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Category: Algebra

sin-2x-cos-xd-x-

Question Number 53051 by Abror last updated on 16/Jan/19 sin(2x)cosxd(x)= Answered by tanmay.chaudhury50@gmail.com last updated on 16/Jan/19 122sin2xcosxdx=12(sin3x+sinx)dx$$=\frac{\mathrm{1}}{\mathrm{2}}\left[\frac{−{cos}\mathrm{3}{x}}{\mathrm{3}}+\frac{−{cosx}}{}\right]+{c} \