Question Number 185206 by cortano1 last updated on 18/Jan/23 Commented by Frix last updated on 18/Jan/23 $$\mathrm{It}\:\mathrm{seems}\:\mathrm{the}\:\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:{x}={y}={z}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 185204 by Ml last updated on 18/Jan/23 $$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{4}+\frac{\mathrm{1}}{\ddots}}}}=??? \\ $$ Commented by MJS_new last updated on 18/Jan/23 $$\mathrm{you}\:\mathrm{could}\:\mathrm{type}\:?^{\mathrm{3}} \:\mathrm{instead}\:\mathrm{of}\:???;\:\mathrm{if}\:\mathrm{you}\:\mathrm{feel} \\ $$$$\mathrm{you}\:\mathrm{can}'\mathrm{t}\:\mathrm{live}\:\mathrm{without}\:\mathrm{an}\:\mathrm{answer}\:\mathrm{just}\:\mathrm{type}\:?^{\infty} \\ $$$$\left[\mathrm{short}\:\mathrm{for}\:\underset{{n}\rightarrow\infty}…
Question Number 185198 by ajfour last updated on 18/Jan/23 Commented by ajfour last updated on 18/Jan/23 $${If}\:\:\:{z}={r}+{xi}+{yj} \\ $$$${z}^{\mathrm{2}} ={r}^{\mathrm{2}} −{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{2}{r}\left({xi}+{yj}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:+{xy}\left({ij}+{ji}\right)…
Question Number 185192 by Rupesh123 last updated on 18/Jan/23 Commented by Rasheed.Sindhi last updated on 18/Jan/23 $$\mathrm{This}\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to}\:\mathrm{that}\:\mathrm{every}\:+\mathrm{ve} \\ $$$$\mathrm{integer}\:\mathrm{can}\:\mathrm{be}\:\mathrm{written}\:\mathrm{as}\:{a}^{\mathrm{2021}} +{b}^{\mathrm{2023}} \\ $$$$\mathrm{or}\:\mathrm{c}^{\mathrm{2022}} +{d}^{\mathrm{2024}} .\mathrm{I}\:\mathrm{think}\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{possible}\:\mathrm{for} \\…
Question Number 185191 by Shrinava last updated on 18/Jan/23 $$\mathrm{y}\:=\:\mathrm{sin}\:\frac{\mathrm{1}}{\mathrm{x}}\:\:\Rightarrow\:\:\mathrm{y}^{'} \:=\:? \\ $$ Answered by Frix last updated on 18/Jan/23 $${y}={f}\left({g}\left({x}\right)\right)\:\Rightarrow\:{y}'={g}'\left({x}\right)×{f}'\left({g}\left({x}\right)\right) \\ $$$${y}=\mathrm{sin}\:\frac{\mathrm{1}}{{x}}\:\Rightarrow\:{y}'=−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\mathrm{cos}\:\frac{\mathrm{1}}{{x}} \\…
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Question Number 119634 by Ar Brandon last updated on 25/Oct/20 $$\mathrm{Q1} \\ $$$$\mathrm{If}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{by} \\ $$$$\:\:\:\:\:\:\:\:{f}\left(\mathrm{x}\right)=\left[\mathrm{x}\right]+\left[\mathrm{x}+\frac{\mathrm{1}}{\mathrm{2}}\right]+\left[\mathrm{x}+\frac{\mathrm{2}}{\mathrm{3}}\right]−\mathrm{3x}+\mathrm{5} \\ $$$$\mathrm{where}\:\left[\mathrm{x}\right]\:\mathrm{is}\:\mathrm{the}\:\mathrm{integral}\:\mathrm{part}\:\mathrm{of}\:\mathrm{x},\:\mathrm{then}\:\mathrm{a}\:\mathrm{period}\:\mathrm{of}\:{f}\:\mathrm{is} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{2}/\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{1}/\mathrm{2}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{1}/\mathrm{3} \\ $$$$ \\ $$$$\mathrm{Q2} \\ $$$$\mathrm{Let}\:{a}<\mathrm{c}<\mathrm{b}\:\mathrm{such}\:\mathrm{that}\:\mathrm{c}−{a}=\mathrm{b}−\mathrm{c}.\:\mathrm{If}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{is}\:\mathrm{a}…
Question Number 119635 by Ar Brandon last updated on 25/Oct/20 $$\mathrm{If}\:\mathrm{a}\:\mathrm{function}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{relation} \\ $$$$\:\:\:\:\:\:\:{f}\left(\mathrm{x}+\mathrm{1}\right)+{f}\left(\mathrm{x}−\mathrm{1}\right)=\sqrt{\mathrm{3}}{f}\left(\mathrm{x}\right)\:\mathrm{for}\:\mathrm{all}\:\mathrm{x}\in\mathbb{R} \\ $$$$\mathrm{then}\:\mathrm{a}\:\mathrm{period}\:\mathrm{of}\:{f}\:\mathrm{is} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{10}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{4} \\ $$ Answered by Olaf last updated on…
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Question Number 54093 by Tawa1 last updated on 28/Jan/19 $$\mathrm{If}\:\:\:\:\:\:\mathrm{tan}\left(\mathrm{z}\right)\:\:=\:\:\mathrm{2},\:\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{z} \\ $$ Commented by mr W last updated on 28/Jan/19 $${z}=\mathrm{tan}^{−\mathrm{1}} \mathrm{2}+{n}\pi \\ $$ Commented…