1}}{\mathrm{2}}\int\mathrm{2}{sin}\mathrm{2}{xcosxdx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\int\left({sin}\mathrm{3}{x}+{sinx}\right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\left[\frac{−{cos}\mathrm{3}{x}}{\mathrm{3}}+\frac{−{cosx}}{}\right]+{c} \\…