Question Number 58851 by hhghg last updated on 30/Apr/19 $$\mathrm{6}+\mathrm{2}×\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 189916 by mustafazaheen last updated on 24/Mar/23 $$\mathrm{when}\:\:\:\:\mathrm{sinx}×\mathrm{cosx}=−\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\mathrm{find}\:\:\:\:\:\:\:\mathrm{sinx}+\mathrm{cosx}=? \\ $$ Answered by aminitindas last updated on 24/Mar/23 $$ \\ $$$$\boldsymbol{\mathrm{Ans}}: \\…
Question Number 189919 by horsebrand11 last updated on 24/Mar/23 $$\:{If}\:{x},{y}\:{are}\:{real}\:{numbers}\:{satisfy} \\ $$$$\:\frac{{x}+\mathrm{40}}{{y}}+\frac{\mathrm{569}}{{xy}}=\frac{\mathrm{26}−{y}}{{x}}\:,\:{then}\:{xy}=? \\ $$ Answered by cortano12 last updated on 24/Mar/23 $$\Rightarrow\left(\mathrm{x}+\mathrm{20}\right)^{\mathrm{2}} +\left(\mathrm{y}−\mathrm{13}\right)^{\mathrm{2}} =\mathrm{0} \\…
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Question Number 189886 by mnjuly1970 last updated on 23/Mar/23 $$ \\ $$$$\:\:{e}^{\:{x}} \:>\:\mathrm{1}+\:{x}\:\:\:\:\left(\forall\:{x}\:>\mathrm{0}\:\right) \\ $$$$\:\:\:{set}:\:{x}=\sqrt{\frac{\pi}{{e}}}\:−\mathrm{1} \\ $$$$\:\:\:\:{e}^{\:\frac{\sqrt{\pi}}{\:\sqrt{{e}}}\:−\mathrm{1}} >\:\frac{\sqrt{\pi}}{\:\sqrt{{e}}}\:\Rightarrow\:{e}^{\:\frac{\sqrt{\pi}}{\:\sqrt{{e}}}} \:>\:\sqrt{\pi}\: \\ $$$$\:\:\:\:\:\:\left(\:{e}^{\:\frac{\sqrt{\pi}}{\:\sqrt{{e}}}} \right)^{\:\sqrt{{e}}} >\:\sqrt{\pi}\:^{\:\sqrt{{e}}} \:\Rightarrow\:{e}^{\:\sqrt{\pi}} \:>\:\sqrt{\pi\:}\:^{\:\sqrt{{e}}}…
Question Number 58816 by Tawa1 last updated on 30/Apr/19 Answered by Kunal12588 last updated on 30/Apr/19 $${from}\:{looking}\:{the}\:{graph}\:{we}\:{can}\:{say}\:{that} \\ $$$${maxima}\:{of}\:{function}\:{is}\:{at}\:\:{x}=\mathrm{2} \\ $$$$\left.{for}\:{A}\right) \\ $$$$\frac{{d}\left({f}\left({x}\right)\right)}{{dx}}=\mathrm{0}\:\:\:\:\:\left[{for}\:{minima}\:{or}\:{maxima}\right] \\ $$$$−\frac{\mathrm{1}}{\mathrm{3}}×\mathrm{2}\left({x}−\mathrm{2}\right)\left(\mathrm{1}\right)=\mathrm{0}…
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Question Number 58789 by ANTARES VY last updated on 30/Apr/19 Commented by ANTARES VY last updated on 30/Apr/19 $$\mathrm{E}=? \\ $$ Commented by tanmay last…
Question Number 189858 by Shrinava last updated on 23/Mar/23 Answered by mr W last updated on 23/Mar/23 $${f}\left({x}\right)={x}^{\frac{\mathrm{1}}{{x}}} \:{is}\:{strictly}\:{increasing}\:{for}\:\mathrm{0}<{x}<{e} \\ $$$${since}\:\mathrm{1}<\sqrt{{e}}<\sqrt{\pi}<{e}, \\ $$$$\left(\sqrt{{e}}\right)^{\frac{\mathrm{1}}{\:\sqrt{{e}}}} <\left(\sqrt{\pi}\right)^{\frac{\mathrm{1}}{\:\sqrt{\pi}}} \\…
Question Number 58780 by hhghg last updated on 29/Apr/19 $$\mathrm{367}×\mathrm{25} \\ $$$$\mathrm{397}×\mathrm{45} \\ $$$$\mathrm{484}×\mathrm{79} \\ $$ Answered by ajfour last updated on 30/Apr/19 $$\mathrm{3}×\mathrm{25}×\mathrm{100}+\mathrm{6}×\mathrm{25}×\mathrm{10}+\mathrm{7}×\mathrm{25} \\…