Question Number 51922 by aseerimad last updated on 01/Jan/19 $${find}\:{the}\:{value}\:{of}… \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{1}−\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\frac{{i}}{\mathrm{1}+\frac{{i}}{\mathrm{1}+{i}}}}} \\ $$$${pls}\:{help}. \\ $$ Answered by ajfour last updated on 01/Jan/19 $$\mathrm{1}+\frac{{i}}{\mathrm{1}+{i}}\:=\:\mathrm{1}+\frac{{i}\left(\mathrm{1}−{i}\right)}{\mathrm{2}}\:=\:\frac{\mathrm{3}+{i}}{\mathrm{2}} \\…
Question Number 182973 by HeferH last updated on 17/Dec/22 Answered by Rasheed.Sindhi last updated on 18/Dec/22 $${x}^{\mathrm{2}} +{x}+\mathrm{1}=\mathrm{0}\:;\:\underset{{n}=\mathrm{1}} {\overset{\mathrm{27}} {\Sigma}}\left({x}^{{n}} +\frac{\mathrm{1}}{{x}^{{n}} }\right)^{\mathrm{2}} =? \\ $$$$\left({x}^{{n}}…
Question Number 182953 by mathlove last updated on 17/Dec/22 $${H}_{\mathrm{4}} \left({x}\right)={L}_{\mathrm{0}} \left({x}\right)\:\:\:\:\:\:\:{x}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182946 by myint last updated on 17/Dec/22 $$\mathrm{If}\:\:\mathrm{0}\:<\:\mathrm{x}\:<\mathrm{1}\:,\:\:\mathrm{then}\:\:\mid\:\mathrm{x}\:−\mathrm{1}\:\mid\:+\:\mid\mathrm{2x}−\mathrm{4}\mid\:+\:\mid\mathrm{2x}+\mathrm{1}\mid= \\ $$ Commented by mr W last updated on 17/Dec/22 $$\neq{constant}\:{value}! \\ $$ Answered by…
Question Number 182947 by myint last updated on 17/Dec/22 $$\mathrm{If}\:\:\mathrm{a}<\:\mathrm{b}<\mathrm{0},\:\:\mathrm{then}\:\:\mid\mathrm{a}−\mathrm{b}\mid\:+\:\mid\mathrm{a}+\mathrm{b}\mid\:+\:\mid\mathrm{ab}\mid= \\ $$ Commented by mr W last updated on 17/Dec/22 $$\neq{constant}\:{value}! \\ $$$${could}\:{be}\:{any}\:{positive}\:{value}! \\ $$…
Question Number 182922 by mnjuly1970 last updated on 16/Dec/22 $$ \\ $$$$\:\:\:{solve} \\ $$$$ \\ $$$$\:\:\:\lfloor\:{x}\:\rfloor\:+\:\lfloor\:\mathrm{2}{x}\:\rfloor\:+\:\lfloor\:\mathrm{3}{x}\:\rfloor\:=\mathrm{1} \\ $$$$ \\ $$ Answered by mr W last…
Question Number 51843 by prakash jain last updated on 31/Dec/18 $${If}\:{ax}^{\mathrm{2}} +{bx}+{c}+{i}=\mathrm{0}\:\mathrm{has}\:\mathrm{purely} \\ $$$$\mathrm{imaginary}\:\mathrm{roots}\:\mathrm{where}\: \\ $$$${a},{b},{c}\:{are}\:{non}−{zero}\:{real}. \\ $$$${answer}\:{given}:\:{a}={b}^{\mathrm{2}} {c} \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{think}\:\mathrm{question}\:\mathrm{is}\:\mathrm{wrong} \\ $$$$\mathrm{since}\:\mathrm{if}\:{z}_{\mathrm{1}}…
Question Number 182907 by balliu last updated on 16/Dec/22 $$\mathrm{2},\:\mathrm{3},\:\mathrm{5},\:\mathrm{7},\:\mathrm{11} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182900 by greougoury555 last updated on 16/Dec/22 $$\:{Determine}\:{the}\:{values}\:{of}\:{b}\:{so}\:{that} \\ $$$$\:{the}\:{system}\:{of}\:{linear}\:{equations} \\ $$$$\:\begin{cases}{{x}+\mathrm{2}{y}+{z}=\mathrm{1}}\\{\mathrm{2}{x}+{by}+\mathrm{2}{z}=\mathrm{2}}\\{\mathrm{4}{x}+\mathrm{8}{y}+{b}^{\mathrm{2}} \:{z}=\mathrm{2}{b}}\end{cases} \\ $$$$\:{has}\:\left({a}\right)\:{no}\:{solution}\: \\ $$$$\:\left({b}\right)\:{a}\:{unique}\:{solution} \\ $$$$\:\left({c}\right)\:{infinitely}\:{many}\:{solutions} \\ $$ Answered by…
Question Number 182890 by Frix last updated on 16/Dec/22 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{formula}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:{n} \\ $$$${S}_{{n}} =\underset{{j}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\underset{{k}=\mathrm{0}} {\overset{{n}} {\prod}}\:\left({j}+{k}\right)} \\ $$ Terms of Service Privacy Policy Contact:…