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Category: Algebra

Question-185972

Question Number 185972 by Michaelfaraday last updated on 30/Jan/23 Answered by Rasheed.Sindhi last updated on 30/Jan/23 x=p3+1p3,y=p+1pShowthaty22=x(x23)$${x}^{\mathrm{3}} =\left(\sqrt[{\mathrm{3}}]{{p}}\:+\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{{p}}\:}\right)^{\mathrm{3}} ={p}+\frac{\mathrm{1}}{{p}}+\mathrm{3}\left(\sqrt[{\mathrm{3}}]{{p}}\:+\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{{p}}\:}\right)…