Question Number 181897 by Acem last updated on 01/Dec/22 Answered by mr W last updated on 02/Dec/22 $${T}_{{k}} =\frac{{k}^{\mathrm{2}} }{{k}^{\mathrm{2}} −\mathrm{10}{k}+\mathrm{50}}=\frac{{k}^{\mathrm{2}} }{\left({k}−\mathrm{5}\right)^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} } \\…
Question Number 50825 by behi83417@gmail.com last updated on 20/Dec/18 $$\boldsymbol{\mathrm{x}}^{\mathrm{4}} =\boldsymbol{\mathrm{ax}}^{\mathrm{2}} +\boldsymbol{\mathrm{by}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{y}}^{\mathrm{4}} =\boldsymbol{\mathrm{bx}}^{\mathrm{2}} +\boldsymbol{\mathrm{ay}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}},\:\boldsymbol{\mathrm{y}}.\:\left[\boldsymbol{\mathrm{a}}\:,\boldsymbol{\mathrm{b}}\in\:\boldsymbol{\mathrm{R}};\:\:\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}}\neq\mathrm{0}\right] \\ $$ Answered by mr W last…
Question Number 116358 by bemath last updated on 03/Oct/20 $$\mathrm{Given}\:\mathrm{that}\:\sqrt[{\mathrm{3}\:}]{\mathrm{17}−\frac{\mathrm{27}}{\mathrm{4}}\sqrt{\mathrm{6}}}\:\mathrm{and}\:\sqrt[{\mathrm{3}\:}]{\mathrm{17}+\frac{\mathrm{27}}{\mathrm{4}}\sqrt{\mathrm{6}}} \\ $$$$\mathrm{are}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\mathrm{x}^{\mathrm{2}} −\mathrm{ax}+\mathrm{b}\:=\:\mathrm{0}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{ab}. \\ $$ Answered by MJS_new last updated on 03/Oct/20 $$\sqrt[{\mathrm{3}}]{\mathrm{17}\pm\frac{\mathrm{27}\sqrt{\mathrm{6}}}{\mathrm{4}}}=\mathrm{2}\pm\frac{\sqrt{\mathrm{6}}}{\mathrm{2}}…
Question Number 116323 by bobhans last updated on 03/Oct/20 $$\left(\mathrm{1}\right)\mathrm{Let}\:\mathrm{a},\mathrm{b}\:\mathrm{and}\:\mathrm{c}\:\mathrm{real}\:\mathrm{number}\:\mathrm{such}\:\mathrm{that}\: \\ $$$$\frac{\mathrm{ab}}{\mathrm{a}+\mathrm{b}}\:=\:\frac{\mathrm{1}}{\mathrm{3}},\:\frac{\mathrm{bc}}{\mathrm{b}+\mathrm{c}}\:=\:\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{and}\:\frac{\mathrm{ac}}{\mathrm{a}+\mathrm{c}}\:=\:\frac{\mathrm{1}}{\mathrm{5}}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\frac{\mathrm{24abc}}{\mathrm{ab}+\mathrm{ac}+\mathrm{bc}}\:? \\ $$$$\left(\mathrm{2}\right)\:\mathrm{Let}\:\mathrm{p}\:\mathrm{and}\:\mathrm{q}\:\mathrm{be}\:\mathrm{two}\:\mathrm{real}\:\mathrm{number}\:\mathrm{that} \\ $$$$\mathrm{satisfy}\:\mathrm{p}.\mathrm{q}=\mathrm{2013}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{minimum} \\ $$$$\mathrm{value}\:\mathrm{of}\:\left(\mathrm{p}+\mathrm{q}\right)^{\mathrm{2}} \:? \\ $$ Answered by…
Question Number 50783 by ajfour last updated on 20/Dec/18 $${x}^{\mathrm{3}} +\left(\mathrm{2}+\mathrm{3}{i}\right){x}+\mathrm{1}=\mathrm{0} \\ $$$${Find}\:{all}\:{three}\:{roots}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 181837 by mr W last updated on 01/Dec/22 $${find}\:{integers}\:{a}>{b}>{c}>\mathrm{0}\:{such}\:{that} \\ $$$$\frac{\mathrm{1}}{{a}}+\frac{\mathrm{2}}{{b}}+\frac{\mathrm{3}}{{c}}=\mathrm{1} \\ $$ Commented by SEKRET last updated on 01/Dec/22 $$\left(\mathrm{2};\mathrm{5};\mathrm{30}\right)\:\left(\mathrm{2};\mathrm{6};\mathrm{18}\right)\:\left(\mathrm{2};\mathrm{7};\mathrm{14}\right)\:\left(\mathrm{2};\mathrm{8};\mathrm{12}\right) \\ $$$$\left(\mathrm{2};\mathrm{10};\mathrm{10}\right)\:\left(\mathrm{2};\mathrm{12};\mathrm{9}\right)\left(\mathrm{2};\mathrm{16};\mathrm{8}\right)\left(\mathrm{2};\mathrm{28};\mathrm{7}\right)…
Question Number 116301 by harckinwunmy last updated on 02/Oct/20 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{condition}\:\mathrm{for}\:\mathrm{a} \\ $$$$\mathrm{given}\:\mathrm{line}\:\mathrm{to}\:\: \\ $$$$\left.\mathrm{1}\right)\:\mathrm{intersect}\:\mathrm{a}\:\mathrm{curve} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{be}\:\mathrm{a}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{a}\:\mathrm{curve} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{not}\:\mathrm{to}\:\mathrm{intersect}\:\mathrm{a}\:\mathrm{curve}\: \\ $$ Answered by Rio Michael last…
Question Number 181832 by henderson last updated on 01/Dec/22 $$\mathrm{help}\:! \\ $$$$\int\:\frac{{ln}\left({x}+\mathrm{1}\right)}{{x}^{\mathrm{2}} +\mathrm{1}}{dx}\:=\:??? \\ $$ Commented by CElcedricjunior last updated on 01/Dec/22 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{{ln}}\left(\boldsymbol{{x}}+\mathrm{1}\right)}{\boldsymbol{{x}}^{\mathrm{2}}…
Question Number 50754 by peter frank last updated on 19/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 20/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 20/Dec/18 $${R}\left({asec}\theta,{btan}\theta\right)\:\:{centre}\left(\mathrm{0},\mathrm{0}\right)\:{S}\left({c},\mathrm{0}\right)\:{S}^{'}…
Question Number 50747 by behi83417@gmail.com last updated on 19/Dec/18 $$\boldsymbol{{x}}^{\mathrm{2}} −\boldsymbol{{y}}^{\mathrm{2}} =\boldsymbol{{a}},{a}\neq\mathrm{0} \\ $$$$\boldsymbol{{y}}^{\mathrm{2}} −\boldsymbol{{z}}^{\mathrm{2}} =\boldsymbol{{b}},{b}\neq\mathrm{0} \\ $$$$\boldsymbol{{z}}^{\mathrm{2}} −\boldsymbol{{x}}^{\mathrm{2}} =\boldsymbol{{c}},{c}\neq\mathrm{0} \\ $$$${solve}\:{for}\::{x},{y},{z}.\:\: \\ $$ Commented…