Question Number 179737 by a.lgnaoui last updated on 01/Nov/22 $$\mathrm{P}{rouve}\:{that} \\ $$$$\mathrm{R}=\frac{\mathrm{L}^{\mathrm{2}} +\mathrm{H}^{\mathrm{2}} }{\mathrm{2H}}\:\:\:? \\ $$ Commented by a.lgnaoui last updated on 01/Nov/22 Commented by…
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Question Number 114189 by A8;15: last updated on 17/Sep/20 Commented by A8;15: last updated on 17/Sep/20 solve the equation in natural numbers Commented by A8;15: last updated on 17/Sep/20 please help …
Question Number 179717 by a.lgnaoui last updated on 01/Nov/22 $$\mathrm{Q}\:\mathrm{179570}\:\left({Posted}\:{by}\:\mathrm{Infinityaction}\:\mathrm{30}.\mathrm{10}.\mathrm{2022}\right) \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right) \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{4}}{\mathrm{x}^{\mathrm{2}} }−\mathrm{8x}−\frac{\mathrm{12}}{\mathrm{x}}+\mathrm{25}}\:+\sqrt{\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{4}}{\mathrm{x}^{\mathrm{2}} }−\mathrm{16x}−\frac{\mathrm{16}}{{x}}+\mathrm{80}}\: \\ $$$$−−−−−−−−−−−−−−−−−− \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\left(\mathrm{x}−\mathrm{4}\right)^{\mathrm{2}} +\left(\frac{\mathrm{2}}{\mathrm{x}}−\mathrm{3}\right)^{\mathrm{2}} }\:\:+\sqrt{\left(\mathrm{x}−\mathrm{8}\right)^{\mathrm{2}} +\left(\frac{\mathrm{2}}{\mathrm{x}}−\mathrm{4}\right)^{\mathrm{2}}…
Question Number 179719 by cortano1 last updated on 01/Nov/22 Commented by Rasheed.Sindhi last updated on 01/Nov/22 $${Is}\:{it}\:\:\sqrt[{\mathrm{5}}]{{x}^{\mathrm{3}} +\mathrm{2}{x}}\:=\sqrt[{\mathrm{3}}]{{x}^{\mathrm{5}} −\mathrm{4}{x}}\:? \\ $$ Commented by mr W…
Question Number 114134 by sherzodbek last updated on 17/Sep/20 $$\left({m}^{\mathrm{2}} −{n}^{\mathrm{2}} +\mathrm{6}\left({n}+{m}\right)/\left({m}^{\mathrm{2}} −\left(\mathrm{6}−{n}\right)^{\mathrm{2}} \right.\right. \\ $$$${m}+{n}=\mathrm{12} \\ $$ Commented by sherzodbek last updated on 17/Sep/20…
Question Number 179660 by mathlove last updated on 31/Oct/22 $$\frac{{a}+{b}}{\:\sqrt{{ab}}}=\mathrm{4}\:\:\:\:{then}\:{a}:{b}=? \\ $$ Answered by FelipeLz last updated on 31/Oct/22 $$\frac{{a}+{b}}{\:\sqrt{{ab}}}\:=\:\mathrm{4} \\ $$$$\frac{{a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} }{\:{ab}}\:=\:\mathrm{16} \\…
Question Number 179659 by mathlove last updated on 31/Oct/22 $${cos}\frac{\mathrm{2}\pi}{\mathrm{7}}=\frac{{ab}}{{c}} \\ $$$${cos}\frac{\mathrm{4}\pi}{\mathrm{7}}=\frac{{bc}}{{a}} \\ $$$${cos}\frac{\mathrm{6}\pi}{\mathrm{7}}=\frac{{ac}}{{b}}\:\:\:\:\:\:\: \\ $$$${faind}\:\:\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} =? \\ $$ Answered by DvMc last…
Question Number 179650 by Linton last updated on 31/Oct/22 $${If}\:{x}\:{and}\:{y}\:{are}\:{positive} \\ $$$${integers}\:{and}\:\mathrm{2}{x}−\mathrm{4}{y}\:=\:\mathrm{3} \\ $$$${then}\:{find}\:\frac{\mathrm{16}^{{x}} }{\mathrm{256}^{{y}} } \\ $$ Commented by Rasheed.Sindhi last updated on 31/Oct/22…
Question Number 114110 by bemath last updated on 17/Sep/20 $$\frac{\mathrm{4}}{\mathrm{1}!}\:+\:\frac{\mathrm{11}}{\mathrm{2}!}\:+\:\frac{\mathrm{22}}{\mathrm{3}!}\:+\:\frac{\mathrm{37}}{\mathrm{4}!}\:+\:…\:=\:? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Sep/20 $${y}\:\:\bigtriangleup{y}\:\bigtriangleup^{\mathrm{2}} {y} \\ $$$$\mathrm{4} \\…