Question Number 48222 by gunawan last updated on 21/Nov/18 $${f}\left({x}\right)=\underset{{i}=\mathrm{0}} {\overset{{n}} {\Sigma}}{a}_{{i}} {x}^{{i}} ={a}_{{n}} {x}^{{n}} +{a}_{{n}−\mathrm{1}} {x}^{{n}−\mathrm{1}} +{a}_{{n}−\mathrm{2}} {x}^{{n}−\mathrm{2}} +\ldots+{a}_{\mathrm{2}} {x}^{\mathrm{2}} +{a}_{\mathrm{1}} {x}+{a}_{\mathrm{0}} \\ $$$${f}^{−\mathrm{1}}…
Question Number 179284 by Agnibhoo98 last updated on 27/Oct/22 $$\mathrm{Solve}\:\mathrm{for}\:\boldsymbol{{x}} \\ $$$$\frac{{a}}{{ax}\:−\:\mathrm{1}}\:+\:\frac{{b}}{{bx}\:−\:\mathrm{1}}\:=\:{a}\:+\:{b}\:\left[{x}\:\neq\:\frac{\mathrm{1}}{{a}},\:\frac{\mathrm{1}}{{b}}\right] \\ $$ Answered by FelipeLz last updated on 27/Oct/22 $$\frac{{a}\left({bx}−\mathrm{1}\right)+{b}\left({ax}−\mathrm{1}\right)}{\left({ax}−\mathrm{1}\right)\left({bx}−\mathrm{1}\right)}\:=\:{a}+{b} \\ $$$$\frac{\mathrm{2}{abx}−\left({a}+{b}\right)}{{abx}^{\mathrm{2}} −\left({a}+{b}\right){x}+\mathrm{1}}\:=\:{a}+{b}…
Question Number 179282 by Shrinava last updated on 27/Oct/22 $$\mathrm{m}^{\mathrm{2}} \:=\:\mathrm{n}\:+\:\mathrm{2} \\ $$$$\mathrm{n}^{\mathrm{2}} \:=\:\mathrm{m}\:+\:\mathrm{2} \\ $$$$\mathrm{4mn}\:−\:\mathrm{m}^{\mathrm{3}} \:−\:\mathrm{n}^{\mathrm{3}} \:=\:?\:\:\:\left(\mathrm{m}\neq\mathrm{n}\right) \\ $$ Answered by Acem last updated…
Question Number 48204 by ajfour last updated on 20/Nov/18 $$\mathrm{2}\left({x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}\right)\left({y}^{\mathrm{4}} −\mathrm{3}{y}^{\mathrm{2}} +\mathrm{4}\right)=\mathrm{7} \\ $$$${Find}\:\left({x},{y}\right)\:. \\ $$ Answered by ajfour last updated on 20/Nov/18…
Question Number 179269 by mnjuly1970 last updated on 27/Oct/22 $$ \\ $$$$\:\:\:{what}\:{is}\:{the}\:{periodicity}\: \\ $$$${of}\:{thefollowing}\:{function}? \\ $$$$ \\ $$$$\:{f}\left({x}\right)={cot}\left({x}\right)−{tan}\left({x}\right)−\mathrm{2}{tan}\left(\mathrm{2}{x}\right)−\mathrm{4}{tan}\left(\mathrm{4}{x}\right) \\ $$$$ \\ $$$$ \\ $$ Commented…
Question Number 179253 by mathlove last updated on 27/Oct/22 $$\left({fog}\right)_{{x}} ={cos}\mathrm{2}{x}\:\:{and}\:{g}\left({x}\right)={tanx} \\ $$$${f}\left({x}\right)=? \\ $$ Commented by CElcedricjunior last updated on 30/Oct/22 $$\left({fog}\right)\left({x}\right)=\boldsymbol{{cos}}\mathrm{2}\boldsymbol{{x}}\:\boldsymbol{{o}}\grave {\boldsymbol{{u}}}\:\boldsymbol{\mathrm{g}}\left(\boldsymbol{\mathrm{x}}\right)=\boldsymbol{\mathrm{tanx}} \\…
Question Number 179242 by Acem last updated on 27/Oct/22 $${f}\left({x}+\mathrm{1}\right)=\:\mathrm{2}{x}−\mathrm{5}\:,\:{find}\:{the}\:{value}\:{of}\:{the}\:{f}\left({x}\right)\:{at}\:{x}=\mathrm{2} \\ $$ Commented by Rasheed.Sindhi last updated on 27/Oct/22 $${x}=\mathrm{1}:\:{f}\left(\mathrm{2}\right)=\mathrm{2}\left(\mathrm{1}\right)−\mathrm{5}=−\mathrm{3} \\ $$ Answered by Rasheed.Sindhi…
Question Number 48161 by gunawan last updated on 20/Nov/18 $${f}\left({z}\right)=\frac{\mathrm{1}−{z}}{\mathrm{1}+{z}} \\ $$$${u}\left({x},{y}\right)=.. \\ $$$${v}\left({x},{y}\right)=.. \\ $$$$ \\ $$$$ \\ $$ Commented by maxmathsup by imad…
Question Number 179230 by mathlove last updated on 26/Oct/22 $${f}\left({x}+{y}\right)={f}\left({x}\right)+{f}\left({y}\right)+{x}\centerdot{y} \\ $$$${and}\:{f}\left(\mathrm{4}\right)=\mathrm{10}\:\:{faind}\:\:{f}\left(\mathrm{2022}\right)=? \\ $$ Answered by mr W last updated on 26/Oct/22 $${let}\:{x}=\mathrm{1},\:{y}={n}−\mathrm{1} \\ $$$${f}\left({n}\right)={f}\left(\mathrm{1}\right)+{f}\left({n}−\mathrm{1}\right)+{n}−\mathrm{1}…
Question Number 179226 by mnjuly1970 last updated on 26/Oct/22 Commented by mnjuly1970 last updated on 26/Oct/22 $$\:\:\:{prove}\:\Uparrow\Uparrow \\ $$ Answered by Acem last updated on…