Question Number 114956 by I want to learn more last updated on 22/Sep/20 Commented by I want to learn more last updated on 22/Sep/20 $$\mathrm{really}?.\:\mathrm{But}\:\mathrm{i}\:\mathrm{cannot}\:\mathrm{solve}\:\mathrm{it}\:\mathrm{sir}.…
Question Number 180490 by Shrinava last updated on 12/Nov/22 Answered by a.lgnaoui last updated on 13/Nov/22 $${m}=\mathrm{60\%}{M}={Masse}\left({final}\right) \\ $$$${m}+{x}\:\:\:\:\:{x}={masse}\:{sugar} \\ $$$$\mathrm{76\%}\left(\mathrm{60\%}{M}+{x}\right)+{x}=\mathrm{100\%}{M} \\ $$$$\mathrm{76}\left(\mathrm{60\%}{M}+{x}\right)=\mathrm{100}{M} \\ $$$$\mathrm{76}×\mathrm{60\%}{M}+\mathrm{76}{x}+{x}=\mathrm{100}{M}…
Question Number 180483 by Shrinava last updated on 12/Nov/22 Commented by MJS_new last updated on 12/Nov/22 $$\mathrm{it}'\mathrm{s}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{find}\:\mathrm{an}\:\mathrm{infinite}\:\mathrm{number}\:\mathrm{of} \\ $$$$\mathrm{sequences}\:{a}_{{n}} \:\mathrm{with} \\ $$$${a}_{\mathrm{1}} =\frac{\mathrm{4}}{\mathrm{3}}\wedge{a}_{\mathrm{2}} =\frac{\mathrm{4}}{\mathrm{5}}\wedge{a}_{\mathrm{3}} =\frac{\mathrm{24}}{\mathrm{25}}\wedge{a}_{\mathrm{4}}…
Question Number 114917 by bemath last updated on 22/Sep/20 Commented by bemath last updated on 22/Sep/20 $${anyone}\:{can}\:{translate}\:{to}\:{english}? \\ $$ Commented by Olaf last updated on…
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Question Number 180407 by CrispyXYZ last updated on 12/Nov/22 $${f}\left({x}−{y}\right)+{f}\left({x}+{y}\right)={f}\left({x}\right){f}\left({y}\right) \\ $$$$\mathrm{find}\:{f}\left({x}\right) \\ $$ Answered by mahdipoor last updated on 12/Nov/22 $${x}=\mathrm{0}\:\:\:{y}=\mathrm{0}\:\Rightarrow \\ $$$${f}\left(\mathrm{0}\right)+{f}\left(\mathrm{0}\right)={f}\left(\mathrm{0}\right){f}\left(\mathrm{0}\right)\:\Rightarrow{f}\left(\mathrm{0}\right)=\mathrm{0}\:\:{or}\:\:\mathrm{2} \\…
Question Number 49331 by rahul 19 last updated on 05/Dec/18 $${Find}\:: \\ $$$${arg}\left(\:\frac{\left(\mathrm{2}\sqrt{\mathrm{3}}+\mathrm{2}{i}\right)^{\mathrm{8}} }{\left(\mathrm{1}−{i}\right)^{\mathrm{6}} }\:\:+\:\frac{\left(\mathrm{1}+{i}\right)^{\mathrm{6}} }{\left(\mathrm{2}\sqrt{\mathrm{3}}−\mathrm{2}{i}\right)^{\mathrm{8}} }\right)\:? \\ $$ Commented by maxmathsup by imad last…
Question Number 180396 by nadovic last updated on 11/Nov/22 $$\mathrm{The}\:\mathrm{difference}\:\mathrm{between}\:\mathrm{the}\:\mathrm{ages}\:\mathrm{of} \\ $$$$\mathrm{Sammy}\:\mathrm{and}\:\mathrm{Cindy}\:\mathrm{is}\:\mathrm{half}\:\mathrm{the}\: \\ $$$$\mathrm{difference}\:\mathrm{between}\:\mathrm{the}\:\mathrm{ages}\:\mathrm{of}\: \\ $$$$\mathrm{their}\:\mathrm{parents}.\:\mathrm{Their}\:\mathrm{father}\:\mathrm{is}\:\mathrm{6} \\ $$$$\mathrm{years}\:\mathrm{older}\:\mathrm{than}\:\mathrm{twice}\:\mathrm{the}\:\mathrm{age}\:\mathrm{of}\: \\ $$$$\mathrm{Cindy}.\:\mathrm{Their}\:\mathrm{mother}\:\mathrm{is}\:\mathrm{twice}\:\mathrm{as}\:\mathrm{old} \\ $$$$\mathrm{as}\:\mathrm{Cindy}\:\mathrm{and}\:\mathrm{12}\:\mathrm{years}\:\mathrm{older}\:\mathrm{than}\: \\ $$$$\mathrm{Sammy}.\:\mathrm{By}\:\mathrm{how}\:\mathrm{many}\:\mathrm{years}\:\mathrm{is}\: \\…
Question Number 180391 by Shrinava last updated on 11/Nov/22 $$\mathrm{y}\:=\:\mathrm{x}\:−\:\frac{\mathrm{2}}{\mathrm{x}} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}. \\ $$ Commented by Shrinava last updated on 11/Nov/22 $$\mathrm{Answer}:\:\:\left(−\infty\:;\:+\infty\right) \\ $$ Answered…