Question Number 182131 by Agnibhoo98 last updated on 04/Dec/22 $$\mathrm{Solve} \\ $$$$\frac{{x}\:+\:{a}^{\mathrm{2}} \:+\:\mathrm{2}{c}^{\mathrm{2}} }{{b}\:+\:{c}}\:+\:\frac{{x}\:+\:{b}^{\mathrm{2}} \:+\:\mathrm{2}{a}^{\mathrm{2}} }{{c}\:+\:{a}}\:+\:\frac{{x}\:+\:{c}^{\mathrm{2}} \:+\:\mathrm{2}{b}^{\mathrm{2}} }{{a}\:+\:{b}}\:=\:\mathrm{0} \\ $$ Answered by manxsol last updated…
Question Number 182108 by Tawa11 last updated on 04/Dec/22 A truck, P traveling at 54km/hr passes through a point at 10:30am, while another truck, Q…
Question Number 182114 by Maisam last updated on 04/Dec/22 Commented by Maisam last updated on 04/Dec/22 $${please}\:\:{help} \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 182093 by Fridunatjan08 last updated on 04/Dec/22 $${Solve}\:{the}\:{equation}: \\ $$$$\frac{{x}−\mathrm{6}}{\mathrm{2020}}+\frac{{x}−\mathrm{5}}{\mathrm{2021}}+\frac{{x}−\mathrm{4}}{\mathrm{2022}}=\mathrm{3} \\ $$ Commented by Fridunatjan08 last updated on 04/Dec/22 $${Please}\:{show}\:{me}\:{the}\:{easy}\:{way}\:{to}\:{solve}\:{this}\:{equation} \\ $$ Commented…
Question Number 182073 by Acem last updated on 04/Dec/22 $${Find}\:{the}\:{sum}\:{of}\:{the}\:{solutions}\:{of}\:{the}\:{equation}: \\ $$$$\:\mid\sqrt{{x}}\:−\:\mathrm{2}\mid+\:\sqrt{{x}}\:\left(\sqrt{{x}}\:−\:\mathrm{4}\right)+\:\mathrm{2}=\:\mathrm{0}\:\:\:;\:{x}>\:\mathrm{0} \\ $$ Answered by HeferH last updated on 04/Dec/22 $$\:\mid\sqrt{{x}}\:−\:\mathrm{2}\mid\:=\:\mathrm{4}\sqrt{{x}}\:−\:{x}\:−\:\mathrm{2} \\ $$$$\:\:\sqrt{{x}}\:−\:\mathrm{2}\:=\:\pm\:\left(\mathrm{4}\sqrt{{x}}\:−\:{x}\:−\:\mathrm{2}\right) \\…
Question Number 182074 by Acem last updated on 04/Dec/22 $${Let}\:{x}+\:{xy}+\:{y}=\:\mathrm{54}\:\:\:;\:{x},\:{y}\in\:\mathbb{N}\:,\:{Find}\:{x}+\:{y} \\ $$ Answered by HeferH last updated on 04/Dec/22 $${x}\:+\:{xy}\:+\:{y}\:=\:\mathrm{54} \\ $$$$\:{x}\left(\mathrm{1}\:+\:{y}\right)\:+\:{y}\:=\:\mathrm{54} \\ $$$$\:{x}\left(\mathrm{1}\:+\:{y}\right)\:+\:\left(\mathrm{1}\:+\:{y}\right)\centerdot\mathrm{1}\:=\:\mathrm{55} \\…
Question Number 116529 by mr W last updated on 04/Oct/20 Commented by MJS_new last updated on 04/Oct/20 $$\frac{\mathrm{5}}{\mathrm{197}} \\ $$ Answered by maths mind last…
Question Number 116509 by Khalmohmmad last updated on 04/Oct/20 $$\mathrm{x}^{\mathrm{4}} −\mathrm{48x}^{\mathrm{2}} +\mathrm{x}+\mathrm{565}=\mathrm{0}\: \\ $$$$\mathrm{x}=? \\ $$ Answered by TANMAY PANACEA last updated on 04/Oct/20 $${f}\left({x}\right)={x}^{\mathrm{4}}…
Question Number 116507 by bemath last updated on 04/Oct/20 Answered by bobhans last updated on 04/Oct/20 $$\mathrm{let}\:\frac{\mathrm{1}}{\frac{\mathrm{1}}{\mathrm{x}}+\frac{\mathrm{1}}{\mathrm{2}}}\:=\:\mathrm{r}\:\Rightarrow\:\frac{\mathrm{1}}{\frac{\mathrm{2}+\mathrm{x}}{\mathrm{2x}}}=\:\mathrm{r} \\ $$$$\Rightarrow\frac{\mathrm{2x}}{\mathrm{2}+\mathrm{x}}\:=\:\mathrm{r}\:.\:\mathrm{the}\:\mathrm{equation}\:\mathrm{equivalent} \\ $$$$\mathrm{to}\:\frac{\mathrm{1}}{\left[\frac{\mathrm{1}}{\mathrm{r}+\mathrm{r}}+\frac{\mathrm{1}}{\mathrm{r}+\mathrm{r}}\right]}\:=\:\frac{\mathrm{x}}{\mathrm{36}}\:\Rightarrow\frac{\mathrm{1}}{\left(\frac{\mathrm{1}}{\mathrm{2r}}+\frac{\mathrm{1}}{\mathrm{2r}}\right)}\:=\:\frac{\mathrm{x}}{\mathrm{36}} \\ $$$$\Rightarrow\:\frac{\mathrm{1}}{\left(\frac{\mathrm{1}}{\mathrm{r}}\right)}\:=\:\frac{\mathrm{x}}{\mathrm{36}}\:;\:\mathrm{r}\:=\:\frac{\mathrm{x}}{\mathrm{36}} \\ $$$$\Rightarrow\frac{\mathrm{2x}}{\mathrm{2}+\mathrm{x}}\:=\:\frac{\mathrm{x}}{\mathrm{36}}\:;\:\mathrm{x}\neq\mathrm{0}…
Question Number 50972 by Necxx last updated on 22/Dec/18 Answered by mr W last updated on 22/Dec/18 $$\mathrm{2}^{\mathrm{2}{x}} =\mathrm{8}{x} \\ $$$${e}^{\mathrm{2}{x}\mathrm{ln}\:\mathrm{2}} =\mathrm{8}{x} \\ $$$$\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{4}}{e}^{\mathrm{2}{x}\mathrm{ln}\:\mathrm{2}} =\mathrm{2}{x}\mathrm{ln}\:\mathrm{2}…