Question Number 58145 by Mikael_Marshall last updated on 18/Apr/19 $${how}\:{to}\:{factorize} \\ $$$${a}^{\mathrm{3}} {b}^{\mathrm{2}} +{a}^{\mathrm{2}} {b}^{\mathrm{3}} \: \\ $$ Answered by tanmay last updated on 18/Apr/19…
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Question Number 189208 by mathlove last updated on 13/Mar/23 Answered by MJS_new last updated on 13/Mar/23 $$\mathrm{easy}\:\mathrm{to}\:\mathrm{see} \\ $$$$\mathrm{9}+\mathrm{2}=\mathrm{11} \\ $$$$\mathrm{3}+\mathrm{4}=\mathrm{7} \\ $$$${x}=\mathrm{9}\wedge{y}=\mathrm{4} \\ $$…
Question Number 58135 by rahul 19 last updated on 18/Apr/19 Answered by tanmay last updated on 18/Apr/19 $${e}^{{i}\alpha} ={cos}\alpha+{isin}\alpha \\ $$$${e}^{{i}\theta} ×{e}^{{i}\mathrm{2}\theta} ×{e}^{{i}\mathrm{3}\theta} ×…{e}^{{in}\theta} =\mathrm{1}={cos}\left(\mathrm{2}{m}\pi+{isin}\mathrm{2}{m}\pi\right)={e}^{{i}\left(\mathrm{2}{m}\pi\right)}…
Question Number 189201 by Shrinava last updated on 13/Mar/23 $$\mathrm{In}\:\:\:\bigtriangleup\mathrm{ABC}\:\:\:\mathrm{holds}: \\ $$$$\sqrt{\mathrm{2}}\:\mathrm{a}\:\mathrm{cos}\:\frac{\mathrm{B}}{\mathrm{2}}\:\mathrm{cos}\:\frac{\mathrm{C}}{\mathrm{2}}\:=\:\mathrm{s} \\ $$$$\Rightarrow\:\mathrm{sec}\:\left(\mathrm{2B}\right)\:+\:\mathrm{tan}\:\left(\mathrm{2B}\right)\:=\:\frac{\mathrm{c}\:+\:\mathrm{b}}{\mathrm{c}\:−\:\mathrm{b}} \\ $$ Answered by som(math1967) last updated on 13/Mar/23 $$\sqrt{\mathrm{2}}{acos}\frac{{B}}{\mathrm{2}}{cos}\frac{{C}}{\mathrm{2}}={s} \\…
Question Number 123638 by 676597498 last updated on 26/Nov/20 $$\mathrm{show}\:\mathrm{that}\:\mathrm{if}\:\mathrm{x}\in\mathbb{R}\:\mathrm{then}\:\mathrm{x}\:\mathrm{and}\:−\mathrm{x}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{positive} \\ $$ Commented by talminator2856791 last updated on 27/Nov/20 $$\:\mathrm{this}\:\mathrm{is}\:\mathrm{just}\:\mathrm{a}\:\mathrm{rule} \\ $$ Terms of Service…
Question Number 58092 by smiak8742 last updated on 17/Apr/19 $$\mathrm{6}{x}^{\mathrm{3}} +\mathrm{5}{x}^{\mathrm{2}} −\mathrm{6}{x}−\mathrm{5}=\mathrm{0} \\ $$ Answered by tanmay last updated on 17/Apr/19 $$\mathrm{6}{x}^{\mathrm{3}} −\mathrm{6}{x}+\mathrm{5}{x}^{\mathrm{2}} −\mathrm{5}=\mathrm{0} \\…
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Question Number 58084 by Tawa1 last updated on 17/Apr/19 Commented by MJS last updated on 17/Apr/19 $$\mathrm{sorry}\:\mathrm{but}\:\mathrm{do}\:\mathrm{you}\:\mathrm{really}\:\mathrm{believe}\:\mathrm{someone} \\ $$$$\mathrm{on}\:\mathrm{this}\:\mathrm{forum}\:\mathrm{could}\:\mathrm{be}\:\mathrm{able}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{problems} \\ $$$$\mathrm{which}\:\mathrm{can}'\mathrm{t}\:\mathrm{be}\:\mathrm{solved}\:\mathrm{by}\:\mathrm{the}\:\mathrm{greatest} \\ $$$$\mathrm{mathematicians}\:\mathrm{of}\:\mathrm{our}\:\mathrm{time}? \\ $$…
Question Number 58077 by hhghg last updated on 17/Apr/19 $$\frac{\mathrm{3}}{\mathrm{10}}×\mathrm{2} \\ $$ Answered by $@ty@m last updated on 17/Apr/19 $${Pl}.\:{see}\:{my}\:{comment}\:{on}\:\mathrm{57882}. \\ $$ Commented by mr…