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Category: Algebra

I-Incenter-in-ABC-A-2-2-B-6-4-C-4-8-M-8-6-Find-MI-

Question Number 183120 by Shrinava last updated on 20/Dec/22 $$\mathrm{I}−\mathrm{Incenter}\:\mathrm{in}\:\:\bigtriangleup\mathrm{ABC} \\ $$$$\mathrm{A}\left(\mathrm{2},\mathrm{2}\right)\:,\:\mathrm{B}\left(\mathrm{6},\mathrm{4}\right)\:,\:\mathrm{C}\left(\mathrm{4},\mathrm{8}\right)\:,\:\mathrm{M}\left(\mathrm{8},\mathrm{6}\right) \\ $$$$\mathrm{Find}:\:\:\:\mathrm{MI}\:=\:? \\ $$ Answered by manolex last updated on 21/Dec/22 $$\mathbb{I}=\frac{{Aa}+\boldsymbol{{B}}{b}+{Cc}}{{a}+{b}+{c}} \\…

Question-183076

Question Number 183076 by Engr_Jidda last updated on 19/Dec/22 Answered by TheSupreme last updated on 21/Dec/22 $${t}\:=\:{tan}\left({x}\right) \\ $$$$\mathrm{10}\geqslant{t}\geqslant\frac{\mathrm{7}}{\mathrm{3}} \\ $$$$\left({t}−\mathrm{2}\right)^{\pi} +\left({t}+\mathrm{5}\right)^{\pi} =\left(\mathrm{3}{t}−\mathrm{7}\right)^{\pi} +\left(\mathrm{10}−{t}\right)^{\pi} \\…

Solve-x-4-log-5-50x-x-6-

Question Number 52007 by Tawa1 last updated on 02/Jan/19 $$\mathrm{Solve}:\:\:\:\:\:\:\:\:\:\:\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{4}}\right)^{\boldsymbol{\mathrm{log}}_{\mathrm{5}} \mathrm{50}\boldsymbol{\mathrm{x}}} \:\:\:=\:\:\:\:\boldsymbol{\mathrm{x}}^{\mathrm{6}} \\ $$ Answered by MJS last updated on 02/Jan/19 $$\left(\frac{{x}}{\mathrm{4}}\right)^{\mathrm{log}_{\mathrm{5}} \:\mathrm{50}{x}} ={x}^{\mathrm{6}} \\…

Find-the-equation-of-the-line-which-passes-through-the-point-3-5-and-is-tangent-to-the-circle-x-1-2-y-1-2-4-

Question Number 183044 by depressiveshrek last updated on 19/Dec/22 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{line}\:{which} \\ $$$${passes}\:{through}\:{the}\:{point}\:\left(\mathrm{3},\:\mathrm{5}\right) \\ $$$${and}\:{is}\:{tangent}\:{to}\:{the}\:{circle} \\ $$$$\left({x}−\mathrm{1}\right)^{\mathrm{2}} +\left({y}−\mathrm{1}\right)^{\mathrm{2}} =\mathrm{4} \\ $$ Answered by mr W last…

Find-12-2-35-10-2-21-

Question Number 183041 by Shrinava last updated on 18/Dec/22 $$\mathrm{Find}: \\ $$$$\sqrt{\mathrm{12}−\mathrm{2}\sqrt{\mathrm{35}}}\:\:−\:\:\sqrt{\mathrm{10}−\mathrm{2}\sqrt{\mathrm{21}}}\:\:=\:\:? \\ $$ Answered by HeferH last updated on 18/Dec/22 $$\:\sqrt{\mathrm{12}−\mathrm{2}\sqrt{\mathrm{35}}}\:=\:\sqrt{\left(\sqrt{\mathrm{7}}\right)^{\mathrm{2}} \:+\:\left(\sqrt{\mathrm{5}}\right)^{\mathrm{2}} −\mathrm{2}\sqrt{\mathrm{7}}\centerdot\sqrt{\mathrm{5}}}\:\: \\…