Question Number 182804 by mnjuly1970 last updated on 14/Dec/22 $$ \\ $$$$\:\:\:\:{solve} \\ $$$$\:\:\:\:\lfloor\underset{} {\overset{} {{x}}}\:\rfloor\:−\:\lfloor\:\frac{{x}}{\mathrm{3}}\:\rfloor\:=\:\mathrm{3} \\ $$$$\:\:\:\:\:\:\: \\ $$ Answered by mahdipoor last updated…
Question Number 182794 by mnjuly1970 last updated on 14/Dec/22 $$ \\ $$$$\:\:\:\:\:\:\:\Omega\:=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\:\left(−\underset{} {\overset{} {\mathrm{1}}}\:\right)^{\:{n}} }{\mathrm{2}^{\:{n}} .{n}\left({n}\underset{} {\overset{} {+}}\mathrm{1}\right)\left({n}\underset{} {\overset{} {+}}\mathrm{2}\right)}\:=\:?\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\…
Question Number 182788 by CrispyXYZ last updated on 14/Dec/22 $${y}''+{ay}={b} \\ $$ Answered by qaz last updated on 14/Dec/22 $${y}_{{p}} =\frac{\mathrm{1}}{{D}^{\mathrm{2}} +{a}}{b}=\frac{{b}}{\mathrm{2}{i}\sqrt{{a}}}\left(\frac{\mathrm{1}}{{D}−{i}\sqrt{{a}}}−\frac{\mathrm{1}}{{D}+{i}\sqrt{{a}}}\right) \\ $$$$=\frac{{b}}{\mathrm{2}{i}\sqrt{{a}}}\left({e}^{{i}\sqrt{{a}}{x}} \frac{\mathrm{1}}{{D}}{e}^{−{i}\sqrt{{a}}{x}}…
Question Number 51691 by peter frank last updated on 29/Dec/18 Answered by afachri last updated on 29/Dec/18 $$\mathrm{suppose}\:\gamma\:=\:{U}_{\mathrm{1}} \:;\:\beta\:=\:{U}_{\mathrm{2}} \:;\:\alpha\:=\:{U}_{\mathrm{3}} \\ $$$$\boldsymbol{\gamma}\:,\:\boldsymbol{\beta}\:\:=\:\:\frac{−{a}\:\pm\:\sqrt{{a}^{\mathrm{2}} −\:\mathrm{4}{b}\:}}{\mathrm{2}} \\ $$$$\boldsymbol{\beta}\:−\:\boldsymbol{\gamma}\:\:=\:\:\frac{\left(−{a}\:−\:\sqrt{{a}^{\mathrm{2}}…
Question Number 182721 by mnjuly1970 last updated on 13/Dec/22 Answered by Acem last updated on 13/Dec/22 $$\:{It}\:{period}:\:{T}=\:\frac{\mathrm{1}}{{a}} \\ $$$$\:{f}\left({x}\right)=\mathrm{1}\:\Rightarrow\:{b}=\mathrm{1} \\ $$$$\underset{{x}\rightarrow\frac{\mathrm{15}^{\:−} }{\mathrm{2}}} {\mathrm{lim}}\:{f}\left({x}\right)=\:−\infty\:\Rightarrow\:\mathrm{cos}\:\pi{ax}=\:\mathrm{cos}\:\frac{\pi^{\:+} }{\mathrm{2}}\:\Rightarrow\:{a}<\mathrm{0} \\…
Question Number 182720 by mnjuly1970 last updated on 13/Dec/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 117172 by zakirullah last updated on 10/Oct/20 Answered by $@y@m last updated on 10/Oct/20 $$\mathrm{21168}=\mathrm{2}×\mathrm{2}×\mathrm{2}×\mathrm{2}×\mathrm{3}×\mathrm{3}×\mathrm{3}×\mathrm{7}×\mathrm{7} \\ $$$$\mathrm{3}\:{has}\:{no}\:{pair}. \\ $$$$\therefore\:\mathrm{21168}\:{must}\:{be}\:{divided}\:{by}\:\mathrm{3} \\ $$$${to}\:{yield}\:{perfect}\:{square}. \\ $$…
Question Number 182704 by HeferH last updated on 13/Dec/22 $${On}\:{a}\:{path}\:{there}\:{was}\:{an}\:{odd}\:{number}\:{of}\:{rocks} \\ $$$$\:{with}\:{a}\:{distance}\:{of}\:\mathrm{10}{m}\:{between}\:{them},\:{we}\: \\ $$$$\:{want}\:{to}\:{put}\:{them}\:{all}\:{where}\:{the}\:{middle}\:{one}\:{is}, \\ $$$$\:{if}\:{we}\:{start}\:{to}\:{collect}\:{from}\:{one}\:{of}\:{the}\:{ends}\:{and} \\ $$$$\:{when}\:{we}\:{finish}\:{we}\:{have}\:{walked}\:\mathrm{3}{km}\:{in}\:{total}, \\ $$$$\:{how}\:{many}\:{rocks}\:{are}\:{there}? \\ $$ Answered by TheSupreme…
Question Number 182705 by HeferH last updated on 13/Dec/22 $${A}\:{father}\:{has}\:\$\mathrm{320}\:{to}\:{go}\:{a}\:{sporting}\:{event}\:{with} \\ $$$$\:{his}\:{children}.\:{If}\:{he}\:{takes}\:{tickets}\:{of}\:\$\mathrm{50}\:{he} \\ $$$$\:{lacks}\:{money},\:{if}\:{he}\:{takes}\:{tickets}\:{of}\:\$\mathrm{40}\:{he} \\ $$$$\:{has}\:{money}\:{left}\:{over}.\:{Find}\:{the}\:{number}\:{of}\: \\ $$$$\:{children}. \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 182702 by CrispyXYZ last updated on 13/Dec/22 $$\mathrm{log}_{\mathrm{2}} \left({x}+\mathrm{1}\right)−{x}>\mathrm{0} \\ $$ Commented by mr W last updated on 13/Dec/22 $${at}\:{x}=\mathrm{0}\:{and}\:{x}=\mathrm{1}:\:\mathrm{log}_{\mathrm{2}} \:\left({x}+\mathrm{1}\right)={x} \\ $$$$\Rightarrow−\mathrm{1}<{x}<\mathrm{0}\:\vee\:\mathrm{1}<{x}<+\infty…