Category: Algebra

Question Number 56179 by problem solverd last updated on 11/Mar/19 $$\mathrm{draw}\mathrm{the}\mathrm{graph}\mathrm{of}$$$$\mathrm{f}\left(x\right)=\sqrt{1-x^2}$$$$\mathrm{for}0⩽x⩽1$$ Commented by mr W last updated on…

Question Number 187233 by ajfour last updated on 15/Feb/23 $$Findxif:x^4+a=x\mathrm{\forall }(0<a<\frac{2}{9})$$ Commented by MJS_new last updated on 15/Feb/23 $$\mathrm{maybe}\mathrm{off}\mathrm{topic}\mathrm{but}\mathrm{it}\mathrm{could}\mathrm{be}\mathrm{of}\mathrm{interest}$$$$\left({x}−\frac{{p}^{\mathrm{2}} }{\mathrm{2}}−\frac{\sqrt{\mathrm{2}−{p}^{\mathrm{6}} }}{\mathrm{2}{p}}\right)\left({x}−\frac{{p}^{\mathrm{2}}…

Question Number 121684 by mathocean1 last updated on 10/Nov/20 $$\theta \in [0;2\pi ].$$$$solvein\mathbb{C}thisequation:$$$$z^2-\left(2^{\theta +1}cos\theta \right)z+2^{2\theta }=0$$$$$$ Commented by Dwaipayan Shikari…

Question Number 56144 by gunawan last updated on 11/Mar/19 $$\mathrm{calculate}{(i-1)}^{49}{(\cos \frac{\pi }{40}+i\sin \frac{\pi }{40})}^{10}$$ Answered by Smail last updated on 11/Mar/19 $${(i-1)}^{49}={\left[\sqrt{2}(\frac{\sqrt{2}}{2}-i\frac{\sqrt{2}}{2})\right]}^{49}$$$$=\sqrt{\mathrm{2}^{\mathrm{49}} }\left({e}^{{i}\frac{\pi}{\mathrm{4}}}…

Question Number 187209 by ajfour last updated on 14/Feb/23 Commented by ajfour last updated on 14/Feb/23 $$Findsort.$$ Terms of Service Privacy Policy Contact:…