Question Number 183019 by mathlove last updated on 18/Dec/22 $${Q}\:\:\:{f}\left({x}\right)={a}^{{x}} +{b}^{{x}} \:\:\:\:\:{g}\left({x}\right)=\frac{{f}\left({x}\right)}{{f}\left({x}−\mathrm{2}\right)} \\ $$$${g}\left(\mathrm{3}\right)=? \\ $$$$ \\ $$ Commented by mathlove last updated on 18/Dec/22…
Question Number 182999 by Shrinava last updated on 18/Dec/22 $$\sqrt{\mathrm{m}^{\mathrm{2}} −\mathrm{4m}+\mathrm{4}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{m}−\mathrm{2n}+\mathrm{8}}\:=\:\mathrm{0} \\ $$$$\mathrm{n}\:=\:? \\ $$ Answered by cortano1 last updated on 18/Dec/22 $$\:\mid{m}−\mathrm{2}\mid\:+\sqrt[{\mathrm{4}}]{{m}−\mathrm{2}{n}+\mathrm{8}}\:=\:\mathrm{0} \\ $$$$\:\begin{cases}{{m}=\mathrm{2}}\\{\sqrt[{\mathrm{4}}]{\mathrm{10}−\mathrm{2}{n}}\:=\:\mathrm{0}\:\Rightarrow{n}=\mathrm{5}\:}\end{cases}…
Question Number 51922 by aseerimad last updated on 01/Jan/19 $${find}\:{the}\:{value}\:{of}… \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{1}−\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\frac{{i}}{\mathrm{1}+\frac{{i}}{\mathrm{1}+{i}}}}} \\ $$$${pls}\:{help}. \\ $$ Answered by ajfour last updated on 01/Jan/19 $$\mathrm{1}+\frac{{i}}{\mathrm{1}+{i}}\:=\:\mathrm{1}+\frac{{i}\left(\mathrm{1}−{i}\right)}{\mathrm{2}}\:=\:\frac{\mathrm{3}+{i}}{\mathrm{2}} \\…
Question Number 182973 by HeferH last updated on 17/Dec/22 Answered by Rasheed.Sindhi last updated on 18/Dec/22 $${x}^{\mathrm{2}} +{x}+\mathrm{1}=\mathrm{0}\:;\:\underset{{n}=\mathrm{1}} {\overset{\mathrm{27}} {\Sigma}}\left({x}^{{n}} +\frac{\mathrm{1}}{{x}^{{n}} }\right)^{\mathrm{2}} =? \\ $$$$\left({x}^{{n}}…
Question Number 182953 by mathlove last updated on 17/Dec/22 $${H}_{\mathrm{4}} \left({x}\right)={L}_{\mathrm{0}} \left({x}\right)\:\:\:\:\:\:\:{x}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182946 by myint last updated on 17/Dec/22 $$\mathrm{If}\:\:\mathrm{0}\:<\:\mathrm{x}\:<\mathrm{1}\:,\:\:\mathrm{then}\:\:\mid\:\mathrm{x}\:−\mathrm{1}\:\mid\:+\:\mid\mathrm{2x}−\mathrm{4}\mid\:+\:\mid\mathrm{2x}+\mathrm{1}\mid= \\ $$ Commented by mr W last updated on 17/Dec/22 $$\neq{constant}\:{value}! \\ $$ Answered by…
Question Number 182947 by myint last updated on 17/Dec/22 $$\mathrm{If}\:\:\mathrm{a}<\:\mathrm{b}<\mathrm{0},\:\:\mathrm{then}\:\:\mid\mathrm{a}−\mathrm{b}\mid\:+\:\mid\mathrm{a}+\mathrm{b}\mid\:+\:\mid\mathrm{ab}\mid= \\ $$ Commented by mr W last updated on 17/Dec/22 $$\neq{constant}\:{value}! \\ $$$${could}\:{be}\:{any}\:{positive}\:{value}! \\ $$…
Question Number 182922 by mnjuly1970 last updated on 16/Dec/22 $$ \\ $$$$\:\:\:{solve} \\ $$$$ \\ $$$$\:\:\:\lfloor\:{x}\:\rfloor\:+\:\lfloor\:\mathrm{2}{x}\:\rfloor\:+\:\lfloor\:\mathrm{3}{x}\:\rfloor\:=\mathrm{1} \\ $$$$ \\ $$ Answered by mr W last…
Question Number 51843 by prakash jain last updated on 31/Dec/18 $${If}\:{ax}^{\mathrm{2}} +{bx}+{c}+{i}=\mathrm{0}\:\mathrm{has}\:\mathrm{purely} \\ $$$$\mathrm{imaginary}\:\mathrm{roots}\:\mathrm{where}\: \\ $$$${a},{b},{c}\:{are}\:{non}−{zero}\:{real}. \\ $$$${answer}\:{given}:\:{a}={b}^{\mathrm{2}} {c} \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{think}\:\mathrm{question}\:\mathrm{is}\:\mathrm{wrong} \\ $$$$\mathrm{since}\:\mathrm{if}\:{z}_{\mathrm{1}}…
Question Number 182907 by balliu last updated on 16/Dec/22 $$\mathrm{2},\:\mathrm{3},\:\mathrm{5},\:\mathrm{7},\:\mathrm{11} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com