Question Number 207779 by Tawa11 last updated on 26/May/24 Answered by mr W last updated on 26/May/24 Commented by Tawa11 last updated on 26/May/24 $$\mathrm{Thanks}\:\mathrm{sir}.…
Question Number 207771 by hardmath last updated on 25/May/24 $$\mathrm{Simplify}:\:\:\:\:\:\frac{\sqrt[{\mathrm{4}}]{\boldsymbol{\mathrm{b}}}\:\:\sqrt{\boldsymbol{\mathrm{c}}}\:\:−\:\:\sqrt[{\mathrm{4}}]{\boldsymbol{\mathrm{c}}}\:\:\sqrt{\boldsymbol{\mathrm{b}}}}{\:\sqrt[{\mathrm{4}}]{\boldsymbol{\mathrm{b}}}\:\:\sqrt{\boldsymbol{\mathrm{c}}}\:\:−\:\:\sqrt[{\mathrm{4}}]{\boldsymbol{\mathrm{c}}}}\:\:=\:\:? \\ $$ Answered by Rasheed.Sindhi last updated on 26/May/24 $$\frac{{b}^{\mathrm{1}/\mathrm{4}} {c}^{\mathrm{1}/\mathrm{2}} −{c}^{\mathrm{1}/\mathrm{4}} {b}^{\mathrm{1}/\mathrm{2}} }{{b}^{\mathrm{1}/\mathrm{4}} {c}^{\mathrm{1}/\mathrm{2}}…
Question Number 207747 by MASANJAJJ last updated on 25/May/24 $${find}\:{the}\:{value}\:{of}\:{y}\:{given}\:{that}\:{y}^{{y}\:} =\mathrm{3}^{{y}+\mathrm{9}} \\ $$ Commented by A5T last updated on 25/May/24 $$\mathrm{3}^{\mathrm{9}+\mathrm{9}} =\mathrm{3}^{\mathrm{18}} =\left(\mathrm{3}^{\mathrm{2}} \right)^{\mathrm{3}^{\mathrm{2}} }…
Question Number 207730 by mr W last updated on 24/May/24 Commented by mr W last updated on 24/May/24 $${is}\:{this}\:{possible}? \\ $$ Commented by efronzo1 last…
Question Number 207724 by hardmath last updated on 24/May/24 $$\mathrm{2}\:\mathrm{tg}^{\mathrm{3}} \:\boldsymbol{\mathrm{x}}\:−\:\mathrm{2}\:\mathrm{tg}^{\mathrm{2}} \:\boldsymbol{\mathrm{x}}\:+\:\mathrm{6}\:\mathrm{tg}\:\boldsymbol{\mathrm{x}}\:=\:\mathrm{3}\:\:\:,\:\:\:\left[\mathrm{0}\:;\:\mathrm{2}\boldsymbol{\pi}\right] \\ $$$$\mathrm{Sum}\:\mathrm{of}\:\mathrm{roots}\:=\:? \\ $$ Answered by Frix last updated on 24/May/24 $$\mathrm{tan}^{\mathrm{3}} \:{x}\:−\mathrm{tan}^{\mathrm{2}}…
Question Number 207717 by hardmath last updated on 24/May/24 $$\mathrm{lg}^{\mathrm{2}} \:\left(\mathrm{10x}\right)\:−\:\mathrm{lg}\:\mathrm{10x}\:+\:\mathrm{1}\:=\:\mathrm{6}\:−\:\mathrm{lg}\:\mathrm{x} \\ $$$$\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Answered by TonyCWX08 last updated on 24/May/24 $$\left(\mathrm{1}+{lg}\left({x}\right)\right)^{\mathrm{2}} −\left(\mathrm{1}+{lg}\left({x}\right)\right)+{lg}\left({x}\right)+\mathrm{1}−\mathrm{6}=\mathrm{0} \\…
Question Number 207718 by hardmath last updated on 24/May/24 $$\mid\mathrm{x}−\mathrm{3}\mid\:+\:\mid\mathrm{x}\:+\mathrm{2}\mid\:=\:\mathrm{9} \\ $$$$\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Answered by TonyCWX08 last updated on 24/May/24 $${There}\:{are}\:\mathrm{4}\:{possible}\:{cases}. \\ $$$${x}−\mathrm{3}+{x}+\mathrm{2}=\mathrm{9} \\…
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Question Number 207699 by hardmath last updated on 23/May/24 $$\frac{\mathrm{4}}{\mathrm{2x}−\mathrm{1}}\:\:+\:\:\frac{\mathrm{27}}{\mathrm{3x}−\mathrm{1}}\:\:+\:\:\frac{\mathrm{125}}{\mathrm{5x}−\mathrm{1}}\:\:=\:\:\frac{\mathrm{144}}{\mathrm{4x}−\mathrm{1}} \\ $$$$\mathrm{Find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 23/May/24 $$\frac{\mathrm{4}}{\mathrm{2x}−\mathrm{1}}\:+\:\frac{\mathrm{27}}{\mathrm{3x}−\mathrm{1}}\:+\:\frac{\mathrm{125}}{\mathrm{5x}−\mathrm{1}}\:=\:\frac{\mathrm{144}}{\mathrm{4x}−\mathrm{1}} \\ $$$$\frac{\mathrm{4}}{\mathrm{2x}−\mathrm{1}}+\:\frac{\mathrm{125}}{\mathrm{5x}−\mathrm{1}}=\:\frac{\mathrm{144}}{\mathrm{4x}−\mathrm{1}}−\frac{\mathrm{27}}{\mathrm{3x}−\mathrm{1}} \\…
Question Number 207663 by efronzo1 last updated on 24/May/24 $$\:\:\mathrm{Given}\: \\ $$$$\:\:\:\mathrm{x}_{\mathrm{1}} +\mathrm{x}_{\mathrm{3}} +…+\mathrm{x}_{\mathrm{2023}} \:=\:\mathrm{25}−\left(\mathrm{x}_{\mathrm{2}} +\mathrm{x}_{\mathrm{4}} +…+\mathrm{x}_{\mathrm{2022}} \right) \\ $$$$\:\:\mathrm{x}_{\mathrm{1}} ^{\mathrm{2}\:} +\:\mathrm{x}_{\mathrm{3}} ^{\mathrm{2}} +…+\mathrm{x}_{\mathrm{2023}} ^{\mathrm{2}}…