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Category: Algebra

Evaluer-1-logx-1-x-dx-

Question Number 179494 by a.lgnaoui last updated on 29/Oct/22 $${Evaluer} \\ $$$$\int\frac{\mathrm{1}−\mathrm{logx}}{\mathrm{1}+\mathrm{x}}\mathrm{dx} \\ $$ Answered by ARUNG_Brandon_MBU last updated on 29/Oct/22 $$\int\frac{\mathrm{1}−\mathrm{log}{x}}{\mathrm{1}+{x}}{dx} \\ $$$$=\mathrm{log}\left(\mathrm{1}+{x}\right)−\underset{{n}=\mathrm{0}} {\overset{\infty}…

x-2-x-2-x-2-OR-x-2-x-2-x-2-

Question Number 113931 by Rasheed.Sindhi last updated on 16/Sep/20 $$\mid\:{x}\:\mid=\mathrm{2}\Rightarrow\:{x}=\mathrm{2}\:\vee\:{x}=−\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{OR} \\ $$$$\mid\:{x}\:\mid=\mathrm{2}\Rightarrow\:{x}=\mathrm{2}\:\wedge\:{x}=−\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:? \\ $$ Commented by bemath last updated on 16/Sep/20…

Find-the-square-root-of-50-48-

Question Number 113913 by Aina Samuel Temidayo last updated on 16/Sep/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{square}\:\mathrm{root}\:\mathrm{of}\:\sqrt{\mathrm{50}}+\sqrt{\mathrm{48}} \\ $$ Answered by 1549442205PVT last updated on 16/Sep/20 $$\mathrm{We}\:\mathrm{have}\:\left(\sqrt{\mathrm{50}}+\sqrt{\mathrm{48}}\right)^{\mathrm{2}} =\mathrm{98}+\mathrm{2}\sqrt{\mathrm{50}.\mathrm{48}} \\ $$$$=\mathrm{98}+\mathrm{2}\sqrt{\mathrm{25}.\mathrm{16}.\mathrm{6}}=\mathrm{98}+\mathrm{40}\sqrt{\mathrm{6}}…

Solve-for-real-numbers-3sinx-4-y-cosx-y-2-9-

Question Number 179449 by Shrinava last updated on 29/Oct/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\mathrm{3sinx}\:+\:\mathrm{4}\left(\mathrm{y}\:+\:\mathrm{cosx}\right)\:=\:\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{9} \\ $$ Answered by mr W last updated on 29/Oct/22 $$\mathrm{3}\:\mathrm{sin}\:{x}+\mathrm{4}\:\mathrm{cos}\:{x}−\mathrm{5}={y}^{\mathrm{2}} −\mathrm{4}{y}+\mathrm{4}…

Question-48368

Question Number 48368 by behi83417@gmail.com last updated on 22/Nov/18 Answered by MJS last updated on 22/Nov/18 $${a}^{\frac{\mathrm{1}}{\mathrm{3}}} −{b}^{\frac{\mathrm{1}}{\mathrm{3}}} ={c} \\ $$$${a}−\mathrm{3}{a}^{\frac{\mathrm{2}}{\mathrm{3}}} {b}^{\frac{\mathrm{1}}{\mathrm{3}}} +\mathrm{3}{a}^{\frac{\mathrm{1}}{\mathrm{3}}} {b}^{\frac{\mathrm{2}}{\mathrm{3}}} −{b}={c}^{\mathrm{3}}…

Question-48367

Question Number 48367 by behi83417@gmail.com last updated on 22/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 $${xy}−\mathrm{1}=\sqrt{\mathrm{3}}\:\left({x}+{y}\right) \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}=\frac{{x}+{y}}{{xy}−\mathrm{1}} \\ $$$$\frac{{x}+{y}}{\mathrm{1}−{xy}}=−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}} \\ $$$${tana}={x}\:\:\:{tanb}={y}\:\:\:\:{tanc}={z} \\ $$$${tan}\left({a}+{b}\right)=−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}…

f-x-1-x-and-g-x-x-2-2x-1-Find-g-1-f-3-

Question Number 179436 by Shrinava last updated on 29/Oct/22 $$\mathrm{f}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{1}}{\mathrm{x}}\:\:\:\:\:\mathrm{and}\:\:\:\:\:\mathrm{g}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{x}\:+\:\mathrm{2}}{\mathrm{2x}\:+\:\mathrm{1}} \\ $$$$\mathrm{Find}:\:\:\:\:\:\mathrm{g}^{−\mathrm{1}} \left(\mathrm{f}\left(\mathrm{3}\right)\right)\:=\:? \\ $$ Commented by cherokeesay last updated on 29/Oct/22 $${y}=\frac{{x}+\mathrm{2}}{\mathrm{2}{x}+\mathrm{1}}\Leftrightarrow\mathrm{2}{xy}+{y}={x}+\mathrm{2}\Rightarrow \\ $$$${x}\left(\mathrm{2}{y}−\mathrm{1}\right)=\mathrm{2}−{y}\Leftrightarrow{x}=\frac{\mathrm{2}−{y}}{\mathrm{2}{y}−\mathrm{1}}…

Question-113894

Question Number 113894 by Aina Samuel Temidayo last updated on 16/Sep/20 Commented by MJS_new last updated on 16/Sep/20 $$\mathrm{let}\:{x}=\mathrm{2}\wedge{y}=\mathrm{4} \\ $$$$\mathrm{2}^{\mathrm{4}} =\mathrm{4}^{\mathrm{2}} =\mathrm{16} \\ $$$$\left({x}/{y}\right)^{\left({x}/{y}\right)}…